Vtracs for 6/49?

[jack]

Hello, pab, I need help on this, it pairs the two extremes of high and low vetrac the draw, then the limit from 01 to 08 is the lowest vtrac, and from 16 to 24 is the largest vtrac.
So are 8 x8 = 64 pairs, joining the lowest and highest vtrac a draw.
Example a draw vtrac the lowest is 07 and the other 4 18 largest vtrac will be between 08-17
Vtrac or 11 of 24, pab must see the use of this limit of 01-08 smaller and 16 to 24 or higher if you have to increase the limit, but I must give 90% within this limit, need to do,
After the 4 groups of 6 numbers of the groups has at least two vtrac always
But no one knows which group has done at 4 Issues = 6x2 = 15 x 4 = 60 pairs in vratc in 100% of any lot, or by 60 always has a couple pairs, only this pair is the pair of the ends. It is the pair rotating in 4 groups of 6 numbers,

 

[jack]

Hello, pab below the list of 60 pairs of vtrac, at least one of the pairs in this 100%
In any lottery =
Making the 4 groups of 6
So are closing 6 2 = 15 do we have in the other 3 groups,
15 + 15 +15 +15 = 60 pairs
Below is the list of 60 pairs of vtrac, attention of peers are not the extremes ok =
01 02
01 03
01 04
01 05
01 06
02 03
02 04
02 05
02 06
03 04
03 05
03 06
04 05
04 06
05 06
07 08
07 09
07 10
07 11
07 12
08 09
08 10
08 11
08 12
09 10
09 11
09 12
10 11
10 12
11 12
13 14
13 15
13 16
13 17
13 18
14 15
14 16
14 17
14 18
15 16
15 17
15 18
16 17
16 18
17 18
19 20
19 21
19 22
19 23
19 24
20 21
20 22
20 23
20 24
21 22
21 23
21 24
22 23
22 24
23 24
#

 

[PAB]

Hi Jack,

Hello, pab, I need help on this, it pairs the two extremes of high and low vetrac the draw, then the limit from 01 to 08 is the lowest vtrac, and from 16 to 24 is the largest vtrac.
So are 8 x 8 = 64 pairs, joining the lowest and highest vtrac a draw. Example a draw vtrac the lowest is 07 and the other 4 18 largest vtrac will be between 08-17

For numbers 01 to 08 there are 28 combinations of pairs for C(8,2).
For numbers 09 to 15 there are 21 combinations of pairs for C(7,2).
For numbers 16 to 24 there are 36 combinations of pairs for C(9,2).

Unfortunately, I do not understand what help you are asking me for?

Regards,
PAB


-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-
12:45, restate my assumptions.
Mathematics is the language of nature.
Everything around us can be represented and understood through numbers.
If you graph the numbers of any system, patterns emerge. Therefore, there are patterns everywhere in nature.

 

[jack]

Hello, pab no, no '!! is this calculation, so each number is 01-08 with conbina 16-24
* Are 64 conbinaçoes pairs in the 1st number in the pair is the group 01-08 and 2nd pair number is 16 to 24, forming pairs at both ends, after the fourth vtrac lacking bp puts the inside boundary of the pairs,
Pab, you can not combine 01-08, you must combine a number for each group
* For the group 01-08 are the smallest, and the group 16-24 are the largest, it is easy

 

[jack]

01-08 the limit can not take par because only one escohido number at a time, or is the group cobinado 16-24 form the pair

 

[PAB]

Hi Jack,

...is this calculation, so each number is 01-08 with conbina 16-24
* Are 64 conbinaçoes pairs in the 1st number in the pair is the group 01-08 and 2nd pair number is 16 to 24, forming pairs at both ends, after the fourth vtrac lacking bp puts the inside boundary of the pairs,
Pab, you can not combine 01-08, you must combine a number for each group
* For the group 01-08 are the smallest, and the group 16-24 are the largest, it is easy

Do you mean this:-

01-16
01-17
01-18
01-19
01-20
01-21
01-22
01-23
01-24
02-16
02-17
02-18
02-19
02-20
02-21
02-22
02-23
02-24
03-16
03-17
03-18
03-19
03-20
03-21
03-22
03-23
03-24
04-16
04-17
04-18
04-19
04-20
04-21
04-22
04-23
04-24
05-16
05-17
05-18
05-19
05-20
05-21
05-22
05-23
05-24
06-16
06-17
06-18
06-19
06-20
06-21
06-22
06-23
06-24
07-16
07-17
07-18
07-19
07-20
07-21
07-22
07-23
07-24
08-16
08-17
08-18
08-19
08-20
08-21
08-22
08-23
08-24

Making a total of 72 combinations?

