Hello, ram, this filter is important, so the goal of the project is to hit the suitIn each position, to become pivot, to rotate with 20 positions possibleThis filter is only the last digit (0 to 9) example suit = 12.24 57 = last digit = 2, 4.7The type of the front is not covered, because the range is 0 to 6 shortThen it enters the filter, will be out,The filter only the endings ok =is of vertical terminaçoescaption =digitsO = oddE = pairsL = low (0, 1, 2, 3.4)H = high (5, 6, 7, 8.9)1, 7, 2, 3.4 = LHLLL 00EOE1, 3, 4, 8.2 = LLLHL 00EEE5, 6, 2, 4.9 = HHLLH OEEEO7, 2, 3, 4.2 = HLLLL OEOEEwith the table to see patterns to play, diagonally left rightexample deum of 20 suits = 12.24 57 = last digit = 7 = 2, 4, EL, EL, OHAnother example, 32 = 01 = .15 last digit = 1, 2 = 5, OL, OH, ELas with other of 20 positions do vertically, you already have dismembered, with this you can see patterns on the diagonal and vertical estatiticas of each position,
digit
- Thread starter jack
- Start date
Hello, these formations are 60 two-digit and two digits of the front ends
In the case of senna have sweet 60 groups, a lotto 49/6 is taking 55 type etc 45.55
Because the front digit goes to 0-4, then the list of ram 60, the three frequencies do
Hot and cold media, making the analysis of such delays result within 60 see
What is in arrears, gave example = 4 4 3 3, then the numbers would be = 42 45 13 53, this would be one of the groups, the analysis is good not to play with 60grupos (all)
In the case of senna have sweet 60 groups, a lotto 49/6 is taking 55 type etc 45.55
Because the front digit goes to 0-4, then the list of ram 60, the three frequencies do
Hot and cold media, making the analysis of such delays result within 60 see
What is in arrears, gave example = 4 4 3 3, then the numbers would be = 42 45 13 53, this would be one of the groups, the analysis is good not to play with 60grupos (all)
00 00
00 11
00 22
00 33
00 44
00 55
00 66
00 77
00 88
00 99
11 00
11 11
11 22
11 33
11 44
11 55
11 66
11 77
11 88
11 99
22 00
22 11
22 22
22 33
22 44
22 55
22 66
22 77
22 88
22 99
33 00
33 11
33 22
33 33
33 44
33 55
33 66
33 77
33 88
33 99
44 00
44 11
44 22
44 33
44 44
44 55
44 66
44 77
44 88
44 99
55 00
55 11
55 22
55 33
55 44
55 55
55 66
55 77
55 88
55 99
00 11
00 22
00 33
00 44
00 55
00 66
00 77
00 88
00 99
11 00
11 11
11 22
11 33
11 44
11 55
11 66
11 77
11 88
11 99
22 00
22 11
22 22
22 33
22 44
22 55
22 66
22 77
22 88
22 99
33 00
33 11
33 22
33 33
33 44
33 55
33 66
33 77
33 88
33 99
44 00
44 11
44 22
44 33
44 44
44 55
44 66
44 77
44 88
44 99
55 00
55 11
55 22
55 33
55 44
55 55
55 66
55 77
55 88
55 99
Hello Jack,
Statistics for last digit says that mean is equal to 4 and Standard Dev: 2.4-- So we can found between 2-6 (or 7) three or four numbers of the comb will be in with these digits and most cases. We can get positional patterns using this tecnique to see if they cluster to get the best distribution for last digits.
Ramrock
Statistics for last digit says that mean is equal to 4 and Standard Dev: 2.4-- So we can found between 2-6 (or 7) three or four numbers of the comb will be in with these digits and most cases. We can get positional patterns using this tecnique to see if they cluster to get the best distribution for last digits.
Ramrock
Hello Ram, very good trabaho! Suits and dismembered by 20 digits separated by (first and last digit) seems to be easier to predict, that of an industry cluster, is fanstastico, AAS jumps median, vertical view of each position, is very good, the lottery in the standards we follow them, then we repetitions and not repeat, because the repetition of an event is the secret of probability, this part when divided into 4 groups you understand?
