Black week was really last week, nothing work especially on the Q-49; in the Super 7. I am straitening the concept of the 2 half’s of the orange, 25 numbers and 22 numbers wheels cover the whole 47 numbers and the worst case scenario is 3 +B in one wheel and 4 numbers in the other, it happens (why me, why last week.) last draw and since I played 3 out 4 guarantees wheels. I GOT THE MINIMUN 3 NUMBERS RIGHT IN 1 COMBINATION IN EACH WHEEL!!!
Now the perfect play should be theorically to play 4 out of 4 wheels, even in the worst case scenario you will win something and if you are lucky and one wheel gets the 7 + B you are on your way very close to the jackpot, the problem is the cost and how many times before you can get the perfect mach inside your wheels. To play 4 out of 4 in 25 numbers takes 440 combinations and 22 numbers 252 combinations, all together a total of 692 combinations, divided by 3 (Loto Quebec has Personal Selections 3 combinations pick by you at $2, I am not sure all provinces of Canada have this option) = 231 (you have to play 1 extra combination yourself) x $2 = $462.
If you have not luck like me last week and get the worst case scenario 3+B plus 4 in the other, you probably lost most of the $462. but if you get 7 + B in one wheel…you are on the way to jackpot land, now the dilemma I am facing this week is what kind of wheel to use on these 2 half’s of the orange.
Back to the play we start as usual with the free tickets won last week (2).
04 18 21 24 30 34 44…03 05 06 16 19 38 47…07 17 26 28 33 35 46
02 03 04 06 07 16 44…21 28 30 32 37 40 42…01 12 18 20 29 34 45
I am thinking
…I am 
…Babar 
Now the perfect play should be theorically to play 4 out of 4 wheels, even in the worst case scenario you will win something and if you are lucky and one wheel gets the 7 + B you are on your way very close to the jackpot, the problem is the cost and how many times before you can get the perfect mach inside your wheels. To play 4 out of 4 in 25 numbers takes 440 combinations and 22 numbers 252 combinations, all together a total of 692 combinations, divided by 3 (Loto Quebec has Personal Selections 3 combinations pick by you at $2, I am not sure all provinces of Canada have this option) = 231 (you have to play 1 extra combination yourself) x $2 = $462.
If you have not luck like me last week and get the worst case scenario 3+B plus 4 in the other, you probably lost most of the $462. but if you get 7 + B in one wheel…you are on the way to jackpot land, now the dilemma I am facing this week is what kind of wheel to use on these 2 half’s of the orange.
Back to the play we start as usual with the free tickets won last week (2).
04 18 21 24 30 34 44…03 05 06 16 19 38 47…07 17 26 28 33 35 46
02 03 04 06 07 16 44…21 28 30 32 37 40 42…01 12 18 20 29 34 45
I am thinking
…I am …Babar 
Babar 
of this week, 
Babar 
spell