Pick 6 = Two Pick 3's?

Icewynd

Member
Here's a question -- has anyone ever broken a Pick 6 lottery (such as 6/49) into two sets of 3 numbers and then treated those as a Pick 3 problem?

To do this we would have to break each of the lottery numbers into digits. For example, 49 would be broken down into the decade (40 or 4) and the last digit (9). 17 would be 10 (1) plus 7. and 1-9 would become 0 (zero) plus 1, 2, 3...9. Focusing just on these final digits would give us a set-up similar to two Pick 3 games where we try to pick 3 digits out of 10 (0-9).

For example, the last ON49 result was 3-17-19-20-46-49. Just looking at the last digits we can break this into a first 3 (3-7-9) and a last 3 (0-6-9). Now we could apply Pick 3 techniques to see if we could figure out the next digits that would be played. Only "straight" Pick 3 results would be useful -- in other words we would have to get the 3 digits in the correct order. Then we would have to add in the decades to get back to the full lotto number.

Of course, the cases aren't exactly comparable. Pick 6 doesn't have a zero in the lowest decade, so the only time a zero could appear in the first position would be if the first number was 10, 20 or 30, which happens only 5% of the time. Even with this handicap, the first digit of the first three still has a 62% chance of being a low digit (0-4). For the back threesome, the third digit has a 66% chance of being a high digit (5-9). However, these anomalies make it easier to pick the first digit of the front 3 and the last digit of the back 3 than it would be for a Pick 3 game where all digits are equally represented.

Is this worth following up? What's your opinion?

:thumb:
 

Teufellj

Member
Hello Icewynd, that mess above makes for interesting thoughts. My thinking is...
1-know which game (md/or eve) that you would use for the setup or would you use both (with or without mirrors)
2-the pick3 game has 10 balls or 30 total. The larger game uses 49 balls.
3-you may want to play games flipping digits it's no bad thing but...
4-statistics and a probability runup would enhance your numbers but can
they give good odds for getting numbers like...6 and 7 or 39 and 40?
5-back to back next digits in sequence appear often in winning plays.
6-which state or country has a close numerical system that gives like numbers as the 6/49? And would you choose-RNG's over Ball drops? Those are some considerations for thought!

Teufellj...
 

madam

Member
Icewynd: I get the following #s from Sat. win, 467 and 057. Do we then do a run down as with Teufellj.
 

Icewynd

Member
madam said:
Icewynd: I get the following #s from Sat. win, 467 and 057. Do we then do a run down as with Teufellj.

Hi Madam,

Yes, that's what I get too.

I'm not sure about doing a rundown -- a rundown is meant to exploit the random aspect of Pick 3, but the more I look at this idea the less I am sure that the comparison to Pick 3 is valid.

For one thing, Position 1 and Position 6 from the Pick 6 game don't feature all the digits equally as for Pick3. In the Pick 6 game, Position 1 is much more likely to feature the digits 1-4 (58% of the time) while in P3 all the digits are equally likely. Same for Position 6 with the digits 5-9. The Pick 6 game also seems to be more likely to repeat at least one digit from the last game (64% for Pick 6 vs. 40% for Pick 3) and to feature at least one digit from the last 3 games (Pick 6 95%, average 2.6 vs. Pick 3 93%, average 1.8).

So, I would proceed cautiously with any attempt to predict last digits this way -- although I am going to keep looking at it, as it provides some interesting insights into the game. For example, did you know that "9" hasn't hit in Position 1 since last July? That's 49 games! Whether or not it is due I can't say, since the record is for a digit to miss in this position for 89 games in a row.

Anyway, interesting, but I'm not sure if its useful.

Good luck!
:thumb:
 

jack

Member
hello, ice, good filter, you can use the best system pick3
* and make a prediction as if it were two 3 pick3 after joining
also can desmenbrar 20 positions
1,2,3 1, 2,4 4,5,6 = ................... 20 positions, thus positional, not needing to unite as the two separated by 3 digits each, but both are good filters, both desmenbramento by position (20 positions) or in two sementos
 

Teufellj

Member
Two Pick3's...

Hello again, Icewynd,
I've had some more thoughts about building some possible outposts
to get numbers for this...6/49.
Suppose doing what I'm messing with now, which is to double-double the winner and its mirrors by running the digits across and down then reversing
the original direction to run the numbers down then across with the mirrors. This would give 24 digits as a base to work nearly twice the possibilities for two or three lines of play. I would think that starting out like this and incorporating what winner digit plus its mirror would give two to three solid numbers in the line plays. These two or three digits could be traced week by week in reverse time order and may allow knowledge about what to play.
The other members chiming in on this post, have valuable information that adds to whipping this beast. Plying all of your information in one bowl and thorough mixing could tame your game. It's good to see many thoughts and ideas pouring from so many free thinkers.

Teufellj...
:smokin:
 

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