Regards,
PAB


-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-
12:45, restate my assumptions.
Mathematics is the language of nature.
Everything around us can be represented and understood through numbers.
If you graph the numbers of any system, patterns emerge. Therefore, there are patterns everywhere in nature.

 

[PAB]

Hi Jack,

I wrote this Macro to check the figures:-

Option Explicit
Option Base 1

Const Min1 As Integer = 1
Const Max1 As Integer = 8
Const Min2 As Integer = 16
Const Max2 As Integer = 24

Sub Pair_2_Groups_PAB()
Dim Grp1 As Integer, Grp2 As Integer
Dim Count As Long
With Application
.ScreenUpdating = False: .Calculation = xlCalculationManual: .DisplayAlerts = False
End With
Range("A1").Select
Count = 0
For Grp1 = Min1 To Max1
For Grp2 = Min2 To Max2
Count = Count + 1
With Application.WorksheetFunction
ActiveCell.Offset(0, 0).Value = .Text(Grp1, "00")
ActiveCell.Offset(0, 1).Value = .Text(Grp2, "00")
ActiveCell.Offset(1, 0).Select
End With
Next Grp2
Next Grp1
Range("A1").Select
With Application
.DisplayAlerts = True: .Calculation = xlCalculationAutomatic: .ScreenUpdating = True
End With
End Sub

Regards,
PAB


-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-
12:45, restate my assumptions.
Mathematics is the language of nature.
Everything around us can be represented and understood through numbers.
If you graph the numbers of any system, patterns emerge. Therefore, there are patterns everywhere in nature.

 

[jack]

Hello, ok you're right!! 01-08 because of no 8 and 9 inclusive perfect here this error
Are correct then is 9x9 = 72. These are the pairs are of both ends of the lower vtrac (01 to 08) and the largest 16-24), we have 72 pairs of the ends or tips of the lower and higher
An example par 01xxx16 the xis are the other 4 vetrac
08xxx24
02xxxx17 ...
Pab and ice, these 72 pairs are the pairs that close a bet, the xxxx is the center court position 2nd 3rd 4th 5th, positions 1 and 6th are 72 pairs above
Pab, when referring to center court xxxx24 01 (xxxx) center court in a bid
Numca will start 01 and 02 or have mine with 23 24, atenaço note that I am speaking of the center court, the bet complete with 6 numbers ai can, to differentiate it,
So are 01.02 and 23.24 out, we have 20 closing by 4 = 4.845, = central block in 99% of pairings, but these blocks 4.845 applies filters delays, etc. warm. etc.. quatra central vtrac of course!!

 

[jack]

Hello, ice and pab, we see this model of peer end
* If the couple is not better vtrac 01.02, 01.25 and ice than did
For example look at, making vtrac, pairs of sequence 01,02,1 03,04 vtrac 2nd vtrac
* 05,06 3rd vtrac ...... until 48.49, so to use the couple seems to be better, but we need to test ok!!
Example of a raffle that gave = 05, xxxx37
In vtrac is par 03 xxxx 18, but we need to simulate various tests,

 

[jack]

Hello, ice, from 13 million in a lottery of 49/6, to center court
Declined from 13 million for 4845. course is center court, then have to convert and put the two ends (the pair ends) but is a great reduction, not to mention that at most three numbers until the center court or by past results, the court will only repeat cad drawings 2mil , or close to it, then one can study the center court and the couple of tips.

 

[PAB]

Hi Jack,

Hello, ok you're right!! 01-08 because of no 8 and 9 inclusive perfect here this error
Are correct then is 9x9 = 72. These are the pairs are of both ends of the lower vtrac (01 to 08) and the largest 16-24), we have 72 pairs of the ends or tips of the lower and higher
An example par 01xxx16 the xis are the other 4 vetrac
08xxx24
02xxxx17 ...
Pab and ice, these 72 pairs are the pairs that close a bet, the xxxx is the center court position 2nd 3rd 4th 5th, positions 1 and 6th are 72 pairs above
Pab, when referring to center court xxxx24 01 (xxxx) center court in a bid

Firstly, 9x9=81 so I think you have got your figures wrong somewhere. Do you mean C(8,1)*C(9,1)=72 combinations???

