digit

[jack]

Hello, ok perfect, can test with calm, good mirror of the last result
example is that excluding the digit 9 you take the whole column of 9 = 09 19 29 39 49 59
and thus to other digits, and filing the corresponding columns, you can add ram
and testing your ideas too, ok the mean and the jumps are factors to see!

 

[jack]

Hello ram denotes a repetition of a number block from a past draws, regardless of the position. means that at least one number is not a repetition of the block constituting the past two ties (or 12 numbers, not necessarily only). This number is a repeat, however, the last three drawings (ie, 18 numbers, not necessarily original). The median is a very important parameter. Median. That means that at least 50% of cases, a number of repeated using the last draw refers to two numbers repeat; refers to repeated three numbers, etc., the medians are respectively 2, 4, 6, 9 18. This means that at least 50% of cases: TWO repeated numbers from 3 LAST CALL, THREE repeated numbers from the last five DRAWINGS; FOUR repeated numbers from 7 LAST CALL, ram, you can enhance the suits in relçao , the median vove can see the repetition of the 17-20 draw, the mega

 

[RAMROCK]

Sure Jack, the Lotto Links and statistics can generate the good ones, but the last digit is a powerfull filter, the best of this is to get the jackpot in a hundred of combs with a low cost. The work of both can lead us to the jackpot.

Hello, ok perfect, can test with calm, good mirror of the last result
example is that excluding the digit 9 you take the whole column of 9 = 09 19 29 39 49 59
and thus to other digits, and filing the corresponding columns, you can add ram
and testing your ideas too, ok the mean and the jumps are factors to see!

Thanks.
Ramrock.

 

[jack]

Hello, ram, noting that the the mirror is positional filter, which eliminated the column heading a second may not be in the fourth, but the fourth is the limit of numbers, one of the tables Position is important, over time, we teach an algorithm to predict these patterns Need a link, to filter up to three numbers for previous draws, the mirror is positional, the suit pivot will also be good to create wheels, it will be fixed, ram the use of 75% to 100% already this far in the polls. How will you use the median, because on average it takes about 60 numbers each draw out All, some numbers have a long cycle is another short cycle! you showed some analizes suit last digit, but it has to do vertical positions of 20 ok, because we have 20 chances to settle a bet, thank you

 

[jack]

Hello, here is an example of the cycle, the mega sena, giving up all the numbers 60 cycles It closed in 46 to draw up the final numbers, just to show the mismatch ((absences) To close the loop, and then get another to get the other has to give the 60 numbers In the case of senna sweet, the goal is to see the cycle of each digit
001) 04 05 30 33 41 52 -> 01 - 04 05 30 33 41 52 .
(002) 09 37 39 41 43 49 -> 02 - 09 37 39 43 49 ....<01>=1
(003) 10 11 29 30 36 47 -> 03 - 10 11 29 36 47 ....<01>=1
(004) 01 05 06 27 42 59 -> 04 - 01 06 27 42 59 ....<01>=1
(005) 01 02 06 16 19 46 -> 05 - 02 16 19 46 .......<04>=2
(006) 07 13 19 22 40 47 -> 06 - 07 13 22 40 .......<03>=1 <05>=1
(007) 03 05 20 21 38 56 -> 07 - 03 20 21 38 56 ....<01>=1
(008) 04 17 37 38 47 53 -> 08 - 17 53 .............<01>=1 <02>=1 <03>=1
(009) 08 43 54 55 56 60 -> 09 - 08 54 55 60 .......<02>=1
(010) 04 18 21 25 38 57 -> 10 - 18 25 57 ..........<01>=1
(011) 15 25 37 38 58 59 -> 11 - 15 58 .............<02>=1 <04>=1
(012) 04 16 19 20 27 43 -> 12 - ...................<01>=1 <02>=1 <04>=1 <05>=2
(013) 18 32 47 50 54 56 -> 13 - 32 50 .............<03>=1
(014) 02 16 23 27 47 53 -> 14 - 23 ................<03>=1 <04>=1 <05>=2
(015) 12 33 35 51 52 60 -> 15 - 12 35 51 ..........<01>=2
(016) 20 32 34 49 58 60 -> 16 - 34 ................<02>=1
(017) 06 10 13 19 20 51 -> 17 - ...................<03>=1 <04>=1 <05>=1 <06>=1
(018) 23 27 36 37 42 56 -> 18 - ...................<02>=1 <03>=1 <04>=2
(019) 05 10 12 24 25 60 -> 19 - 24 ................<01>=1 <03>=1
(020) 11 25 28 30 33 51 -> 20 - 28 ................<01>=2 <03>=1
(021) 06 33 36 46 49 53 -> 21 - ...................<01>=1 <02>=1 <03>=1 <04>=1 <05>=1
(022) 01 09 31 38 46 56 -> 22 - 31 ................<02>=1 <04>=1 <05>=1
(023) 17 37 39 51 52 59 -> 23 - ...................<01>=1 <02>=2 <04>=1
(024) 01 08 14 28 33 43 -> 24 - 14 ................<01>=1 <02>=1 <04>=1
(025) 24 43 50 54 55 56 -> 25 - ...................<02>=1
(026) 10 22 50 53 57 58 -> 26 - ...................<03>=1 <06>=1
(027) 13 17 20 33 44 51 -> 27 - 44 ................<01>=1 <06>=1
(028) 03 06 22 24 54 60 -> 28 - ...................<04>=1 <06>=1
(029) 03 08 14 43 56 58 -> 29 - ...................<02>=1
(030) 07 14 15 29 38 50 -> 30 - ...................<03>=1 <06>=1
(031) 17 19 28 45 48 56 -> 31 - 45 48 .............<05>=1
(032) 05 14 33 36 43 44 -> 32 - ...................<01>=2 <02>=1 <03>=1
(033) 05 17 33 39 42 49 -> 33 - ...................<01>=2 <02>=2 <04>=1
(034) 13 15 17 40 53 57 -> 34 - ...................<06>=2
(035) 04 16 21 23 54 57 -> 35 - ...................<01>=1 <05>=1
(036) 03 13 17 25 29 51 -> 36 - ...................<03>=1 <06>=1
(037) 06 07 22 38 52 60 -> 37 - ...................<01>=1 <04>=1 <06>=2
(038) 10 42 43 45 54 55 -> 38 - ...................<02>=1 <03>=1 <04>=1
(039) 12 16 37 45 52 56 -> 39 - ...................<01>=1 <02>=1 <05>=1
(040) 03 05 08 12 46 47 -> 40 - ...................<01>=1 <03>=1 <05>=1
(041) 12 26 35 38 39 47 -> 41 - 26 ................<02>=1 <03>=1
numeros: 1=>6 2=>5 3=>5 4=>5 5=>4 6=>4 7=>5 8=>2 9=>4 10=>3 11=>2 13=>2 14=>1 15=>3 16=>1 19=>1 20=>1 22=>1 24=>1 27=>1 31=>2 41=>1
Media..: 1=>00,59 2=>00,46 3=>00,39 4=>00,39 5=>00,29 6=>00,24

