Number Picker Challenge Selection Methods

Ramijami

Member
Was thinking the number picker challenge is possibly a good opportunity to share ideas/methods on selecting numbers. I will post my current selection method and others are free to share theirs (or not). I don't know how LotteryHits selects so won't be able to provide that. My current method (done by computer):

Randomly select 20 unique numbers. Compare the selected set to the following criteria and discard if it fails:
No more than 5 matching any of the previous jackpots (I use the full draw history).
No more than 4 matching any of the last 100 draws.
No more than 3 matching any of the last 3 draws.
No more than 6 matching the last 3 draws combined (so no more than 6 from the 18 numbers in the last 3 draws).
Odd/Even 8-12.
High/Low 8-12.
No more than 6 from same decade.
No more than 3 of the same last digit.
No more than 3 of the same individual number rootsum.
No more than 4 from the same 7 number group (1-7, 8-14 etc.)
No more than 5 consecutives.

Looking forward to see the different selection methods of those willing to share :) :) :) .
 

Icewynd

Member
Hi Ramijami,

Great idea for a post!

What I do is to list all 49 numbers by their skip. I then eliminate numbers that have skipped more than 10 games. Then I look at what I can eliminate based on decades, playslip groups (7's grouped by rows and columns), last digits, expected repeats, etc. Using these 'clues' I eliminate numbers until I have only 20 left.

Good luck!
:thumb:
 

jol

Member
Other than the first challenge game I use non of the above.:eek:
I have used the challenge to try a new idea based on previous line hits/misses.:idee:
Numbers are the first 20 with no alteration or filter, if it throws out 1 to 20 then that is what I would use.
I have been chasing the bubble a bit but from now on I will use the same system without tinkering.:smash:
It will be interesting to see how it does.
All the very best of luck.:goodluck:
Jol
 

Ramijami

Member
Was thinking of a "starting" point for a strategy. The premise is "What if" we combine the two sets that consistently matches the most numbers when combined to create a possible starting or "Master" set. These are the previous sets (from draw 12) with the matching numbers on the side (not sure if there are errors):

Random - 1 2 4 6 10 11 12 18 19 20 25 26 31 32 34 36 38 42 44 49 --- 25 36 44 (04)
Frank - 03 05 07 09 10 12 14 16 19 20 21 24 26 30 35 45 46 47 48 49
Ramijami - 1, 2, 5, 6, 8, 9, 17, 19, 22, 24, 25, 28, 30, 38, 39, 40, 42, 44, 45, 47 -- 08 25 39 44
LotteryHits - 04 09 11 12 18 19 23 24 25 27 28 29 30 31 33 35 41 45 46 49 --- 25 27 (04)
Blitzed - 04 07 08 13 16 18 26 29 30 31 33 34 39 40 41 43 44 46 47 49 --- 08 39 44 (04)
IceWynd - 2 4 8 9 11 12 13 14 15 16 18 19 22 23 24 25 26 37 44 45 --- 8 25 44 (04)
Jol - 1 4 5 9 10 11 14 15 16 18 19 25 28 29 35 37 43 45 47 48 --- 25 (4)
Niteowl - 02 04 07 10 11 15 18 19 24 25 28 29 30 35 36 37 40 41 45 49 --- 25 36 (04)

These are the two sets COMBINED that gave the most numbers for draw twelve:

Random+Ramijami (5+b)
1, 2, 5, 6, 8, 9, 17, 19, 22, 24, 25, 28, 30, 38, 39, 40, 42, 44, 45, 47
4 10 11 12 18 20 26 31 32 34 36 49 (32)

Ramijami+Lottery Hits (5+b)
1, 2, 5, 6, 8, 9, 17, 19, 22, 24, 25, 28, 30, 38, 39, 40, 42, 44, 45, 47
04 11 12 18 23 27 29 31 33 35 41 46 49 (33)

Ramijami+NiteOwl (5+b)
1, 2, 5, 6, 8, 9, 17, 19, 22, 24, 25, 28, 30, 38, 39, 40, 42, 44, 45, 47
04 07 10 11 15 18 29 35 36 37 41 49 (32)

These produced (5+b) in 32/33 numbers. I'm sure there should be some full Jackpots matches in those draws where there was a 5 number match (haven't had time to back test other than this draw). Could be a possible strategy to explore if one can choose which two predicted sets to combine to best effect????? What do others think?
 

Icewynd

Member
Interesting idea, Ramijami.

Indeed, there has been at least one example of a 6 match when combining sets.

In draw 2 (January 4th), I matched 5 numbers (all main numbers). Jol had the missing main number (4) and 8 different numbers for a total of 28, Frank had the missing main number and 10 different numbers for a total of 30 and Random had the missing main number as well as the bonus number (4 +8) with 13 different numbers for a total of 33 numbers in all. Playing all 1,107,568 combinations of those 33 numbers would have been profitable indeed, netting a Jackpot plus 6 5/6+Bonus prizes.

Since Frank and Random have been the best predictors so far, a good rule of thumb might be to combine your set with either (or both) of those.

Keep us posted if you decide to follow this strategy. I think it has promise to capture all 6 numbers, but gives a rather large pool to deal with.

Good luck!
:thumb:
 

jol

Member
Ramijami. Icewynd
Agreed thats still a massive set of numbers to cover.
Have you ever tried to hit 6 yourself in less than 33 numbers ? your picks so far in the challenge suggest that you can probably beat 33.
How about a hit 6 in the lowest set of numbers challenge, you pick any set of numbers, set then out in the order you want them used then see who gets all 6 in the lowest number of balls.
Jol
 

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