The keys to winning: Day games First Number...Pick 5/6 First to digits

S

Sharks001

Member
Ok this is only my view on pick3 day games the first number digit make or break your chances on the win......get the first number correct and your in with a good chance. On Pick5/6 games your first number is important like pick3 but your second number will make sure your chances of winning a prize is better.....Some may disagree with me but in my own trial and error I have seen this plenty of times.....I have hit 5/6 twice on a normal 6/49 lottery. Your view on this

I will even go as far to say Lottery companies protect the first digit number -Pick3 and Pick 5 and Pick6.....the most people they can fool the safer the jackpot and a chance to roll the Jackpot
 
S

Sharks001

Member
Appologies my keybords w went missing there...the heading should read : The keys to winning: Day games First Number...Pick 5/6 First two digits/ numbers
 
mabuse

mabuse

Member
Hi Sharks!!!
It's certainly true that you have to have the first two numbers/digits correct if you want to win a major prize/the jackpot in a 49 ball draw....
Apart from playing a rather expensive 2if2 wheel with all the numbers what's your strategy to achieve this??
 
S

Sharks001

Member
bloubul said:
Sharks001

Can you be more specific with some examples.

BlouBul :cool:
Click to expand...

Bloubbul

Just some logic

On a pick3 if your first number is out you have lost.....its the most important digit/number you MUST get right to win straight. Example winning Number 476.....You played all your combinations a 4 -your in with chance to a straight hit

Same apply to Pick5 and Pick6. Getting the first 2 numbers perfectly correct your chances of ending up in prizes are so much better. The same apply there like in pick3...Getting the first number incorrect your jackpot chances are over....and your on a deficit to catch a prize too. If you can get the first two digits correct your in with a chance to a jackpot and lotto companies worst nightmare.....My logic they PROTECT the FIRST NUMBER on ANY game.....if you will also see the winning number is also always the least numbers played....it make business sense for them to throw you out on the very first number.....thus protecting the Jackpot to roll
 
S

Sharks001

Member
Mabuse correct if I knew how to accurately get that right I will sharre that is the ten million dollar question right there for you:teach:

mabuse said:
Hi Sharks!!!
It's certainly true that you have to have the first two numbers/digits correct if you want to win a major prize/the jackpot in a 49 ball draw....
Apart from playing a rather expensive 2if2 wheel with all the numbers what's your strategy to achieve this??
Click to expand...
 
J

jack

Member
Hello, straks, also the last digit or last number is important
So we can join the first digit with the last digit in pick3, since pick 5.6
It is the last number the rest goes within the two limit 1º with the last one
 
S

Sharks001

Member
jack said:
Hello, straks, also the last digit or last number is important
So we can join the first digit with the last digit in pick3, since pick 5.6
It is the last number the rest goes within the two limit 1º with the last one
Click to expand...

Hi Jack

No the last digit is easy......First one is KEY. A good predictor is measured on the First number.People that can predict the first number on a consistent basis you can take them serious...they got some serious skills
 
mabuse

mabuse

Member
Hi again, sharks!

Could you please explain how the lottery companies could do what you described below??

Sharks001 said:
My logic they PROTECT the FIRST NUMBER on ANY game.....if you will also see the winning number is also always the least numbers played
Click to expand...
 
J

jack

Member
hello sharks001

In a 3 digit game there are 1000 combinations of numbers. That means that roughly once every 100 drawings the same last two digits will appears in a drawing. The first digit then has a 1 in 10 chance of appearing every time that pair shows.

So if you want to know the most likely pairs to appear in the next 1-25 drawings, look at the last few 100-150 drawings until there are 25 remaining pair that have not yet appeared. There is a reasonably good chance that one of them will appear.

Once you have isolated that pair look at the last 5 drawings where that pair has appeared and since which 1st digit that it appeared with. You will probably wind up with 5-7 digits for you to choose from that have not yet appeared with that pair. And you can probably use some other methodology based on how many times that number has appeared with other pairs in the last X drawings to reduce your choice down to 2-3 numbers.