Hello Ram, very good job! Suits and dismembered by 20 digits separated by (first and last digit) seems to be easier to predict, that of an industry cluster, is fantastic, the median jumps AAS, seen in the vertical position of each is very good, the lottery in the standards we follow them, then we repetitions and not repeat, because the repetition of an event is the secret of probability, this part when divided into 4 groups you understand?
Hello, the ram endings or last digit of each of the tender 20, then
We have 64 x20 = 1208 = 80% always hits just the ends of the pair of suits only
0 0 2
0 0 4
0 0 6
0 0 8
0 2 0
0 2 2
0 2 4
6 0 2
0 2 8
0 4 0
0 4 2
0 4 4
0 4 6
0 4 8
0 6 0
0 6 2
0 6 4
0 6 6
6 0 8
0 8 0
0 8 2
0 8 4
0 8 6
0 8 8
2 0 2
2 2 2
2 2 4
2 2 6
2 2 8
2 4 2
2 4 4
2 4 6
2 4 8
2 6 2
2 6 4
2 6 6
2 6 8
2 8 2
2 8 4
2 8 6
2 8 8
4 0 4
4 2 4
4 4 4
4 4 6
4 4 8
4 6 4
4 6 6
4 6 8
4 8 4
4 8 6
4 8 8
6 0 6
6 2 6
6 4 6
6 6 6
6 6 8
6 8 6
6 8 8
8 8 0
8 2 8
8 4 8
8 6 8
8 8 8
We have 64 x20 = 1208 = 80% always hits just the ends of the pair of suits only
0 0 2
0 0 4
0 0 6
0 0 8
0 2 0
0 2 2
0 2 4
6 0 2
0 2 8
0 4 0
0 4 2
0 4 4
0 4 6
0 4 8
0 6 0
0 6 2
0 6 4
0 6 6
6 0 8
0 8 0
0 8 2
0 8 4
0 8 6
0 8 8
2 0 2
2 2 2
2 2 4
2 2 6
2 2 8
2 4 2
2 4 4
2 4 6
2 4 8
2 6 2
2 6 4
2 6 6
2 6 8
2 8 2
2 8 4
2 8 6
2 8 8
4 0 4
4 2 4
4 4 4
4 4 6
4 4 8
4 6 4
4 6 6
4 6 8
4 8 4
4 8 6
4 8 8
6 0 6
6 2 6
6 4 6
6 6 6
6 6 8
6 8 6
6 8 8
8 8 0
8 2 8
8 4 8
8 6 8
8 8 8
Hello, the Rams have 20 positions of first and last digit, suits, aim is to settle a suit to become pivotal in addition to the many ways you can use the trunk positions are two positions of the stem 20 positions positions are = 1, 5,6 and 2,3,4 because they occupy the center of the 20 positions are the two positions = trunk, is the reference or pivot is so othe way to see the pivot, as the trunk of 6 numbers so you can use 12 xxxx 57, outnumbered more then 57 and 12 within the block, but split into three positions sãoposiçoes 123, 124, 134, 234 the 20 positions 123 124 125 126 134 135 136 145 146 156 234 235 236 245 246 256 345 346 356 456
Hello, ram, did you notice that the positions trunk (core) of the 20 positions There is a repeating position = 1,5,6 = 2,3,4 can be used as pivot, then we have to see how many references, a good pair of two ends and another way to see the forecast The union of the 1st and 6th position forming the pair with the smallest number to largest number Then a second amount of 01-20 number 6 and 40-60 have 400 pairs The other four in number dao, the pair enter the 4 number 18 45 is missing this entity 19-44 within the two limits, within these four numbers can be broken down into four positions
Hello, ram, they look fantastic example of these two results Test = 09 26 34 43 53 54 The 1st number is 09 and the 6th number is = 54 = at par 09 54 (even the union of the child with the greatest number) there is no repetition of the four digits, no repetition of four digits, and together form the tender without repetition of digit we get the number 26 in the 2nd position Another example test = 03 05 20 21 38 56 = track 03 56 (21) the number 21 4 th position, then ram the 400 pairs can be filtered by peers in delays, because it is the 4 digit different, and the third number number is spinning in 4 positions of the center court. What can not repeat The digits form when the suit, 03,56,21, that the analysis of table columns, it is very important because it gives us to see the delays by column vertically, and also give other filters, a mirror for the pair of ends
Hello Jack,
i have been busy with other software projects. I am looking back your posts to see if is missing something, i can't filter out the amount of combs that I want but in some cases i am getting some goods results 5 out of 6 and with good frecuency 4 out of 6 testing the right lotto-link..in the real bet we need to select around 20 lotto-link that conform the 64% of cases in the whole lotto file. I think that it is a good approach anyway.
