Sangoma-number divination

Springbok

Member
Multiple strikes?

I am going to stick my neck out.I ran my triple file zulu. zulu12 and zulu14 according to the statistical reports are due in lunchtime today( 31 January). Zulu12{15, 34, 43} and zulu{18, 21, 35}. The parameter used was 100 draws. I wonder what will happen? As yet techniques with triples are not fully tested so the probability is 25%, although I would put these two triple at 60%.
 
The probability for a duplicate group in a draw, whit 14 groups, 13 whit 3 numbers, one whit 4 (I would prefer 15 groups all whit 3 numbers) is 83,59% (Birthday Paradox). The probability that a group of numbers will hit twice in 3 draws after he was already drawn twice is 47,2% and to hit within 4 draws is 53,3%. I would not take this percentage for granted because although my calculations seem correct they may not be. I now test a system that evolved from two mistakes… So do not take anything for granted. It would be interesting to know if we should apply a strategy based on the median value of skips, or still on the highest values. I wait for some opinions. Anyway test must be performed whit a powerful software. :look: See you later, now I study. :dog:
 

Springbok

Member
Excellence, in the final analysis what we are trying to achieve eventually in the 6/49 game is to occupy each of the 6 slots with a number pair which will give us 64 combinations. Then we hit those combinations with the Purge function of Lotwon632 and the Past draws in Mdied to reduce them to 4 or 5. Get that right and you have achieved what is regarded as impossible winning the jackpot with skill and cunning and not relying on blind luck.
 
I was thinking the probability is way to large, so I spotted my mistake. The probability for at least 2 of 3 is not equal to the probability of at least one of 3. The probabilities presented above stand correct for the at least 1 of 3. They are in fact the probability of the group of 3 numbers. For multiple strikes the number of trials required for a probability above 50% is 11! So playing the groups that have a skip, calculated like I said in my previous post, of 9 or 10 could indicate that the group will have two numbers in the next 2 or even next draw. Need soft to verify. We can also improve the odds by making a statistic report. How many times a group exceeded his median whit a previous skip value bellow or above median. Or things like that. Please someone whit countif function. It can be crucial really.
Reading last Springbok post. I think that the are other possibilities of hitting the jakpot. How much I wish to have my analysis completed by Thursday. The jackpot in my country’s lotto is around 6 million euros.. But until then I think we should work on some strategies that bring us money, like in sports betting. We need money to buy the most precious thing: TIME. In time only we would achieve a strategy that could be the killer for lotto games. And my guess is that that strategy will also kill any gambling, of any form. Much time ahead.
One of my fundamental principles is that randomness was built in a mould. The theory of probabilities or the randomness are like a labyrinth. We need a map and the only way to achieve is step by step, number by number if you wish.
Again please someone whit the countif function, really. I know it is a lot to work but I also know that it could be possible.
 

Patrick123

Member
Okay Springbok, I've uploaded the latest program that allows you to view all 18424 triples combinations(for 49 balls at about 200MB memory 800 draws) in it as well. I was thinking of using this to highlight triples of interest, which we can then zoom in on.
I've still got a bit to chew on, I'll let you know how it goes.
Regards
Patrick
 

Springbok

Member
Excellence, the way to beat "randomnes" is to avoid individual numbers but to work in groups or sets of numbers. If you read the book -The Newtonian Casino- these people were able to predict which area the roulette ball would land in, not the individual number. An excellent way of doing this is to play the douzains at roulette based on Ion Saliu's strategy. There are 3 douzains. You divide the douzains into 3 groups:-
A(1, 2)
B(1, 3)
C(2, 3)
You bet always on one of the three groups. Each time you bet you are in the 67% probabilty zone. Where you bet depends on the skips. You have to record the results. I play roulette(play, play money) on my computer. The CD is from the bookie I bet the 49s with. Without fail I win play, play money with this method. Whether you would win if you went online is something I don't know. Is the online roulette game honest as the play play one? Someone reported on Saliu's site that they were making real money with this method. I don't know if it was on an internet or real casino. You are using sets here in roulette and not betting on individual numbers. In another book - The Man Who Broke the Bank at Monte Carlo- used teams of people using the reverse labouchiere betting sequence at roulette. If there were 3 teams, 2 would lose but the third would win. They got banned from the Casino, Monte Carlo and France. When people go shooting birds with shotguns, 100 pellets might miss but one will hit. Catch the logic of using sets, Excellence, in any activity.
 

Patrick123

Member
Seeing that we're going off topic slightly, back when Pa fell off the bus, I had a method for the horse racing, I'll try and dig it out, essentially, taking into account, the course, handicaps, time, etc. the formula spits out a number which you plot (day offset vs value). You then fit a sine curve to this. The favourites had a high amplitude and short frequency, compared to the outsiders that had long frequencies. You simply extrapolate the curve to the day of the race. It sort of worked fine, but in those days, you had to manually calculate everything & plot it on paper, so by you got finished, the races were already over.
Regards
Patrick
 

Springbok

Member
Well with computers, your calculations could be done in a flash:) I prefer random numbers as they are more predictable. I once typed in a horse racing programme on one of those early computers which ran at zero megaherz. It predicted a horse at Turffontein which had odds of 300-1. The horse was from the Orange Free State. The horse was called Chimborazo. I did not believe the computer. The horse won going away.

