digit

[jack]

Hello, ramrock, these arrays below, are of terminations (last digit)But only and odd pairsEach array has 100% 65 groups they all sweepstakes daoFinal digit 0 the endings or 9
even
0 0 2
0 0 4
0 0 6
0 0 8
0 2 0
0 2 2
0 2 4
0 2 6
0 2 8
0 4 0
0 4 2
0 4 4
0 4 6
0 4 8
0 6 0
0 6 2
0 6 4
0 6 6
0 6 8
0 8 0
0 8 2
0 8 4
0 8 6
0 8 8
2 0 2
2 2 2
2 2 4
2 2 6
2 2 8
2 4 2
2 4 4
2 4 6
2 4 8
2 6 2
2 6 4
2 6 6
2 6 8
2 8 2
2 8 4
2 8 6
2 8 8
4 0 4
4 2 4
4 4 4
4 4 6
4 4 8
4 6 4
4 6 6
4 6 8
4 8 4
4 8 6
4 8 8
6 0 6
6 2 6
6 4 6
6 6 6
6 6 8
6 8 6
6 8 8
8 0 8
8 2 8
8 4 8
8 6 8
8 8 8

0 0 4
0 0 6
0 0 8
0 2 0
0 2 2
0 2 4
0 2 6
0 2 8
0 4 0
0 4 2
0 4 4
0 4 6
0 4 8
0 6 0
0 6 2
0 6 4
0 6 6
0 6 8
0 8 0
0 8 2
0 8 4
0 8 6
0 8 8
2 0 2
2 2 2
2 2 4
2 2 6
2 2 8
2 4 2
2 4 4
2 4 6
2 4 8
2 6 2
2 6 4
2 6 6
2 6 8
2 8 2
2 8 4
2 8 6
2 8 8
4 0 4
4 2 4
4 4 4
4 4 6
4 4 8
4 6 4
4 6 6
4 6 8
4 8 4
4 8 6
4 8 8
6 0 6
6 2 6
6 4 6
6 6 6
6 6 8
6 8 6
6 8 8
8 0 8
8 2 8
8 4 8
8 6 8
8 8 8

1 1 1
1 1 3
1 1 5
1 1 7
1 1 9
1 3 1
1 3 3
1 3 5
1 3 7
1 3 9
1 5 1
1 5 3
1 5 5
1 5 7
1 5 9
1 7 1
1 7 3
1 7 5
1 7 7
1 7 9
1 9 1
1 9 3
1 9 5
1 9 7
1 9 9
3 1 3
3 3 3
3 3 5
3 3 7
3 3 9
3 5 3
3 5 5
3 5 7
3 5 9
3 7 3
3 7 5
3 7 7
3 7 9
3 9 3
3 9 5
3 9 7
3 9 9
5 1 5
5 3 5
5 5 5
5 5 7
5 5 9
5 7 5
5 7 7
5 7 9
5 9 5
5 9 7
5 9 9
7 1 7
7 3 7
7 5 7
7 7 7
7 7 9
7 9 7
7 9 9
9 1 9
9 3 9
9 5 9
9 7 9
9 9 9

 

[jack]

hello came two lists of pairs, just use a list of even and odd
sao 65 peer groups and odd 65, they are 100% can use
as studies
warning came two lists of pairs, just use a

 

[jack]

Hhelo ramrock, you can make the individual sums of each suit eg
Sum = 001 = 1
Sum = 122 = 5
....
Sum = 555 = 15
the terminations
= 0,4,8 soma12
= 2,6,8 soma16
= 1,2,3 soma6
.....
We have this filter to see
pp = 24
p.i = 51
i.p = 34
i.i = 19
where pp = sigfica digits stop pair
p.i = means = even and odd digits. ok my host site yousendit

 

[jack]

corret p.i=41 ok
p.i= 51error

 

[jack]

Hello, ramrock, or the final digit endings are the three possible conditions Three odd and three pairs, four pairs and two odd and two odd and four pairs So ram is always a group in mimimo three or imparesm pairs or within the 20 positions, where they will be able, in the front digits also It to find the suit pivot ok. My host site is yousendit

 

[jack]

