digit

[jack]

Ram missed the 456

 

[jack]

Hello, ram, this idea is split into 3 groups the last digit from 0 to 9IE = 0,2,4 1,3 ,5. The third mixed pairs and groups = odd, 6 7, 8.9Then it got three groups = odd and mixed pairs = A=0, 2, 4 B= 1,3, 5 C= 6, 7, 8,9 Example: the suit of the first position the last digit of the last draw was = 5, 6.2Next do not play in Group b the type 5 and so with the digit 2, 6, andAnother example the digit 2 gave the ultimate result in Group A in the next did not play in the GroupA, then do so with 19 positions in each vertical position of the suit in the last digitRAM, we now have the mirror, we have the adjacent, and the three groups, to filter the last digit in each suit vertical position

 

[jack]

Hello Ram, you play 49/6? can put the last three results in the post? thank you

 

[RAMROCK]

Hello Jack,

I have been working on the magic mirror, i am testing now. here you go my results (6/54):

last draw# 05,16,24,32,48,49
previous draw# 03,17,18,22,46,54
draw# 25,26,40,43,46,51

Regards!

 

[jack]

Hello, ram look in three tests, have at least one suit of the last digit Only pairs = 1 = 6,2,6 2nd = 8,2,6 3 result = 6,0,6 That is at least one suit digits only three pairs in the standard drawings You only have the list of pairs and also just odd, Then ram on this list and only pairs of odd, do all three frequencies, hot media and cold

 

[jack]

hello ram in your lottery divided into 4 groups Figures 1 and 2 = 13 and 3 = 13 numbers each group and 0 ° 15 = 54 numbers, always in a group will have 100% zero or a number mimima condition and the other two numbers, one group can have up to 6 numbers, but what counts as standard is the condition mimima two numbers, then we do in four editions, or 4 groups, because we do not know, which group, or filter mirror, can give indications a group number or zero, also noted that the results had three sequences 17.18 25.26 47.48

 

[jack]

Hello, ram besides the pair in a row, instance = 17, 18, ​​also we always have a pair With the distances between pairs = 1,2,3 = example In the test = 25,26,40,43,46,51 = have heels or deltas = 1,14,3,3,5 Starting from the number based on the first and last number in the lottery 54/6 can have values For delta between the numbers, but also has ram can only suit the delta Terminaçaoes of example 1 suit = 25,26,40 = delta = 1.14 or 20 suit = 43,46,51 = delta = 3.5 So do all the ram Standing on a graph of possible deltas suits, and make the three frequencies

 

[jack]

