Number selection method for Pick5 and Pick6 lotteries

[GameBelgium]

Good job Kenya649. See how different your results are, compared to the results I generated earlier. It all depends on what 7 lines you select. Your lines:
13 14 23 38 41 42
11 13 14 23 38 42
11 19 14 23 38 42
14 19 23 38 41 42

My lines:
01 03 05 13 20 29
01 03 05 19 20 29
03 05 13 20 24 29
03 05 19 20 24 29

We only have number 19 in common. I'll post the results tomorrow night.

 

[GameBelgium]

Hey GameBelgium

I can construct a similar table for your lottery, if it's usufull to you.
if you want that just send my all your past lottery results in an excel spreedsheet.

El_patron
Reply With Quote

Hi Patron, that would be most helpful and useful. You can download the results from this link:

http://www.lotto.be/NL/Spelen_en_Winnen/Trekkingsspelen/Lotto/Results/DownloadResults.aspx

Can you use the results from 01.1990 until 03.2011?

 

[Frank]

And as a control here are my 12 using the repeat statistic, but not that method.

2,8,11,12,19,20,28,29,35,39,41,42.

NB. for any random 12 selections in a 6/42 draw on average, 1.7 balls should match by chance alone.

 

[Frank]

Good job Kenya649. See how different your results are, compared to the results I generated earlier. It all depends on what 7 lines you select. Your lines:
13 14 23 38 41 42
11 13 14 23 38 42
11 19 14 23 38 42
14 19 23 38 41 42

My lines:
01 03 05 13 20 29
01 03 05 19 20 29
03 05 13 20 24 29
03 05 19 20 24 29

We only have number 19 in common. I'll post the results tomorrow night.

So thats 11,13,14,19,23,38,41,42 ( 8 selections)

and 1,3,5,13,19,20,24,29, ( 8 selections)

By chance you would expect 1.14 balls to match on average for a pool of 8 random balls.

 

[Kenya649]

And as a control here are my 12 using the repeat statistic, but not that method.

2,8,11,12,19,20,28,29,35,39,41,42.

NB. for any random 12 selections in a 6/42 draw on average, 1.7 balls should match by chance alone.

Frank,

It is wise you share your method as we are here to evaluate different methods and who knows

 

[patron]

GameBelgium

I've finished the analysis. post an email to send you the spreedsheet.
Good job Frank
What is your method?

El-Patron

 

[Frank]

Frank,

It is wise you share your method as we are here to evaluate different methods and who knows

It is quite complex and needs a computer to extract the information, but is as I mentioned, based on skips and whether a particular skip is likely to continue to have a repeat number or not in the next draw. However this control does not use past lotto results, it uses random numbers. Since in my early posts I did say that the statistic was true for any result be it a past one, a random one or any 6/42 line written on a piece of paper

I can give you a breakdown of the all steps involved, but you'd really need to be able to programme it as otherwise its very laborious.

 

[GameBelgium]

GameBelgium

I've finished the analysis. post an email to send you the spreedsheet.
Good job Frank
What is your method?

El-Patron

Not sure I can mention an e-mail address here, but I'll try (leave out the spaces):
g e r t _ 2 0 0 3 AT h o t m a i l DOT c o m

Thanks again for the input guys, I appreciate it!

 

[madam]

GameBelgium: You could try "OLG.ca" and address a sweet young thng called Jennifer with your request of the dates you require or as in my case she sent me an attachment of 26 pages of it all up to 11/03/09. Myzelf I am not sure how I could transport the dates yu requested. There is also, in my mind a discrepancy in the ways I interpret you 0 no wing and win lines. I assume that when the lower line has a similar number in the upper line that it is a win line. Similarly if there is no number between the lower and upper lines then the lower line become a 0 line. Somehow I do not see this happening in the latest presentations of say the 16th.
madam

 

[GameBelgium]

Here are the results of last night's drawing:
02 03 08 12 27 38

Analysis time! Where did we go wrong in choosing our numbers?

First of all:

Let's stick to 7 lines for a start.

