A recent conversation with our friend Bloubul sparked an idea in my mind.
I have been spending a lot of time on the Pick 3 game lately, and they use a system called Vtracs to reduce the 10 digits down to 5 for easier analysis. The advantage is that if you can eliminate one of the vtracs, you can eliminate 2 of the real numbers.
Vtracs are calculated such that 0 represents 0 and 5, 1 represents 1 and 6, etc. up to 4 which represents 4 and 9. (Some use different methods of calculation, but the concept is always the same).
We could come up with a similar system for 6/49, perhaps using a factor of 25. So 1 would represent 1 and 26, 2=2 & 27, 3=3&28....up to 24=24 & 49. This would leave the 25 unused, it could stand alone or lump it with the 1 (i.e. 1+25=26), or add it in with the 24, 25, 49.
Anyway, I'll probably do up a quick spreadsheet to see if there are any advantages to this idea.
Any comments?
I have been spending a lot of time on the Pick 3 game lately, and they use a system called Vtracs to reduce the 10 digits down to 5 for easier analysis. The advantage is that if you can eliminate one of the vtracs, you can eliminate 2 of the real numbers.
Vtracs are calculated such that 0 represents 0 and 5, 1 represents 1 and 6, etc. up to 4 which represents 4 and 9. (Some use different methods of calculation, but the concept is always the same).
We could come up with a similar system for 6/49, perhaps using a factor of 25. So 1 would represent 1 and 26, 2=2 & 27, 3=3&28....up to 24=24 & 49. This would leave the 25 unused, it could stand alone or lump it with the 1 (i.e. 1+25=26), or add it in with the 24, 25, 49.
Anyway, I'll probably do up a quick spreadsheet to see if there are any advantages to this idea.
Any comments?