black prince
Member
Hi HalfBee
This is Skip1 in Winnalotto, also refered to as #20. The above #20 < 6, says
if skip1 is less than 6 select. My filter has the following:
#20 < 6
and
#21 > 5
and
#22 > 5
and
#23 > 5
and
#24 > 5
This says if skip1 (#20) is less than 6 and skip2 (#21) is greater than 5 and
so on. The example above is a pattern and I refer to it as 65555. Where 6
is always less and 5 is always greater. The pattern 55555 is very rare, so
when a number has this pattern I eliminate it. A number that has a skip
pattern like 0,3,1,4,0 is 66666 or all skips less than 6. A number that has
a skip pattern like 20,17,9,11,8 is 55555 or greater than 5. I adjust the
pattern numbers by observing the skip patterns of winning draws. I'm
creating a program that will automate which patterns occur the least for
elimination. I'm presently using 12 skip patterns. Checking which occur
the least manually is time consuming. A program will solve this problem.
-BP
Originally Posted by HalfBee
Can you elaborate a little more on this? It sounds interesting...
I'm not sure what your #20 < 6 is pointing to (column 20 < 6 such as a filter?)
This is Skip1 in Winnalotto, also refered to as #20. The above #20 < 6, says
if skip1 is less than 6 select. My filter has the following:
#20 < 6
and
#21 > 5
and
#22 > 5
and
#23 > 5
and
#24 > 5
This says if skip1 (#20) is less than 6 and skip2 (#21) is greater than 5 and
so on. The example above is a pattern and I refer to it as 65555. Where 6
is always less and 5 is always greater. The pattern 55555 is very rare, so
when a number has this pattern I eliminate it. A number that has a skip
pattern like 0,3,1,4,0 is 66666 or all skips less than 6. A number that has
a skip pattern like 20,17,9,11,8 is 55555 or greater than 5. I adjust the
pattern numbers by observing the skip patterns of winning draws. I'm
creating a program that will automate which patterns occur the least for
elimination. I'm presently using 12 skip patterns. Checking which occur
the least manually is time consuming. A program will solve this problem.
-BP