Using a pool a numbers from recent draws for the next one!
- Thread starter thornc
- Start date
Dennis Bassboss
Member
Nothing is new here I once saw a site where this was debated...but I can't find it anymore.... 
Dennis Bassboss
Member
But what is new for many...not for me...is when you criss-cross the announcers with it.. 
Dennis Bassboss
Member
I don't know if it somebody has the expected values for numbers hitting from the last 4 draws and the same thing from the last 6 draws?
That would be very funny to see.... 
That would be very funny to see....
Dennis Bassboss
Member
If I recall I think that Goswinus once posted such datas...But I'm not sure if it was him or a friend of mine at school...
Dennis Bassboss
Member
Since the beginning with bonus the Canadian 6/49 has for repeaters a values of 1,00749625187406 repeat on back to back draw...by looking at 4 draws back that value would definitely increase a lot....
Dennis Bassboss
Member
Got to go now....be back later... 
Dennis Bassboss said:Since the beginning with bonus the Canadian 6/49 has for repeaters a values of 1,00749625187406 repeat on back to back draw...by looking at 4 draws back that value would definitely increase a lot....
So you mean that there's close to 1 repeats from draw to draw??
By other word, 1 of the numbers in a present draw was present in the previous draw!
Ok, I think I understand I'll try to look into calculating for 4/5 draws!!!
I was confused by the comma Beaker, my first impression was 1*10^15 repeats??? So I had to confirm...Beaker said:Repeaters from the last draw of course - this shouldn't be a surprise to anyone who has followed this site
I think that in the full history my lotto isn't so generous, I'll check it as soon as I get home!! I'm working late...Check it for your lotto thornc
You and Dennis, are really tuned to each other...
Dennis Bassboss
Member
This is the actual value or average for the PT 6/49 lottery concerning repeaters from the previous draw... counting the last 998 draws...
1,03510531594784
1,03510531594784
Nick Koutras
Member
Repeats after N draws in a 6/49 Game.
Repeats after N draws in a 6/49 Game.
The probability of 0 repeats on the next draw is:
6c0*43c6/49c6=1*6,096,454/13,983816= 0.43596
So the probability for 1 or more repeats is 1-.43596= 0.56404
But this is not of easy use by a regular player,
because we can have 1,2,3,4,5 or 6 repeats probable!
To built a Binomial Distribution upper and lower limits
will be very complicated to understand.
Below is a table of the average number of repeats after N draws, the easy way.
DRAW Avg. Repeats
0 0
1 6*6/49=0.735
2 12*6/49=1.469
3 18*6/49=2.204
4 24*6/49=2.939
5 30*6/49=3.673
6 36*6/49=4.408
7 42*6/49=5.143
8 48*6/49=5.878
Repeats after N draws in a 6/49 Game.
The probability of 0 repeats on the next draw is:
6c0*43c6/49c6=1*6,096,454/13,983816= 0.43596
So the probability for 1 or more repeats is 1-.43596= 0.56404
But this is not of easy use by a regular player,
because we can have 1,2,3,4,5 or 6 repeats probable!
To built a Binomial Distribution upper and lower limits
will be very complicated to understand.
Below is a table of the average number of repeats after N draws, the easy way.
DRAW Avg. Repeats
0 0
1 6*6/49=0.735
2 12*6/49=1.469
3 18*6/49=2.204
4 24*6/49=2.939
5 30*6/49=3.673
6 36*6/49=4.408
7 42*6/49=5.143
8 48*6/49=5.878
Repeat after N draws
I do not know if we measure the same thing but using the Lotto 6/49 (2002 draws), I get the following results:
1 draw: 0.746 repeats
2 draws: 1.484 repeats
3 draws: 2.233 repeats
4 draws: 2.960 repeats
5 draws: 3.713 repeats
6 draws: 4.462 repeats
7 draws: 5.199 repeats
8 draws: 5.921 repeats
Results are fairly near your own results but always slightly higher; differences range from 0.011 to 0.056. Maybe it is because I include multiple repeats in my calculations.
By the way, Nick K. you must be the same guy that put out the Probability Calculator. I found that on the web quite a few years ago but I still use it on a fairly regular basis.
I do not know if we measure the same thing but using the Lotto 6/49 (2002 draws), I get the following results:
1 draw: 0.746 repeats
2 draws: 1.484 repeats
3 draws: 2.233 repeats
4 draws: 2.960 repeats
5 draws: 3.713 repeats
6 draws: 4.462 repeats
7 draws: 5.199 repeats
8 draws: 5.921 repeats
Results are fairly near your own results but always slightly higher; differences range from 0.011 to 0.056. Maybe it is because I include multiple repeats in my calculations.
By the way, Nick K. you must be the same guy that put out the Probability Calculator. I found that on the web quite a few years ago but I still use it on a fairly regular basis.
Very interesting...
Thanks Nick and Gilles,
What about looking at medians instead of averages??
And Nick your calculations are nice, but most of the times you get less numbers than then 6*NoDraws and you still get godd results... I think it all depends on the moment...
Hence the idea of finding a good trigger to play...
Thanks Nick and Gilles,
What about looking at medians instead of averages??
And Nick your calculations are nice, but most of the times you get less numbers than then 6*NoDraws and you still get godd results... I think it all depends on the moment...
Hence the idea of finding a good trigger to play...
Brad said:Strange but true ... I cut my teeth so to speak on a very similar strategy a number of years back, using BC49 of course.
Used N=4, with and without bonus, subbing for and without numbers that repeated within N=4, etc. Have results going back to draw one ... maybe it's time to dust off the old spread sheet and feed it into WH somehow
I like the direction of this thread, keep it coming thornc and all
Brad,
you can see hits of last 4 draws at www.sorte.no.sapo.pt.
It shows results in UK National Lottery and Totoloto (Portugal), with inclusion of Bonus number and without Bonus number.
Till now, you can conclude that this strategy don't win everytime. May be your tests can be made in a good scenario.
Hot
Brad
Member
Thanks Hot4,
interesting results, at first glance they're very similar to mine. I'll take a closer look when I have time.
I saw a site many moons ago that used the same approach, and used 'trigger draws' (my term, they called it something diff). Looking at what happened say 50,100,200 ... etc. draws ago, one could supposedly find a cycle and thus predict when to apply the system ... haven't found one for BC49, yet. I lost the link to that site ...
interesting results, at first glance they're very similar to mine. I'll take a closer look when I have time.
I saw a site many moons ago that used the same approach, and used 'trigger draws' (my term, they called it something diff). Looking at what happened say 50,100,200 ... etc. draws ago, one could supposedly find a cycle and thus predict when to apply the system ... haven't found one for BC49, yet. I lost the link to that site ...
thornc said:
Olá Thornc,
Yes, I'm from Portugal and my intention is to update results of last 4 draws from time to time. (Sim vivo em Portugal e o meu objectivo é actualizar os resultados dos últimos 4 sorteios de tempos a tempos.)
I think in next update better conclusions will come , so that we can use last 4 draws numbers when they seem good. (Penso que proximamente as conclusões serão melhores para que se possa utilizar os números quentes dos últimos 4 sorteios, da melhor maneira.)
Although I signed here as HOT, from now on I'll sign
Frank