Hello, those 65 pairs are linear, they are correct because they are positional What are these worth 124, to only peers they are ok positional use to study strategy and the 124=
0 0 0
0 0 2
0 0 4
0 0 6
0 0 8
0 2 0
0 2 2
0 2 4
0 2 6
0 2 8
0 4 0
0 4 2
0 4 4
0 4 6
0 4 8
0 6 0
0 6 2
0 6 4
0 6 6
0 6 8
0 8 0
0 8 2
0 8 4
0 8 6
0 8 8
2 0 0
2 0 2
2 0 4
2 0 6
2 0 8
2 2 0
2 2 2
2 2 4
2 2 6
2 2 8
2 4 0
2 4 2
2 4 4
2 4 6
2 4 8
2 6 0
2 6 2
2 6 4
2 6 6
2 6 8
2 8 0
2 8 2
2 8 4
2 8 6
2 8 8
4 0 0
4 0 2
4 0 4
4 0 6
4 0 8
4 2 0
4 2 2
4 2 4
4 2 6
4 2 8
4 4 0
4 4 2
4 4 4
4 4 6
4 4 8
4 6 0
4 6 2
4 6 4
4 6 6
4 6 8
4 8 0
4 8 2
4 8 4
4 8 6
4 8 8
6 0 0
6 0 2
6 0 4
6 0 6
6 0 8
6 2 0
6 2 2
6 2 4
6 2 6
6 2 8
6 4 0
6 4 2
6 4 4
6 4 6
6 4 8
6 6 0
6 6 2
6 6 4
6 6 6
6 6 8
6 8 0
6 8 2
6 8 4
6 8 6
6 8 8
8 0 0
8 0 2
8 0 4
8 0 6
8 0 8
8 2 0
8 2 2
8 2 4
8 2 6
8 2 8
8 4 0
8 4 2
8 4 4
8 4 6
8 4 8
8 6 0
8 6 2
8 6 4
8 6 6
8 6 8
8 8 0
8 8 2
8 8 4
8 8 6
8 8 8

 

[jack]

Hello, are now the odd formations posicionais124, you have to use These are the correct ok 124 odd =
1 1 1
1 1 3
1 1 5
1 1 7
1 1 9
1 3 1
1 3 3
1 3 5
1 3 7
1 3 9
1 5 1
1 5 3
1 5 5
1 5 7
1 5 9
1 7 1
1 7 3
1 7 5
1 7 7
1 7 9
1 9 1
1 9 3
1 9 5
1 9 7
1 9 9
3 1 1
3 1 3
3 1 5
3 1 7
3 1 9
3 3 1
3 3 3
3 3 5
3 3 7
3 3 9
3 5 1
3 5 3
3 5 5
3 5 7
3 5 9
3 7 1
3 7 3
3 7 5
3 7 7
3 7 9
3 9 1
3 9 3
3 9 5
3 9 7
3 9 9
5 1 1
5 1 3
5 1 5
5 1 7
5 1 9
5 3 1
5 3 3
5 3 5
5 3 7
5 3 9
5 5 1
5 5 3
5 5 5
5 5 7
5 5 9
5 7 1
5 7 3
5 7 5
5 7 7
5 7 9
5 9 1
5 9 3
5 9 5
5 9 7
5 9 9
7 1 1
7 1 3
7 1 5
7 1 7
7 1 9
7 3 1
7 3 3
7 3 5
7 3 7
7 3 9
7 5 1
7 5 3
7 5 5
7 5 7
7 5 9
7 7 1
7 7 3
7 7 5
7 7 7
7 7 9
7 9 1
7 9 3
7 9 5
7 9 7
7 9 9
9 1 1
9 1 3
9 1 5
9 1 7
9 1 9
9 3 1
9 3 3
9 3 5
9 3 7
9 3 9
9 5 1
9 5 3
9 5 5
9 5 7
9 5 9
9 7 1
9 7 3
9 7 5
9 7 7
9 7 9
9 9 1
9 9 3
9 9 5
9 9 7
9 9 9
#

 

[RAMROCK]

hi jack,
Have you tested this strategy before? anyway i'll do the software and see what happens..
Ramrock!!

 

[jack]

Hello, ramrock, ok! is that like dismembered in suits positional and divided into two parts
The digits of each number, you can see patterns emerging, look in the example
Terminations, has three output options 3 pairs and 3 or 4 odd pair and two odd
Or conversely, the mimimo then ever, you have three, or not needing to play with the 1000 (one thousand) endings, then any statistic that is made by all can be done by positional suits, the solft give a better view of everything. We can clearly see the repetitions
Digits, there is a pattern that occurs in 100% of the draws, divided into 4 groups
Whenever a group of zero or one numerro, and another two or more numbers, then after you do in a group taking four editions of each, that you can use in any lottery
5,6,7 ...

 

[jack]

Hello, ramrock, your soft will be good!, Because you are intelligent, and works well! Later, I'll give you the right to register solft,

 

[RAMROCK]

i would like that your strategy really worth the effort and all the members can get some advantage of this or give us more ideas and kick the fckd odds. i dont care about the soft...it will be free (limited editions).

Thanks.
Ramrock.

 

[jack]

Hello, ramrock, have been nearly 400 visits in our conversation, so they have ideas Or questions may participate at will, because the concept is for lotteries, 5,6,7 .. From 36 to 70 numbers, the forum members can contribute ideas to improve the prediction The interesting this is that the draw can be in two bowls or the numbers together It will work the same way because it is binary, we have to find out more output patterns of numbers, 80% to 100% and to use the formulas of rotation numbers,

 

[jack]