If you want to factor the number of times that digit was odd versus even as a means of narrowing own your choices you can certainly do that, but in the end all you are doing is widening the number of drawings that it will take for that pattern to reappear.

The more conditions used to define the strategy, the larger the window between drawings when that pattern has a chance of winning. There is no way to circumvent that which is what keeps the lotteries in business.

If you play all odd or all even numbers there are 250 combinations where the numbers are all odd or all even. There are only 50 pairs where the last two digits are all odds or all even. This means roughly once every four drawings you will see that kind of result, no system is going to alter that fact although in the short term there may be times when it occurs once every two drawing or once every ten.
 
J

jack

Member
Hello, frank, could you please do in excel 2010 or higher
About the study of the first digit of the pick3
You can simulate a list of pick 3 then it would just change
Goal = focus on the 1st digit of pick3
 
S

Sharks001

Member
mabuse said:
Hi again, sharks!

Could you please explain how the lottery companies could do what you described below??
Click to expand...

Mabuse just logic if they can throw you off by the first number your out of the equation ....only meant a lottery is a business the more losers then they make money. More winners equal smaller profits for them
 
S

Sharks001

Member
jack said:
hello sharks001

In a 3 digit game there are 1000 combinations of numbers. That means that roughly once every 100 drawings the same last two digits will appears in a drawing. The first digit then has a 1 in 10 chance of appearing every time that pair shows.

So if you want to know the most likely pairs to appear in the next 1-25 drawings, look at the last few 100-150 drawings until there are 25 remaining pair that have not yet appeared. There is a reasonably good chance that one of them will appear.

Once you have isolated that pair look at the last 5 drawings where that pair has appeared and since which 1st digit that it appeared with. You will probably wind up with 5-7 digits for you to choose from that have not yet appeared with that pair. And you can probably use some other methodology based on how many times that number has appeared with other pairs in the last X drawings to reduce your choice down to 2-3 numbers.

If you want to factor the number of times that digit was odd versus even as a means of narrowing own your choices you can certainly do that, but in the end all you are doing is widening the number of drawings that it will take for that pattern to reappear.

The more conditions used to define the strategy, the larger the window between drawings when that pattern has a chance of winning. There is no way to circumvent that which is what keeps the lotteries in business.

If you play all odd or all even numbers there are 250 combinations where the numbers are all odd or all even. There are only 50 pairs where the last two digits are all odds or all even. This means roughly once every four drawings you will see that kind of result, no system is going to alter that fact although in the short term there may be times when it occurs once every two drawing or once every ten.
Click to expand...

Some good logic but if you cant read repeats you will be in for a tough time....how accurately do you know when a repeat is due ??? HIGH odds involved here Jack...I hear you about pairs due..but there is quite a few factors you should consider as its more tricky than lotto or your pick5's. Pick3 is highly more complex to read correctly
 
Frank

Frank

Member
jack said:
Hello, frank, could you please do in excel 2010 or higher
About the study of the first digit of the pick3
You can simulate a list of pick 3 then it would just change
Goal = focus on the 1st digit of pick3
Click to expand...

Jack, what analysis of the first digit would I need to do in Excel that I couldn't do in my head?

probability of a given number = 0.1
probability of same number in 2 consecutive draws = (0.1) squared = 0.01 etc.
probability of first digit = second digit = 0.1
probability of first digit = second digit = third digit = (0.1) squared =0.01
probability of first digit being odd = 0.5
probability of first digit being odd in 2 consecutive draws = (0.5) squared etc.
Probability the digit is made up of straight lines = 0.3
probability the digit is the same upside down= 0.4
probability the digit is spelled with three letters = 0.3
probability the digit when spelled has only one vowel = 0.2


what more do you need to know?? :confused:
 
You must log in or register to reply here.

Sidebar

Top