Here is another idea which does bear fruit sometimes. You use 2 different sets of numbers:- example
M5alpha8 {36, 37, 38 ,39,40}
M6alpha4{31, 32, 33, 34, 35 ,36}

The M designates the numbers in the set(to avoid confusion). When you see a common number in each set it can point to the number coming in. So if they both come in at teatime then the chances are that 36 will be the number. This is the only way I know of forecasting a single number but it is not infallible. This can be done with triplets say M3bravo7 and M3omega12. You predict they will come in next draw and they have a number in common. I have seen this happen many times.
 
Hi Patrick,
I was looking at your software. After I loaded the csv file from the zip, I went to Ball analysis and pressed Triples analysis. Great job whit the triples combination. I was wondering what is the current skip for every combination? Last drawn?
 

Patrick123

Member
This is similar to the concept that I use on the Draw Probability Screen. I basically count the number of times a number appears in one of these sets of interest (whether pairs or trips) and display it there as a weight.
 

Springbok

Member
to Patrick and Excellence

Thinking of Excellence's idea posted earler today we can think of the original Eliminator concept of Fullhouse. Chase 3 numbers up to the 24th or 25th draw and try and get 2. If we pick the three highest skip numbers below 25(or was it 24) and pair them. You will have 3 pairs. Perform a statistical analysis and see which one comes out on top. Another idea pick 3 numbers that are one skip below their 92% historical skip level and pair them and get a stats report on the best one.I am talking about real numbers before we convert into pairs.
I had better take a work break now for a few hours.
 

Patrick123

Member
Well #37 is now way past it's sell by date, but my order of preference for lunch time is as follows:
Number - Single Perc - Pair Perc - Trip Perc
41 - 0 - 71 - 51
37 - 100 - 68 - 49
11 - 0 - 63 - 51
15 - 0 - 60 - 48

Number 43 is showing unusually high values in the trips(usually the values go down), I wonder if it's trying to tell us something.
43 - 0 - 50 - 60

Regards
Patrick
 

Springbok

Member
My money is on the pair 32, 37. Definitely 37 should hit lunchtime. Can you explain exactly what pair perc and trip perc are referring to?
 

Patrick123

Member
As how you calculated percentages on the individual pairs. To give me an accumulated percentage, e.g. if the pair 32,37 gave me 8 8 8 9 10 10 hit & we were on 8 that would be 50%. Now if 29,32 gave us 7 7 8 and we were on 7, that would be 67%. because I take all the possible pair and combinations, the above would give me and accumulated count of 5/9 = 56% for the number 32. Immediately then I can look at all pairs containing the number 32 and get a better picture of its relationship with the other numbers.

Regards
Patrick
 

Springbok

Member
Baie dankie Patrick123, I catch what you are doing. Well 37 dropped in lunchtime. The 800 draw margin is pretty rigorous to catch the high skip chappies. I am having problems harmonising the pairs for simultaneous hits next draw. I was also experimenting with triples. In one instance I picked 7 triples sitting on their median. 5 hit in the next draw and the remaining two hit in the second draw.. Phenomenal I thought, it was but this is not a normal occurence and could not replicate it. I theoretically worked out that 93% of pairs should hit by the 9th or 10th drawing with 7% escaping to hit at a later date. This would mean that we should hit 9 out of 10 of these gents provided they were in the 4 draw parameter to the 10th skip. Will run tests on this. Often theory and actual practice do not coincide.
 

Springbok

Member
I must emphasize that it is totally essential to have 3 hits on one line or there is no hope for the 6/49 or the 5 number section of the UK Thunderball. The pair predicted hit lunchtime today. If it can be done for one pair, why not three pairs? At the moment I shall be trying to predict 2 triples and one pair. When I feel confident enough I shall post predictions. To me a 50% strike rate on 3 simultaneous hits = confidence. I have numerous tricks up my sleeve which I have never mentioned. But for the moment sangoma will be used. The numbers must speak to me nicely:)
 

Springbok

Member
Predictions for teatime. A choice here-:
{8, 32} high at 17 over 1000 draws
{32, 41} high at 17 over 1000 draws
{8, 41} high at 17 over 1000 draws

They cannot all hit at the same time, maybe two but not three. Which one. I don't know. Patrick, any ideas? I would tend to go for anyone with 32 in it.
 

Springbok

Member
Trying for a double strike with a pair and a triple. The triple is M3iota6. Consists of {7, 18, 22}. Sitting on a 200 draw high of 7. The pair will be {8, 32}. For teatime draw.
 

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