# positional system in 27 formations at 100% pick 3

#### jack

##### Member

positional system in 27 formations at 100% pick 3
then we have to
k = 0,1,2,3
0 = 4.5
1 = 6,7,8,9
27 formations (standards) Positional 1st, 2nd, 3rd you have to look for column, each of the 3 columns
the reduction of pattern is 100%
example
478 = 011
159 =k 0 1
k k k
k k 0
k k 1
k 0 k
k 0 0
k 0 1
k 1 k
k 1 0
k 1 1
0 k k
0 k 0
0 k 1
0 0 k
0 0 0
0 0 1
0 1k
0 1 0
0 1 1
1 k k
1 k 0
1k 1
1 0 k
1 0 0
1 0 1
1 1k
1 1 0
1 1 1

#### jack

##### Member
we have the 27 formations
subdivision

K=0,1,2,3,

0=4,5

1=6,7,8,9
KO1
K
PAIRS =K= 0.2
0 = 4
1 = 6.8
ODD
KO1
K = 1.3
0 = 5
1 = 7.9

#### Icewynd

##### Member
Well, the same pattern only repeats about 10% of the time, so you are pretty safe eliminating that one, if that is what you are asking.

#### jack

##### Member
yes !! is it ok !!!. ice, if the last pick3 draw (need to test thousands of sweepstakes) it is 10% to repetition,
then need to make standards Statistics delays or patterns cycle, how long it takes to drawn all 27 padreos, comprrende thus controls standards and not numbers =
we can expand the columns also
459
753
120
then = 47120 = 01kkk
55120 = 00kkk
93120 = 1kkkk
then we have = 01kkk, 00kkk, 1kkkk
ice here was accompanied by the three columns in the vertical to the horizontal
the last draw (120) crossing the patterns

#### jack

##### Member
ice, this patterns of 27 formations and sub-pairs / Odd
You can work better than vtrac?