I can't understand this Cycle, how did you get it? What <01> =1 means?
Thanks!! Ramrock.
i have been busy with other software projects. I am looking back your posts to see if is missing something, i can't filter out the amount of combs that I want but in some cases i am getting some goods results 5 out of 6 and with good frecuency 4 out of 6 testing the right lotto-link..in the real bet we need to select around 20 lotto-link that conform the 64% of cases in the whole lotto file. I think that it is a good approach anyway.
I can't understand this Cycle, how did you get it? What <01> =1 means?
jack said:
Thanks!! Ramrock.
just i am kidding!! Hello, ram, the cycle of mega easy example is taken from statistics of sweet senna, It's easy, it begins with the first result of the tender, and will give up until all 60 numbers (of course in the case of senna sweet) when you give all 60 numbers at least once It is considered a closed loop, dpois begins another cycle, then within each cycle up to 60 numbers, we have numbers that come out more, cold and mean, after about 1000 Results, it has been able to have about 20 cycles and one can see that groups of numbers in the 1st cycle They left in a position of the cycle, the next cycle, do not repeat the same example In the 1st cycle, the numbers came out there at the end of the cycle, and the next two at the beginning of the cycle, to see the positions of the cycle is to see the list, and other statistics, Ram on the pivot, you can also use the last result, the last result the numbers will be deleted, but the digits forward and not separate endings, then ram, is in play can be mathematically go up to 60-70%
Hello, study of the cycle, it starts with 1 result, ok will give up to 60 numbers After starting either cycle, eg in the 1st cycle out at least once in 41 draws, the drawing 42 starts new cycle up to 60 numbers, and thus to the end of the list of so rteios ram can remove numbers by the cycle example in the last cycle, 10 in the list is the starting position, then look for the past 11 cycles in numbers that have 11, and not play until about 25 numbers, has several estatisticasde medium, hot cold, etc., etc. , Within each closed loop, which could not used to remove the cycle numbers Of course mathematically, you can get up to 88% is already very good, eliminating per cycle
Hello, ram this is important in the early post we have the first digit and last digit and in separate suits, The first digit of the total 000 to 556 (case of 60/6) of 49/6 is less Because it has 5.6 So, Ram, both the list of first and last digit is very important to see the cycle also Have the full amount (17) and separate digit (a) and (7) And yet we have only the first digit pairs 000-444 or just odd 111-555 The last digit is also only the even and odd, then we have two lists with even and odd Together and apart, the ends of each suit only the odd andor peers, works well And we still have ups and downs and mirror.
Hello Ram, this is so for the last digit 0-9 or inside the suits of the last digit See if the position has mennos UMSA sequential example = 1,2,3 Look at the test 14,32,33,40,42 = 51 = last digit = 4,2,3,0,2,1 = 1,2,3 we have the sequence It does not matter ordemo this example the sequence of three digits 1,2,3 is the position 2nd, 3rd, and 6th = 2,3,1, no matter the position, but the sequence of 1,2,3, see how many threads Are possible 0-9 and their statistical, 1,2,3 5,6,7 ... etc. results is that the pair It is sequential, one can crial a sequential filter all together even and odd pairs and sequential single sequence x = 0,2,4 only odd, 1,3,5, all together (even and odd) 1,2,3 3,4,5 etc. The position may be the biggest in the 1st place!! says you understand?