 

[jack]

we should take into account where we want to cut a given set of numbers ... Filter Ace Terminations of Sums ranging from (0-64). Ex: a termination: 1-11-21-31-41-51 6 = sum termination 2: 2-12-22-32-42-52 sum = 12 terminating 3: sum 3-13-23-33-43-53 = 18 terminating 4: = sum 4-14-24-34-44-54 24 5 Termination: 5-15-25-35-45-55 = sum 30 terminating 6: sum 6-16-26-36-46-56 = 36 terminating 7: = sum 7-17-27-37-47-57 42 termination 8: 8-18-28-38-48-48 58soma termination 9: 9-19-29-39-49-64 59soma terminating 0: 10-20-30-40-50-60 = sum Zero (0) We can then conclude that the sum of the endings of any key draw, will be included between 0 and 64. many keys are output with the same amount, and the sums are among the most 0:42. ram, only adds the endings (last digit) digit of the front does not enter the sum ok

 

[jack]

Hello, ram the above example of the sums of endings, it has to suit each separate
And at each position ok example
12,32,45 sum = 9
... and so with the other 19 positions. The above example was made ​​by the whole
The result of six numbers, you have to make the sum of each suit endings ok

 

[jack]

1-1-1-1-1-1 - 444 - 21:49% - 21.65%
2-1-1-1-1-0 - 1031 - 49.90% - 50.56%
2-2-1-1-0-0 - 407 - 20.70% - 20.82%
2-2-2-0-0-0 - 15 - 0.73% - 0.76%
3-1-1-1-0-0 - 122 - 5.91% - 6.61%
3-2-1-0-0-0 - 42 - 2.03% - 2.27%
3-3-0-0-0-0 - 1 - 0.05% - 0.03%
4-1-1-0-0-0 - 4 - 0.19% - 0.28%
4-2-0-0-0-0 - 0 - 0.00% - 0.03%
5-1-0-0-0-0 - 0 - 0.00% - 0.00%
Hello, ram sena's sweet, ne note here that good to use the double
Of digits = 0.0 to 9.9, and the last pair of scarcely two repeats focusing numbers in a column, we see affixing

 

[jack]

Hello Ram incredible, the above example are the 10 columns, but also occurs in 6 lines
(If sweet senna) has 70% or (0 0) (1 1) (2 2) (3 3) (4 4) (5 5)
Example 03.06 22 24 54 60
So join the Rams have to face the two digit (first digit) lines and the last digit of the 10 columns also by two, thus the suit, may be pivotal or not
are then dl dl of the first and last digit, 10 x 5 = 50
You can give out the suit, taking advantage of this pattern
crossing with other filters of the sums of the digits of each suit positional

 

[jack]

