digit

[jack]

Hello, ram, this is important, so is ok example of a lottery 54/6 or similar
Divide into four groups
pp = 02.04 ...
i.i = 15,17,39,,,
p.i = 4,5,27
i.p = 1,8,34 .....
where pp = means the pair is first and last digit is even
i.i mean = odd and odd
p.i = even and odd
i.p = odd and even,
ok, instance = draw = 12,15,24,35,46,52
we look down, the position of each number, the number of the last 12 draw
ip = is not next draw is not playing in this group, playing in the other three groups
and so with the other five numbers, then filtered groups, in this example, the filter
is the whole number, the first digit and last digit together = 12, the maximum repeating a raffle to another is one or two groups, say you understand?

 

[jack]

corretor
p.p= 02,24
i.i= 15,17
p.i= 45 27
i.p=18,34

 

[jack]

Hello, so do not forget, we are in search of patterns, beyond the pivot, the last digit, suits
Example, a lottery 53/6 or similar, where the divide in 4 groups, can shuffle as you please, whenever a group has zero or a number, and another two or more, this pattern is 100% so if you play two numbers where the one or zero misses you, if you play in the group where the two numbers you will play a miss, but it is not known which group we do in 4 editions taking a group, the union of 3 groups always have numbers 5-6 another pattern are polindromos, 01.10 02,20,15,51
23.32, ........ and hard to leave them together or 32, or 23 numca the two together
This is important when the last digit will join with first digit, ok.quanto repeating numbers earlier results, using a lottery as pivot, repeated in different positions, eg, if you choose a number in the pivot position 3rd position noa next sweepstakes avoid this position, ram see another pattern in cad separate group
The average hot and cold, but each group separately, because a number delayed by
All is not even a sector or group, first patterns after the filters,
That, of IPPP ip. Ii, in Portuguese, is the last to see next, just repeat the two groups, so we are taking group, in the last instance
Gave 12 = is = ip next should not play this group is so with other with other 5 numbers,

 

[jack]

Hello, ram you saw that you can use, in suits each of the 20 positions of the last digit
You can use the vertical position at the vtrac or any other system, one of the 20 cad of heading No
Separately, like a pick3. In 1st position you can take the vertical table. Until 10 or 20 raffles
And use vtrac or othe form of reduction, you can use the vertical deltas in the system to predict pairs, any
One of the positions can be analyzed after the pivot or reference, the Rams vtrac good you can do in the horizontal
Picking up the 20 positions and crossing with each of the 20 positions in the vertical, so the break up is very good
Ram is going to build the code? thank you

 

[jack]

Hello, ran, you can see the sum of the delays of the last digit of suits,
example
4,5,9 = one of 20 suits last digit
= 1,2,5 are the delays and == 7 is the sum of delays Suit study
The first digit do not need,
It make the sum of the delays of each suit the last digit at each of 20 positions

 

[jack]

Hello, ramrock, you are having doubts of how to code?
* You know desmebrado in 20 positions, one can also
* Using methods like a pick 3 in each position,
* Especially the last digit 0-9, (final digits)
You're able to do?

 

[jack]

Hello, ramrock, you are working in the program? we will only take the top post! thank you

 

[jack]

Hello, ramrock, you are working in the program code? Only use what is needed of post ok! thank you

 

[jack]

Hello, ram, you can add this, an example of a 6/49 lottery, predict the
Smaller and larger pairs and trios, ok
Smaller pairs example from 01 to 22 = limit we have 231 peers and 1,540 trios
At 28 to 49 = we have 231 peers and 1,450 trios, these are larger pairs
Goal is to see the pairs of the two ends, of course, lack the Central pair,
After combined the two pairs that are 4 numbers, they the 4 numbers can give indications of the central pair, type the naumca pair that came out with the two pairs of ends,
Etc.. to filter the pairs and trios will use the filters you created now, so now we have a base, which is to provide for major and minor pairs, ok, like this going solft? Thanks ramcock

 

[jack]

Hello, ramrock, you are working in code? The study of dios pairs end of 49/6, it is also a good study, the couple from the Centre or from the 3rd and 4th position, is for another study
Then a filter use the last digit of two pairs of the extremes of a bet
Example = 12, 15, 26, 35, 45.49
Couple minor = 12.15 higher pair = 45.49 pair Center = 26.35
The pair, while 26.35 Centre does not enter the study
Separate the last digit of 2, 5, pairs = 5.9
To aplaicar our mirror system, and others so far seen and to anticipate the endings or last digit

 

[jack]

hello.ramrock!!

 

[jack]

Hello, ramrock, glad you came back to look at this example initial and final digit
Initial digits of 49/6 = 0,1,2,3,4 initial digits
Agoral the last digit high = 5,6,7,8,9, usually a 49/6 we have two digits in this
High group last digit = 5,6,7,8,9
Example 466 = 20,24,40,43,48,45 sweepstakes in the last digit given high 5.8 (two digits)
The other initial and end to complete the number given within 0,1,2,3,4
20,24,40,43, then we have 4 numbers within 0,1,2,3,4, two high = 5.8
In total the draw = 466 had six digits (adding the digits start and end)
So we have to see how many numbers of the combination should be at 0,1,2,3,4, with two of the
High 5,6,7,8,9, uam to give good reduction and see the ups 5,6,7,8,9, arrears ok.
Or filters, not to cross 0,1,2,3,4 all this with only two other group 5,6,7,8,9
(Sometimes this group of 3 digits high).

 

[jack]

Hello, below the array with the numbers of the 25 digit combination of initial and final
0,1,2,3,4
0 0
0 1
0 2
0 3
0 4
1 0
1 1
1 2
1 3
1 4
2 0
2 1
2 2
2 3
2 4
3 0
3 1
3 2
3 3
3 4
4 0
4 1
4 2
4 3
4 4
Sometimes a sweepstakes of two consecutive sample = 12.13 or 33.34, here needs filters, not to play with the numbers 25, two or three clear lack of high 5,6,7,8,9
But we have a good base reduction

 

[RAMROCK]

Hi jack

thank you for tips and suggestions. I owe you something, now all software related with lotto is on stand by.

Ramrock.

 

[jack]

Hello, ramrock, thanks for replying the post, ok, just to see what will actually benefit
For the use of solft, since the study of the digit appears to be a good filter with patience
Let's create a good design, ok thank you