Hi Jack,
Thanks for your input. I divided the Vtracs, as you suggested, into 4 groups of 6.
The results were as follows:
0 missing groups 42%
1 missing group 52%
2 missing groups 6%
For the situation where one group is missing, there were 3 patterns possible: 0-1-2-3 (0 from one group, 1 from another group, 2 from another group, 3 from the last group), 0-2-2-2, and 0-1-1-4. The distribution of these groups was:
0-1-2-3 65% of draws with one group missing
0-2-2-2 20%
0-1-1-4 15%
So, quite often (52% of the time) there is a situation where all the numbers are drawn from only 18 Vtracs, and about 2/3 of those cases have a pattern of 0-1-2-3. Very good!
I am not sure how you got your result here. Can you explain further?
Thanks for your input. I divided the Vtracs, as you suggested, into 4 groups of 6.
The results were as follows:
0 missing groups 42%
1 missing group 52%
2 missing groups 6%
For the situation where one group is missing, there were 3 patterns possible: 0-1-2-3 (0 from one group, 1 from another group, 2 from another group, 3 from the last group), 0-2-2-2, and 0-1-1-4. The distribution of these groups was:
0-1-2-3 65% of draws with one group missing
0-2-2-2 20%
0-1-1-4 15%
So, quite often (52% of the time) there is a situation where all the numbers are drawn from only 18 Vtracs, and about 2/3 of those cases have a pattern of 0-1-2-3. Very good!
jack said:01 02 03 04 05 06
07 08 09 10 11 12
13 14 15 16 17 18
19 20 21 22 23 24
Result vtrac= 01,08,14,20,21,24
I am not sure how you got your result here. Can you explain further?