Hello, ram, this is very important, these pairs are the combination The digit and the front end of digits that is the right are the ends And the pairs of digits are facing the front, this is important when divided into 4 in the case of lottery groups, one group has to stay out in the group but not walk this Or two digits and last digit from the front, you can create this statistical list of 60 pairs This list is composed in front with the first digits from 00 to 55 (6 lnhas) 10 and the last digit of 00 and 99 (10 columns), these pairs are used to be fixed, ok
00 00
00 11
00 22
00 33
00 44
00 55
00 66
00 77
00 88
00 99
11 00
11 11
11 22
11 33
11 44
11 55
11 66
11 77
11 88
11 99
22 00
22 11
22 22
22 33
22 44
22 55
22 66
22 77
22 88
22 99
33 00
33 11
33 22
33 33
33 44
33 55
33 66
33 77
33 88
33 99
44 00
44 11
44 22
44 33
44 44
44 55
44 66
44 77
44 88
44 99
55 00
55 11
55 22
55 33
55 44
55 55
55 66
55 77
55 88
55 99

 

[jack]

01 02 03 04 05 06 07 08 09 10
11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30
31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50
51 52 53 54 55 56 57 58 59 60
Draws 36 = 03 13 17 25 29 51
O 4º grupo excluir

 

[jack]

Hello missed mark the number 13, this list of 60 pairs are double termination
The right terminations 0-9 digits and the left front saoduplas
In the matrix, of a sweet group of 15 number is out, this filter is important
So the choice of the pair of first and last digit, which has pro jeta group number 15 is out

 

[RAMROCK]

Hello Jack,

You are going so fast, let me digest all these parts and I'll be back with you soon, I have been out almost a week.
Ramrock.

 

[jack]

hello, ram and other forum members, beware of Translations of google, google, exchange words and synonyms
but what counts is the idea generates, the ram is quite understand the contents, a translator is not yet perfect, but we are doing well in the project, thanks

 

[RAMROCK]

Hi Jack,

I have been tested the mirror filter and i found that 54% of last digit numbers are quite different (6 numbers) and 32% of cases 5 numbers of the mirror are different. With the filter from Min>=5 and Max<=6 we can get the 86% from the draws file.Then the filtered combs will come with the right last digits.

Ramrock.

 

[RAMROCK]

Hi Jack
How did you get this table? I am trying to undertand it but i can´t figure out what is the meaning of all these.

1-1-1-1-1-1 - 444 - 21:49% - 21.65%
2-1-1-1-1-0 - 1031 - 49.90% - 50.56%
2-2-1-1-0-0 - 407 - 20.70% - 20.82%
2-2-2-0-0-0 - 15 - 0.73% - 0.76%
3-1-1-1-0-0 - 122 - 5.91% - 6.61%
3-2-1-0-0-0 - 42 - 2.03% - 2.27%
3-3-0-0-0-0 - 1 - 0.05% - 0.03%
4-1-1-0-0-0 - 4 - 0.19% - 0.28%
4-2-0-0-0-0 - 0 - 0.00% - 0.03%
5-1-0-0-0-0 - 0 - 0.00% - 0.00%
Hello, ram sena's sweet, ne note here that good to use the double
Of digits = 0.0 to 9.9, and the last pair of scarcely two repeats focusing numbers in a column, we see affixing

The mirror filter has been added and i´ll be testing to see if can improve it.
Ramrock.

 

[jack]

Hello, the table is quite easy, the array of 60/6 has 10 columns 6 rows ok Where has the highest percentage in red is the value of repetition of endings in the Columns, the patterns of a column has two numbers ok or both ends, And this is the case with the sixth digit from the front lines (first digit) in one of the lines has two numbers, so let's take this trend, giving two numbers on the line and two In the column, it is easy

 

[jack]

01 02 03 04 05 06 07 08 09 10
11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30
31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50
51 52 53 54 55 56 57 58 59 60
Draws 36 = 03 13 17 25 29 51
colun=03 13
line=25 29

 

[jack]

RAM hello, look at this example has the numbers 03 13 3 3 the last digit in the same column and also the line is 25 29 have the first digit second = 2, joining will give 3 3 2 2 a total of 60 pairs, these pairs is good to see analysis of the three frequencies, then these 22 33e are two endings and first two digits, we have two terminations and two first digit

 

[jack]

hello, the mirror system looks good with 86%. but remembering that must be done in four editions, taking a group to get the group that has zero or one, these are the groups = 01 02 03 04 05 11 12 13 14 15 21 22 23 24 25 06 07 08 09 10 16 17 18 19 20 26 27 28 29 30 31 32 33 34 35 41 42 43 44 45 51 52 53 54 55 36 37 38 39 40 46 47 48 49 50 56 57 58 59 60 these groups are fixed are the four quadrants of 60/6 may want to give away as a group will always a number zero or minimum condition and another is two or more then play a number where he has lost two where to play and has zero or one loses also ramcok, as we do not know which group we play in four editions (4 systems), these four groups also must use filters in the first and last digits, leaving a group of over 15 numbers out, for not going to give it, this filter is basic, if not want to use in four editions, we have to see the endings which will be out, these above groups, you can put as fixed in basic solft to filter,