Numca will start 01 and 02 or have mine with 23 24, atenaço note that I am speaking of the center court, the bet complete with 6 numbers ai can, to differentiate it,
So are 01.02 and 23.24 out, we have 20 closing by 4 = 4.845, = central block in 99% of pairings, but these blocks 4.845 applies filters delays, etc. warm. etc.. quatra central vtrac of course!!

Secondly, your explanations are not very clear.
If you could use full example combinations to explain what you are talking about it will make it a lot clearer because we already know that numbers 1 to 8 and numbers 16 to 24 are the Lower & Upper limits.
One minute you are talking about the other four Vtrac numbers being between 9 and 15 but your examples don't show this.

we see this model of peer end
* If the couple is not better vtrac 01.02, 01.25 and ice than did
For example look at, making vtrac, pairs of sequence 01,02,1 03,04 vtrac 2nd vtrac
* 05,06 3rd vtrac ...... until 48.49, so to use the couple seems to be better, but we need to test ok!!
Example of a raffle that gave = 05, xxxx37
In vtrac is par 03 xxxx 18, but we need to simulate various tests

Is this something completely different to what you have tried to explain previously or not because there are numbers 48 & 49 in there which we are NOT using in our system???

...from 13 million in a lottery of 49/6, to center court
Declined from 13 million for 4845. course is center court, then have to convert and put the two ends (the pair ends) but is a great reduction, not to mention that at most three numbers until the center court or by past results, the court will only repeat cad drawings 2mil , or close to it, then one can study the center court and the couple of tips.

We are NOT dealing with 13,983,816 combinations because we are using a hybrid system of 24 numbers which equates to C(24,6)=134,596 combinations.
Where did you get the 4,845 from???

Regards,
PAB


-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-
12:45, restate my assumptions.
Mathematics is the language of nature.
Everything around us can be represented and understood through numbers.
If you graph the numbers of any system, patterns emerge. Therefore, there are patterns everywhere in nature.

 

[PAB]

Taking this one step further.

Using the Lower Limit Numbers From 1 To 8 and the Upper Limit Numbers From 16 to 24 and the Middle Numbers From 9 to 15 this equates to C(8,1)*C(9,1)*C(7,4)=2,520 Combinations.
This is a BIG reduction from the C(24,6)=134,596 Combinations.
I checked my figures with an updated Macro I posted earlier.

Regards,
PAB


-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-
12:45, restate my assumptions.
Mathematics is the language of nature.
Everything around us can be represented and understood through numbers.
If you graph the numbers of any system, patterns emerge. Therefore, there are patterns everywhere in nature.

 

[PAB]

Hi Jack,

Out of interest where are you from, is it Portugal???
Perhaps you could update your profile showing where you are from because it is always useful to know.
Thanks in advance.

Regards,
PAB


-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-
12:45, restate my assumptions.
Mathematics is the language of nature.
Everything around us can be represented and understood through numbers.
If you graph the numbers of any system, patterns emerge. Therefore, there are patterns everywhere in nature.

 

[jack]

Hello, I'm pab of Brazil, Rio Grande do Sul ok, careful translations of google, google exchange synonyms
And change the translations,
When 72 or 91, has not much difference, one can increase the threshold 01-9 or 10
and 14 to 24, this may change if increasing pairs of extremes, as the central block, x = x 12,15,18,19 the center court is 12,15,18,19, the example cited 09-15
is when the pair is 08 16 = xxxx then when par is 08 and 16, the court dara'dentro this limit, reducing, we need to make some simulations to see the recovery, it

 

[PAB]

Hi Jack,

I have never been to Brazil myself but friends of mine have and said how lovely it was and that they would go back.

Anyway,

...we need to make some simulations to see the recovery...

I think we will wait for Icewynd to catchup with this particular topic and see what his thoughts and opinions are before we proceed with this.
If it is something that is outside of this particular project we could setup a new thread for this and continue the discussion there.
Out of interest, what simulations were you thinking of???

Regards,
PAB


-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-∏-
12:45, restate my assumptions.
Mathematics is the language of nature.
Everything around us can be represented and understood through numbers.
If you graph the numbers of any system, patterns emerge. Therefore, there are patterns everywhere in nature.

