The ISOLATOR (REVISED)

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Riccardo

Member
:confused: Hi to all from Riccardo,
I am very interested to know the practice of this fantastic method of bet to 49's. Me however I have not understood the operational formality of the method because I don't know very well the language English. Then I ask, with a lot of courtesy, to someone of you to explain to me with examples detailed of schemes. Thanks.:beer:
 
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Springbok

Member
Buenos Dias Riccardo

Listen nicely. Get a pencil and some paper and write the following down. It is called a grid:-

1,2,3,4,5,6,7
11,12,13,14,15,16,17
21,22,23,24,25,26,27
31,32,33,34,35,36,37
41,42,43,44,45,46,47

Go to blue square and go to 49s. Go to the top of the list. Cross off the numbers as they appear in the results. When you have two numbers left on one line which are uncrossed then you bet on them to a maximum of 4 draws. You will have to increase your bet after each draw. Normally one of the 2 numbers should hit within 4 draws.
 
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lottojay

Member
guys how much do you stake on each number? can anybody show me how yr profits grow each win please? its £1 a go right? and you win £6 a right number?
i understand the game but are unsure on wot amount to bet????

many thanks....
 
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Springbok

Member
Use the internet. You can bet 10p a numbers. The betting is over 4 draws. Betting is done on 2 numbers for the 4 draws. Start like this:-
10p 10p
20p 20p
40p 40p
80p 80p
You will make money if a number hits in any draw. Paper test first and see how you go.
 
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lottojay

Member
springbok thankyou very much for yr help and replie..:)

i will give it a go, i have already wrote it down and tested it abit and yes it works,and would be very profitable if one of yr numbers came out on the very next draw (1st bet) but it seems this isnt always the case and by the time you get a number say on the 3rd draw it evens its self out and you havnt really won anything:confused:

i didnt think you could put 10p on? i thought it was a minimum of £1 a go? i must be missing something here...

thanks for yr help..:clap:
 
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chilibill

Member
5/36 Lotto Isolator?

Springbok or Fullhouse or ?, .
How would I draw up an Isolator grid for my 5/36 game?

Or my 6/53 Lotto Game?

chilibill
 
bloubul

bloubul

Member
Hi chilibill
I'm sorry to inform you that Springbok will never frequent this BB again. He passed away some time ago. Thus it is up tho Fullhouse to help you if he / she wants to do so.

BlouBul :cool:
 
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Icewynd

Member
I would try a 5x5 matrix to start with, to make it roughly proportionate to the 7x7 matrix for 6/49 games. I don't think it really matters which numbers you leave out. Test it back aways to see how it works.

Good luck!
 
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chilibill

Member
Icewynd and BlouBul.

Thanks for the replies. I had lots of pleasure reading Springboks intelligent comments and will miss his advice. Early in the Isolator Revised thread, I believe Fullhouse said to randomize the 49 numbers for the 6/49 game, then
form the 7 x 5 grid with them , leaving out 14 numbers. Then later I saw grids with the lines in numerical order?? Also, which 14 numbers to leave out and why.
Fullhouse got some amazing results in 2006 which I would to to duplicate with my 5/36 game , primarily to get good key numbers to wheel.
Maybe Fullhouse will return with a new revision.
.chilibill
 
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chilibill

Member
Blitzed: Isolator grid for a 5/36 game ?

Blitzed,
I read your comments in the old 2006 Isolator (revised) thread. You seem to understand the strategy, as you planned to use it in your California game. Can you please explain in simple terms, how I would construct a grid for my 5/36 game? All the grids in the thread were for the 6/49 game , and had 35 numbers in them, discarding 14. Icewynd suggested I use a 5x5 matrix, but then which numbers to discard?
I hope you can point me in the right direction.
chilibill
 
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Icewynd

Member
Chillibill,

I don't think it really matters which numbers are discarded. The Isolator strategy for 6/49 discards the zero, 8 and 9 endings (e.g. 10, 18, 19), but there are some posts by Springbok (I belive) that use different numbers.

It makes sense to drop the zeros, since there is no zero ending in the first line. Maybe you could do something like:

01,02,03,04,05
11,12,13,14,15
21,22,23,24,25
31,32,33,34,35
​
Then go back into your lotto history and simulate using the matrix with your draws, marking off the numbers as they are drawn. When all but 2 in a line are drawn I play the two remaining for two draws. I do this for each line instead of for the whole matrix as described in the Islolator thread, as it produces more numbers to play. You will get a hit about half the time, and about once every 10 times both will be drawn.

Good luck with this. I think it is a good way to identify some numbers that are ready to pop. :thumb:
 
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Icewynd

Member
Good thought, Lotto_Cat. I had never thought of using it that way. Worth checking out.

I use another of Fullhouse's methods called side-by-side pairs for Keno. I'll do a post on it over on the Keno board.
 
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lotto_cat

Member
For Keno, instead of doing 5 decades (1-10, 11-19, 20-29, 30-39, 40-49), you would be doing 7 decades instead (1-10, 11-19, 20-29, 30-39, 40-49, 50-59, 60-69).

Is there a way to back test this perhapsÉ
 
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Icewynd

Member
Yes, I think grouping by 7s would make the play faster and generate more numbers for play. Besides, you're probably already tracking decades, so this would give a different look at the numbers.

Unfortunately, I can't think of any way to backtest this, other than going draw by draw to mark off the numbers as they are played. I suppose that visually scanning a skip history, if you maintain such a record, would show where and when the hits were coming after setting a start date for each Isolator.

I may play around with this if I get some time.
 
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