Here's a question -- has anyone ever broken a Pick 6 lottery (such as 6/49) into two sets of 3 numbers and then treated those as a Pick 3 problem?
To do this we would have to break each of the lottery numbers into digits. For example, 49 would be broken down into the decade (40 or 4) and the last digit (9). 17 would be 10 (1) plus 7. and 1-9 would become 0 (zero) plus 1, 2, 3...9. Focusing just on these final digits would give us a set-up similar to two Pick 3 games where we try to pick 3 digits out of 10 (0-9).
For example, the last ON49 result was 3-17-19-20-46-49. Just looking at the last digits we can break this into a first 3 (3-7-9) and a last 3 (0-6-9). Now we could apply Pick 3 techniques to see if we could figure out the next digits that would be played. Only "straight" Pick 3 results would be useful -- in other words we would have to get the 3 digits in the correct order. Then we would have to add in the decades to get back to the full lotto number.
Of course, the cases aren't exactly comparable. Pick 6 doesn't have a zero in the lowest decade, so the only time a zero could appear in the first position would be if the first number was 10, 20 or 30, which happens only 5% of the time. Even with this handicap, the first digit of the first three still has a 62% chance of being a low digit (0-4). For the back threesome, the third digit has a 66% chance of being a high digit (5-9). However, these anomalies make it easier to pick the first digit of the front 3 and the last digit of the back 3 than it would be for a Pick 3 game where all digits are equally represented.
Is this worth following up? What's your opinion?

To do this we would have to break each of the lottery numbers into digits. For example, 49 would be broken down into the decade (40 or 4) and the last digit (9). 17 would be 10 (1) plus 7. and 1-9 would become 0 (zero) plus 1, 2, 3...9. Focusing just on these final digits would give us a set-up similar to two Pick 3 games where we try to pick 3 digits out of 10 (0-9).
For example, the last ON49 result was 3-17-19-20-46-49. Just looking at the last digits we can break this into a first 3 (3-7-9) and a last 3 (0-6-9). Now we could apply Pick 3 techniques to see if we could figure out the next digits that would be played. Only "straight" Pick 3 results would be useful -- in other words we would have to get the 3 digits in the correct order. Then we would have to add in the decades to get back to the full lotto number.
Of course, the cases aren't exactly comparable. Pick 6 doesn't have a zero in the lowest decade, so the only time a zero could appear in the first position would be if the first number was 10, 20 or 30, which happens only 5% of the time. Even with this handicap, the first digit of the first three still has a 62% chance of being a low digit (0-4). For the back threesome, the third digit has a 66% chance of being a high digit (5-9). However, these anomalies make it easier to pick the first digit of the front 3 and the last digit of the back 3 than it would be for a Pick 3 game where all digits are equally represented.
Is this worth following up? What's your opinion?