Only 5 lines had 0 winning numbers instead of 7.

No repeating numbers mate...

We assumed there would be not repaeting numbers, when there were in fact two repeating numbers.

Here's the situation we started from:

08/01/2011 03 07 14 15 33 34
12/01/2011 09 10 13 24 38 42
15/01/2011 03 06 17 27 32 37
19/01/2011 17 22 28 32 33 40 (0)
22/01/2011 16 17 18 30 34 35 (0)
26/01/2011 02 03 17 30 33 36
29/01/2011 07 17 28 29 40 42
02/02/2011 05 07 17 18 33 38
05/02/2011 06 15 16 18 20 28
09/02/2011 02 04 08 21 23 37 (0)
12/02/2011 02 06 15 18 20 30
16/02/2011 08 21 25 29 33 34
19/02/2011 04 21 22 27 35 40 (0)
23/02/2011 04 07 12 28 38 42 (0)
26/02/2011 01 02 24 25 41 42
02/03/2011 02 06 13 19 27 31
05/03/2011 02 03 05 09 16 40
09/03/2011 07 15 18 22 25 31 (0)
12/03/2011 03 08 12 15 25 42
16/03/2011 02 06 11 22 27 41 (0)

So we chose lines:

so we have:
4, 5, 10, 13, 14, 18, 20

cool. this ok for you?

Whereas we should have chosen:
4, 5, 7, 9, 18

And this would have been the correct setup:

08/01/2011 03 07 14 15 33 34
12/01/2011 09 10 13 24 38 42
15/01/2011 03 06 17 27 32 37
19/01/2011 17 22 28 32 33 40 (0)
22/01/2011 16 17 18 30 34 35 (0)
26/01/2011 02 03 17 30 33 36
29/01/2011 07 17 28 29 40 42 (0)
02/02/2011 05 07 17 18 33 38
05/02/2011 06 15 16 18 20 28 (0)
09/02/2011 02 04 08 21 23 37
12/02/2011 02 06 15 18 20 30
16/02/2011 08 21 25 29 33 34
19/02/2011 04 21 22 27 35 40
23/02/2011 04 07 12 28 38 42
26/02/2011 01 02 24 25 41 42
02/03/2011 02 06 13 19 27 31
05/03/2011 02 03 05 09 16 40
09/03/2011 07 15 18 22 25 31 (0)
12/03/2011 03 08 12 15 25 42
16/03/2011 02 06 11 22 27 41

Just in case you're wondering: starting from this correct set of 5 lines with 0 winners, only the number 2 can be determined as a guaranteed winner.

 

[GameBelgium]

And as a control here are my 12 using the repeat statistic, but not that method.

2,8,11,12,19,20,28,29,35,39,41,42.

NB. for any random 12 selections in a 6/42 draw on average, 1.7 balls should match by chance alone.
Reply With Quote

Frank, you had 3 correct numbers within your selection of 12, which is above the statistic probability

 

[stefan]

Frank, you had 3 correct numbers within your selection of 12, which is above the statistic probability

Hi GameBelgium,

When you look at the table published on my website it is NOT above any statistical probability:
http://www.lottotrix.com/lottery-predictions-lotto-642.html

Exactly 3 correct numbers within a selection of 12 from 42 comes up in 17% of the draws (roughly once every 6 draws) ...

0 numbers: 11.31909%
1 number : 32.59897%
2 numbers: 34.47968%
3 numbers: 17.02700%
4 numbers: 04.10472%
5 numbers: 00.45293%
6 numbers: 00.01761%

A statistical probability isn't accurately measured over a course of 10 or 20 draws either. Short-term statistical analysis and big jackpot games simply don't coincide. If you fail to make the switch from statistics to combinatorics, probabilities can only be accurately measured over a course of millions of draws.


We can all be easily fooled by randomness and draw the wrong conclusions. The data from the mentioned table is a correct conclusion.

Hope this helps!