Hello, you need to analyze column like this, to For example = terminations usually repeat three digits of the draw Previous, but do not know what position then it is closing six of 20 groups The tebela will show in the best position of 20 is better, giving the standard On 20 bets already hit the 3 endings into position, the digit from the front The repetition is greater than three as will 0-6
001=> 132 --- --- --- --- ---
002=> 123 010 --- --- --- ---
003=> 115 024 --- --- --- ---
004=> 115 037 003 --- --- ---
005=> 118 044 010 --- --- ---
006=> 083 040 007 --- --- ---
007=> 089 039 011 --- --- ---
008=> 073 059 011 001 --- ---
009=> 059 052 010 002 --- ---
010=> 071 058 014 004 --- ---
011=> 044 060 025 003 001 ---
012=> 049 062 029 006 --- ---
013=> 041 071 025 009 --- ---
014=> 035 052 037 005 001 ---
015=> 036 053 031 007 001 ---
016=> 024 077 037 012 --- ---
017=> 034 056 047 014 001 ---
018=> 023 054 034 017 004 ---
019=> 019 045 052 014 003 ---
020=> 018 046 046 021 005 ---
021=> 013 036 049 022 003 ---
022=> 012 036 038 026 005 001
023=> 012 048 058 020 010 ---
024=> 011 041 057 033 007 001
025=> 013 028 040 040 011 ---
026=> 008 021 045 030 008 ---
027=> 004 045 036 037 014 002
028=> 005 029 060 036 016 002
029=> 006 031 049 045 019 001
030=> 002 022 053 043 019 004
031=> 002 021 050 039 025 002
032=> 002 021 039 050 025 008
033=> 001 012 043 063 034 004
034=> 001 005 047 055 029 005
035=> 002 011 030 045 034 012
036=> 001 009 037 049 035 010
037=> --- 010 035 055 029 013
038=> 001 005 028 048 041 011
039=> 001 003 021 050 039 012
040=> --- 008 029 050 036 013
041=> --- 006 019 054 057 015
042=> --- 002 023 040 067 019
043=> 001 003 019 048 065 020
044=> --- 004 015 047 045 028
045=> --- --- 009 032 058 024
046=> 001 --- 010 042 051 021
047=> --- 003 008 037 056 039
048=> --- 001 008 023 047 045
049=> --- --- 003 027 058 062
050=> --- --- 008 021 061 060
051=> --- --- 002 020 074 061
052=> --- --- 002 020 053 072
053=> --- --- --- 014 059 083
054=> --- --- 001 009 055 092
055=> --- --- --- 007 039 081
056=> --- --- --- 002 030 104
057=> --- --- --- 004 034 096
058=> --- --- --- 002 020 113
059=> --- --- --- --- 016 127
060=> --- --- --- --- --- 137

 

[RAMROCK]

Hello jack,

I am working on this now but i am so confuse!! 001=>132,---,---,---,---,--- means for number #1 (001) what is 132? a pattern o frecuency?

Ramrock

 

[RAMROCK]

Jack,

Please Check this picture:

http://www.mediafire.com/imageview.php?quickkey=2w11ugfsdnzgh6c

I think, i am doing it wrong!!

Ramrock.

 

[RAMROCK]

Got it!! it is frecuency distribution by column for each number...you say we can set our bet based on these frecuencies. ok. I think we can select 68% for all the first digit patterns and 68% for the last digit patterns and then create all possible combs. Historical draws are telling us the behavior.

Ramrock.

 

[jack]

Hello, ok ramrock, attention is a lotto 60/6. Where 001 has got to understand how the number 01 was just one example, then the the number already done 01 to 60, but is an analysis of the frequency of each of the 60 numbers in your position. And now you have to remember Which was divided into two parts (digits forward and terminations) and then was dismembered In suits, later you can also break up into pairs and blocks and corners. but For well sepois, Ramrock at the top has become so example Results first digi last digit position first digit position of the LAST DIGIT 01,12,23,34,36,45 0,1,2,3,4,3,4 1,2,3,4,6,5 1,2,3 1,2,4 .... up to 4, 5.6 1,2,3 1,2,4 4,5,6 ...

 

[jack]

Mello, ram, good job statistics, you have to remember that we analyze The complete number, 42 we analyze the first digit and last digit, and we break up Of the 20 position not to lose, we have the fixed table 001 of the first two tables have the endings of even and odd sepadas because joints are one million, but separate and odd pair reduces to 142 each, the statistics must have the three frequencies, hot and cold media, and divide into 10 hot and 30 cold medium 20 = 60 numbers

 

[jack]

Hello, ramrock, the above table was made of the number you have to complete two more Tables, the frequency position of the digits from the front of frequencies and other By the end position of the digits, then we have three tables, the 1st table number Complete 01 to 60, it serves to see the columns of another table deposed digit of Front of 20 positions, eg = training, 445, which of the 20 positions it has the highest output, another example 112qual improve the position, this is going to do with statistics Another example of the endings the same table 468 to see what the best position of the 20 positions So why was dismembered we have three tables for the analysis columns The numbers of digits of the front ends 20 and 20 positions

 

[RAMROCK]

Hi Jack,

You say that we will play all odds or all even all the time, because you last digit table are arranged on this way. If I compare your tables with the real stats got it from your lotto file and those are out of the stats...I mean with low proportions (low freq) do you think we can still play this?

Ramrock.