hello ram, assign zero to pair and one for odd
must look for the vertical position, each limb
64 lines of 20 positions each, it is the perfect matrix =
64 possible positions of the Odd Couple, but with numbers already 6 with 6 positions
Even / Odd - # comb. -% - # Times -%
000,000 to 134.596 - 0.96% - 20 - 0.81%
000,001 to 177.100 - 27.1% - 28 - 1.13%
000,010 to 177.100 - 27.1% - 36 - 1.46%
000,011 to 177.100 - 27.1% - 29 - 1.17%
000,100 to 177.100 - 27.1% - 34 - 1.38%
000,101 to 230.230 - 1.65% - 39 - 1.58%
000,110 to 177.100 - 27.1% - 30 - 1.22%
000,111 to 177.100 - 27.1% - 42 - 1.70%
001,000 to 177.100 - 27.1% - 39 - 1.58%
001,001 to 230.230 - 1.65% - 42 - 1.70%
001,010 to 230.230 - 1.65% - 34 - 1.38%
001,011 to 230.230 - 1.65% - 39 - 1.58%
001,100 to 177.100 - 27.1% - 31 - 1.26%
001,101 to 230.230 - 1.65% - 38 - 1.54%
001,110 to 177.100 - 27.1% - 25 - 1.01%
001,111 to 177.100 - 27.1% - 37 - 1.50%
010,000 to 177.100 - 27.1% - 27 - 1.09%
010,001 to 230.230 - 1.65% - 43 - 1.74%
010,010 to 230.230 - 1.65% - 38 - 1.54%
010,011 to 230.230 - 1.65% - 30 - 1.22%
010,100 to 230.230 - 1.65% - 47 - 1.90%
010,101 to 296.010 - 2.12% - 41 - 1.66%
010,110 to 230.230 - 1.65% - 37 - 1.50%
010,111 to 230.230 - 1.65% - 43 - 1.74%
011,000 to 177.100 - 27.1% - 25 - 1.01%
011,001 to 230.230 - 1.65% - 51 - 2.07%
011,010 to 230.230 - 1.65% - 35 - 1.42%
011,011 to 230.230 - 1.65% - 45 - 1.82%
011,100 to 177.100 - 27.1% - 28 - 1.13%
011,101 to 230.230 - 1.65% - 38 - 1.54%
011,110 to 177.100 - 27.1% - 29 - 1.17%
011,111 to 177.100 - 27.1% - 40 - 1.62%
100,000 to 177.100 - 27.1% - 23 - 0.93%
100,001 to 230.230 - 1.65% - 54 - 2.19%
100,010 to 230.230 - 1.65% - 45 - 1.82%
100,011 to 230.230 - 1.65% - 41 - 1.66%
100,100 to 230.230 - 1.65% - 34 - 1.38%
100,101 to 296.010 - 2.12% - 63 - 2.55%
100,110 to 230.230 - 1.65% - 38 - 1.54%
100,111 to 230.230 - 1.65% - 47 - 1.90%
101,000 to 230.230 - 1.65% - 37 - 1.50%
101,001 to 296.010 - 2.12% - 42 - 1.70%
101,010 to 296.010 - 2.12% - 46 - 1.86%
101,011 to 296.010 - 2.12% - 59 - 2.39%
101,100 to 230.230 - 1.65% - 38 - 1.54%
101,101 to 296.010 - 2.12% - 60 - 2.43%
101,110 to 230.230 - 1.65% - 26 - 1.05%
101,111 to 230.230 - 1.65% - 45 - 1.82%
110,000 to 177.100 - 27.1% - 24 - 0.97%
110,001 to 230.230 - 1.65% - 49 - 1.98%
110,010 to 230.230 - 1.65% - 42 - 1.70%
110,011 to 230.230 - 1.65% - 45 - 1.82%
110,100 to 230.230 - 1.65% - 51 - 2.07%
110,101 to 296.010 - 2.12% - 50 - 2.03%
110,110 to 230.230 - 1.65% - 32 - 1.30%
110,111 to 230.230 - 1.65% - 39 - 1.58%
111,000 to 177.100 - 27.1% - 39 - 1.58%
111,001 to 230.230 - 1.65% - 37 - 1.50%
111,010 to 230.230 - 1.65% - 49 - 1.98%
111,011 to 230.230 - 1.65% - 45 - 1.82%
111,100 to 177.100 - 27.1% - 28 - 1.13%
111,101 to 230.230 - 1.65% - 40 - 1.62%
111,110 to 177.100 - 27.1% - 37 - 1.50%
111,111 to 177.100 - 27.1% - 24 - 0.97%

 

[jack]

hello ram addition of the mirror, each of the tender 20, you can use like a pick3 each of the 20 suits in their positions vertically ok.Count of hits for each unique group. Example: Code: N Current draw: 3 7 0 a draw-n: 0 9 1 n-2 draw: a first 7 No draw-3: 3 0 8 In this example unique6 group (0,1,3,7,8,9) has a hit. hit6 will count 1. then you can catch the last 3 resulatados the last digit like a pick3 vertical position of each, and each choose a

 

[jack]

Hello, ram just, a pattern that is happening in the last digits (0-9)
Example = the sum of the last digit (0-9) LOW, MEDIUM AND HIGH,
And digit range, 10 draws a low sum, will happen and a range
0 to 6 or digit digit 4-9, one could create three kinds of ranges of the last digit
And seeing every 10 draws, its use, then you can play up to 10 lottery
With a lower sum digit 0-6 intrevalo hi another, the last digit,

 

[jack]

Hello, ram also this pattern in your LotteryResult05, 16, 24, 32, 48.4903, 17, 18, 22, 46.5425, 26, 40, 43, 46.51Ram when using this table0, 1, 2, 3, 4, 5, 6 7, 8.9Low highBy a suit last digit group handle high = 5, 6.9The other suit takes the Group down, this is very good, along with mirror filter

 

[jack]

Hello, ram, look at this curious fact.
12 These groups always have a pair,
267
348
159
157
168
249
147
258
369
123
456
789
Ram temos12 groups always hits a pair, for non-repetition within groups
This is to find the pair.