Stefan

 

[Frank]

Quite right and one prediction doesn't prove a system. The figure of 1.7 balls was an average over dozens of draws. Sometimes there would be no matches, sometimes there would be quite a few matches. This time my numbers were just lucky, no more to it than that. You have to be consistently higher than 1.7 in 12 selections over scores of draws to prove anything. I thought that went without saying.

 

[madam]

GameBelgium: Here are 22 latest #'s of the ON49 lottery
11/01/05 02 08 16 18 37 47 30
11/01/08 19 20 21 24 29 35 38
11/01/12 07 09 22 27 38 44 25
11/01/15 05 13 19 32 44 45 23
11/01/19 03 16 17 19 21 29 41
11/01/22 04 06 08 16 18 43 29
11/01/26 04 08 13 29 39 40 17
11/01/29 29 30 34 43 45 46 23
11/02/02 13 21 28 29 32 33 39
11/02/05 13 14 16 24 28 37 35
11/02/09 06 08 14 17 26 42 18
11/02/12 09 10 11 12 31 39 41
11/02/16 01 31 34 36 37 43 02
11/02/19 07 10 18 26 32 39 35
11/02/23 06 08 12 23 43 46 20
11/03/02 03 18 22 25 29 41 05
11/03/05 09 14 25 30 35 48 31
11/03/09 01 03 34 35 36 48 44
11/03/12 03 22 23 38 40 48 30
11/03/16 06 07 26 34 44 49 16
11/03/19 01 18 23 38 39 49 08

The lottery is 6 balls and a bonus. It is run on alternate Wed. and Sat. At this time there are only 1406 games listed. Somehow I get the thoughts that there is some guessing going on instead of a set of more or less rules to follow? Regardless, we would appreciate your assistance in showing us your method, if possible, with the latest ON49 aabove #'s.

 

[GameBelgium]

Madam, for a 6/49 lottery, I would pick 9 lines with 0 winners.

Somehow I get the thoughts that there is some guessing going on

Wherever did you get that idea from? ;-)

The guessing part is choosing the 9 lines with 0 winners correctly. Once you've done that, you can follow a set of rules to determine the possible combinations.

 

[GameBelgium]

Hi GameBelgium,

When you look at the table published on my website it is NOT above any statistical probability:
http://www.lottotrix.com/lottery-predictions-lotto-642.html

Exactly 3 correct numbers within a selection of 12 from 42 comes up in 17% of the draws (roughly once every 6 draws) ...

0 numbers: 11.31909%
1 number : 32.59897%
2 numbers: 34.47968%
3 numbers: 17.02700%
4 numbers: 04.10472%
5 numbers: 00.45293%
6 numbers: 00.01761%

A statistical probability isn't accurately measured over a course of 10 or 20 draws either. Short-term statistical analysis and big jackpot games simply don't coincide. If you fail to make the switch from statistics to combinatorics, probabilities can only be accurately measured over a course of millions of draws.


We can all be easily fooled by randomness and draw the wrong conclusions. The data from the mentioned table is a correct conclusion.

Hope this helps!

Stefan

Hi Stefan

Glad to see the big guns stopped by to take a look at this thread. I actually did use your table for my statement, as most of the times, for any group of 12 randomnly chosen numbers you will have guessed 1 or 2 numbers correctly. Which is why I said that 3 is above the statistic probability.

Thanks for your input Stefan, and I'm looking forward to the release of your next project

 

[Kenya649]

I can give you a breakdown of the all steps involved, but you'd really need to be able to programme it as otherwise its very laborious.

Please give us a breakdown and maybe we can write a macro for you

 

[Frank]

I don't need a macro, I've been running spreadsheet macros (in conjunction with spreadsheet formulas) to do this for years. I just said You'd need to program it to use it. I don't If this site will let me post images I'll go through the stages when I get the time.

 

[Frank]

I can't post images. It will be impossible to explain my method without reference to screenshots. Its too complicated.

 

[stefan]

Hi Frank,
With a maximum file size of "1 Bytes", I don't see how anyone can post image attachments here? Pity!

Hi GameBelgium,
I appreciate the kind words, but I don't see myself this way. I think we all share the same obsession. Good thread!