Want a little information for any pick 3 game?

T

Teufellj

Member
A standard pick 3 game has a thousand combinations...right (?) That scares many a newbie and apprentis players alike and it should, if you view the game in that light...
How many days does a person have to use to make a setup? This too is somewhat confusing but no more so than...that thousand combination statement.
How many days? So, why make things difficult? I use six days to get the seventh day because in Ohio we are now playing seven days at two games per day in the Pick 3/Pick 4 and Rolling Cash 5. (Note, the Rolling Cash5 game is quite different from the three and four ball games and NOT used with the setups that are mentioned for the other two games.) If I were playing only six days it would be ...five days to get the sixth and so forth. There are a few other things that I do when concocting a setup but it's necessary to hold off on that info for another time.

Teufellj...:smokin:
 
bloubul

bloubul

Member
Hi Teufellj

I read almost all of your posts, but I can't remember that you have disclosed any way how to eliminate numbers from a 6/49 lotto. Do you concetrate more on a Pick3/4 game?

How will you eliminate numbers from a 6/49 lotto.

BlouBul :cool:
 
T

Teufellj

Member
An answer about...

Hello bloubul,
yes to Pick 3/pick 4 for the most part. Filtering or sifting---I never get rid of any digit or pairs; In a 6/49 type game...I can reverse them up to the 44 set and then reincorporate whats left over either into a string or two or spread these spares into one of my strongest lines to make a wild card set.
As a general rule I do not publish everything that I do or play, so when the moment hits, folks that know me sometimes learn a thing or two!

Teufellj...:smokin:
 
bloubul

bloubul

Member
Hi Teufellj

What I want to know is how to get rid of excess numbers, which will not be part of the next draw.

BlouBul :cool:
 
T

Teufellj

Member
BlouBal...

Hello again, BlouBul,

In answer to your specific question...I take a different approach than most players...

12345
67890

Are you familiar with the above? It's not a divisional math problem but a reflection of any given number or numbers that can be mirrored...

I use that formula to change numbers up to the 44th. of 49 sets. I stop at 44 because I may want to use the actual numbers already played or change a portion plus, there are actually two more mirrors...45 and 46 or if I want to keep the number range to a smaller grouping I will go...4+5= 9 and 4+6=10 (1)...and add these into the equation. In essence, I am eliminating, filtering and causing a new grouping to be formed without a balancing and juggling act.I don't try to remove or eliminate a set but change the look or reaction that will be caused. Just like in a game of pool if you are too heavy handed your cue ball may fly off of the table; if your stick barely taps a ball when you should have had a bottom right english slam, it (the ball hit) may or may not sink into a given pocket called. I used the pool game to illustrate "finessing" of numbers. Balance and touch are critical to both games!Most long time players know when and how to attack a given situation and they already know or improvise as the game progresses. I never get rid of numbers, I try to take advantage of them!

Teufellj...:smokin:

 
bloubul

bloubul

Member
Hi Teufellj

No I'm not familiar with the above method of you, will give a few examples please.

Thanks

BlouBul :cool:
 
T

Teufellj

Member
Start of answer to BlouBol's question!

12345
67890

This "formula" allows mirror sets to be made:

123 is 678; 02 is 57; 444 is 999; 344 is 899 and etc.

The formula can extrude change in single digits or multiple numbers as was demonstrated above. It is plain simple math. If I were to simplify as in Egyptian math-(No zeros) then I would have to redo certain parts of my tables and not use any zeros but instead I would double up on the ...1's...in the 1's playing area (because ...10=01and 10 also=1). There would be no carry over surplus numbers...1 thru 9...is all that would be used. This setup can be used in just about any game that has math involved.

When the "formula" is used, keep in mind that you must reconvert to the original digits for the preferred playing sets that you want.
Another thought is that sometimes..." it may be best to NOT reconvert those sets: eg,...225=770...but maybe you are looking for something like...255...(?)
In this case as in other doubles in the pick 3/pick 4, it is simpler to just flip-flop them and not go into conversion tables. Using the "formula" on the ...6/49game...you can also do the flip-flop which in this game you would Not Reconvert to original determined numbers and in effect you are eliminating excess numbers that you don't want. When you Do Not reconvert you have added to the games next playing day and go thru the same process of elimination all over again.
Many of the ways described are interchangeable with other games, however, paying close attention to what you are about will save you a major screw up down the line. I make notes on what I did and the expected outcome that should occur.

Teufellj...:smokin:
 
T

Teufellj

Member
Why, THANK YOU, blitzed...!
Folks think that how I do things is difficult until they get the hang of simplicity.

Teufellj...
 
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