 

[jack]

Hello, PAB, a correction!! because it was the center court, a center court numca will start with 01 or vtrac vtrac finished with 24, then the court will have 'the limit 02-23
Giving a total blocks = 7315, 100% accuracy in any lottery, but you can
Deminuir, taking 80% of it, using filters, such suits block sweepstakes past
Not playing, pab, in lottery mathematically can only get 60%, the rest is random, so let's focus on center court, then we'll see how good the pair put on both ends of the bet that is 6 numbers
These 7.315, always hits in 100% of any lot that will come in the future it covers,
From 02 to 23, because a block central numca will start with 01 and end with 24, so the central blocks ranging from 02 to 23 in 100% of the total draws = 7315
Let's try to hit the center court, and use all possible patterns and filters to reduce in value of 7.315.

 

[jack]

Hello pab, ice and soon you will win the grand prize, and will visit Brazil, the study of central blocks is not out of the ice project, just maybe is changing the composition of pairs of vtrac just that. But we need to see what is the best response to the sweepstakes ok
Pab and ice after a filter within the blocks and put the 4 running on a rotating formula, eliminating the blocks taking a group because the standard says that a group has zero or a number, as we did not know which group of 6 numbers, we make the elimination in 4 editions each issue taking a group,
So ice, you create reducing vtrac, and now we have another reduction, which are the central blocks. understands,

 

[jack]

Hello, icewynd, changes nothing about the project, is seen only by the reduction in the central blocks ie a reduction is within your project in central blocks we see the last digit of the pairs if vtrac repeat endings are possible 210
* Below the 210 terminations without repetition to filter 7.315 blocks
in 1234
in 1235
in 1236
in 1237
in 1238
in 1239
in 1230
in 1245
in 1246
in 1247
in 1248
in 1249
in 1240
in 1256
in 1257
in 1258
in 1259
in 1250
in 1267
in 1268
in 1269
in 1260
in 1278
in 1279
in 1270
in 1289
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in 1290
in 1345
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in 1347
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in 1340
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in 1389
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in 1390
in 1456
in 1457
in 1458
in 1459
in 1450
in 1467
in 1468
in 1469
in 1460
in 1478
in 1479
in 1470
in 1489
in 1480
in 1490
in 1567
in 1568
in 1569
in 1560
in 1578
in 1579
in 1570
in 1589
in 1580
in 1590
in 1678
in 1679
in 1670
in 1689
in 1680
in 1690
in 1789
in 1780
in 1790
in 1890
in 2345
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in 2348
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in 2670
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in 2680
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in 2789
in 2780
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in 2890
3456
3457
3458
3459
3450
3467
3468
3469
3460
3478
3479
3470
3489
3480
3490
3567
3568
3569
3560
3578
3579
3570
3589
3580
3590
3678
3679
3670
3689
3680
3690
3789
3780
3790
3890
4567
4568
4569
4560
4578
4579
4570
4589
4580
4590
4678
4679
4670
4689
4680
4690
4789
4780
4790
4890
5678
5679
5670
5689
5680
5690
5789
5780
5790
5890
6789
6780
6790
6890
7890

 

[Icewynd]

Hello, ice, from 13 million in a lottery of 49/6, to center court
Declined from 13 million for 4845. course is center court, then have to convert and put the two ends (the pair ends) but is a great reduction, not to mention that at most three numbers until the center court or by past results, the court will only repeat cad drawings 2mil , or close to it, then one can study the center court and the couple of tips.

Agreed! This is a great reduction in the odds.

I did some testing. I used the 64 combinations starting with 01-08 and ending with 17-24. These 64 combinations show up in 86% of the Vtrac drawns.

I also converted the Vtracs back to regular numbers, with the assumption that Vtracs 01-08 represent numbers 01-08 and Vtracs 17-24 represent numbers 42-49. These combinations appeared in 45% of the drawn numbers.

So, if we can come up with the correct combinations from the 4845 in the 'center court' we will have a winner.

 

[Icewynd]

I think this approach has some merit. As I stated in my previous post, we could cover 45% of the draws with the combinations 1,x,x,x,x,42 ...8,x,x,x,x,49 (with the conversion of the first Vtrac to ONLY the lower number of its pair and the conversion of the last Vtrac to ONLY the higher number of its pair (triple)).

We could also limit the construction of the four numbers in the center by using position limits, for example,
P2=Vtracs 03-14 90% of the time
P3=Vtracs 06-16 91% of the time
P4=Vtracs 08-20 90% of the time
P5=Vtracs 12-23 92% of the time.

I think PAB is right, this should probably be moved to another thread to avoid confusion.

Therefore, I will start a thread entitled "Using 6/49 Vtracs to make playable combinations"