 

[jack]

hello, ram is only one link, to see if you have any informatin probalidades and statistics that can help us in the program can be to find some tool http://www.wolfram.com/mathematica

 

[RAMROCK]

Hello Jack,

It looks like a good software for research. by the way...I am so confused with this part: 000,000 (binary pattern) i can't understand how you get it.

Even / Odd - # comb. -% - # Times -%
000,000 to 134.596 - 0.96% - 20 - 0.81%
000,001 to 177.100 - 27.1% - 28 - 1.13%
000,010 to 177.100 - 27.1% - 36 - 1.46%
000,011 to 177.100 - 27.1% - 29 - 1.17%
000,100 to 177.100 - 27.1% - 34 - 1.38%

Ramrock!!

 

[jack]

Hello, ram is easy, you have to assign a zero for odd and for the couple, can be the opposite So the result, you put down, the six positions of each results We will leave after the breakup of the 20 positions then this result Last digit = 13,15,17,27,29,49 = 3,5,7,7,9,9
0,0,0,0,0,0 another example Last digit = 12,23,24,26,36,49 = 2,3,4,6,6,9 1 1 1 0 1 0 The above matrix is perfect, made ​​a list of draws where showed the highest output Example = 101101 has a good probability of exit Well then you can break up this array of 64 groups In positions 20 to 123 = 4,5,6 1 0 1 1 1 0 They are only the last digit, the whole (the six figures) and dismembered in 20 positions Example you can create this array of betting with 64 combinations, the highest percentage, for example The matrix = 101 101 In 1st position then we have par-ten pairs to the 1st position, and so with the other positions

 

[jack]

Ram is easy, zero for par or odd and the one for the pair or oddAnd convert, the zero and one can be even or odd time to assignThen just convert, where 0 numeros pairs or imparesconforme wasStipulated and type (1) one for odd or pairs as estabecidoSince a perfect array, will hit always, note only the last digit

 

[RAMROCK]

Ram is easy, zero for par or odd and the one for the pair or oddAnd convert, the zero and one can be even or odd time to assignThen just convert, where 0 numeros pairs or imparesconforme wasStipulated and type (1) one for odd or pairs as estabecidoSince a perfect array, will hit always, note only the last digit

Hello jack,

got it!!

it is a detail filter for odd/even. ok let me check it out!!

Ramrock!!

 

[jack]

Hello, perfect, ram, that table, groups of 64 is perfect, you must convert to is where
Zero, even (or odd) where is (1) an odd or even, in the sweepstakes, then see the use (percentages) of each group of 64, can break up into 20 positions
Example = in the dismemberment of the twenty positions, one position
Position = Is = 2,3,6
1 0 1
So if a = is odd = odd to see the last digit to represent where he has (1)
A = 1,3,5,7,9 where it has zero par = 0,2,4,6,8,
It's kind of reduction to last digit and does not need to play every table of 64 groups

 

[jack]

Hello, ram and convert into even and odd, you can convert the table of the 64 groups So = Low = 0,1,2,3,4 High = 5,6,7,8,9 Even = 0,2,4,6,8 Odd = 1,3,5,7,9 IN = 3,4,5,6,7 OUT = 0,1,2,8,9 So besides the even and odd, we have low, high, and in and out You can make a filter with the three conditions together? look at the example last digit = 5,6,9 = 5 where the event is high, and is in the 6 = even, high, in, and the digit 9 is odd high = out, then each digit has three conditions, make a table vertically to see the three patterns together, and see if there are three repetitions of the patterns of the last draw for the next then each digit receives three filter conditions. do in each of 20 positions

 

[jack]

Hello, ram, mirror on the filter, attention is to delete the digit mirror Example = if the last digit in the 1st position gave 1 (a) look at the table and not play the six (6) And so with other digits, the digit equivalent of the table, is to delete, and tends to be in the position, as an example, the digit may not be in 1st position, but may be in 2nd position, either in whole (the six positions together) or dismembered in 20 suits