lottery 49/6

[jack]

Hello, is there any study on this?
Greater, or less based on the last draw
In 49/6?
* example
10 12 26 35 42 49 last draw (base)
08 10 25 30 38 45 next are all smaller numbers
So we have three conditions in each position of the last to close
* Most smaller and equal,
* How can put together a study on this with the endings (last digit)?

 

[Icewynd]

You want to know if the digit in each position is higher or lower than the previous draw, is that it?

I find a useful measure is to compare the drawn numbers to their median. For example, numbers below 4 skips are below-median while numbers that hit at skip 5 or higher are above median. That way, you know that 50% of your hits will come when the digit is in the below-median position.

Good luck!

 

[doug_w]

Hi Icewynd

You want to know if the digit in each position is higher or lower than the previous draw, is that it?

I find a useful measure is to compare the drawn numbers to their median. For example, numbers below 4 skips are below-median while numbers that hit at skip 5 or higher are above median. That way, you know that 50% of your hits will come when the digit is in the below-median position.

Good luck!

In an earlier thread I remember you mentioning that the Median for the Canadian Lotto was 4. Now is that the Median as a general measure, or do you work out the Median for each Ball. Do you also use Standard Deviation and Mode by any chance.

Cheers

 

[jack]

Ok ice, the base or reference will always be the last draw,
At each position in the vertical, view the entire number (union of the initial and final digit)
* example
1st place
49/6
* He next 10 gave 08 or smaller, but the last digit is greater
* So we have 3 standards- major, minor and equal to the number itself
* How to reconcile endings, last digit (0 -9)?

 

[jack]

Ice is possible to create an algorithm taking as a basis the pair of endings?
* example
* Base49 test / 6
10 15 25 29 36 45
* Pairs terminations = 05 59 65
* Initial digit does not enter the study

 

[Icewynd]

In an earlier thread I remember you mentioning that the Median for the Canadian Lotto was 4. Now is that the Median as a general measure, or do you work out the Median for each Ball. Do you also use Standard Deviation and Mode by any chance.

Cheers

If you have enough data, the skip median for each ball should converge to the theoretical median for the group. Don't use the SD. I do use Mode, but only in the sense of a general frequency analysis of the numbers.

 

[jack]

Last Draw Z1,1 Z1,2 Z1,3 Z1,4 Z1,5 Z1,6
Next Draw Z2,1 Z2,2 Z2,3 Z2,4 Z2,5 Z2,6
- ΔZ = Z2,C - Z1,C


Differential Distribution Between Draws
- C - Column

 

[doug_w]

Thanks Icewynd

If you have enough data, the skip median for each ball should converge to the theoretical median for the group. Don't use the SD. I do use Mode, but only in the sense of a general frequency analysis of the numbers.

Thamks for the reply, much appreciated. From a quick look through the Lotto Results for Saturday Draw here in Sydney a lot of the numbers drawn fall below the Medion.

Now Balls that have a Skip greater than the Median, surely the Standard Deviation would be useful in picking numbers eg if Ball Skips isgreater than the Median + Standard Deviation the ball is overdue and could be a possible number to pick.


Wish I was a Mathematical Statistical Wizard.

 

[Icewynd]

Now Balls that have a Skip greater than the Median, surely the Standard Deviation would be useful in picking numbers eg if Ball Skips isgreater than the Median + Standard Deviation the ball is overdue and could be a possible number to pick.


Wish I was a Mathematical Statistical Wizard.

Sounds like a good theory Doug! Why don't you try it out and let us know? I once did a post about using average skip to predict when a long out ball would fall -- kinda the same idea. I'll have to see if I can find it and post the link.

Mathematical Statistical Wizard, LOL! This is me in my Wizard hat!

 

[jack]

Hello, ice, help me in this here
* I will separate the 6 endings of 49/6 into two groups
* 3 digits
* example
10.16 26.34 48 50 0,6,6 4,8,0 = 066 480
after
Most = 2
* Minor = 1
Same = 0
* So we have 27 formations of 100% type pick3 group
* But the 27 pose be filtered. Going for a 20 formations
0 0 0
0 0 1
0 0 2
0 1 0
0 1 1
1 0 2
0 2 0
1 0 2
0 2 2
1 0 0
1 0 1
1 0 2
1 1 0
1 1 1
1 2 1
1 0 2
1 2 1
1 2 2
2 0 0
1 0 2
2 0 2
1 0 2
1 2 1
2 1 2
2 2 0
2 2 1
2 2 2

 

[jack]

example
* Base always last draw
* 453
* If you choose to 221
The 1st position we = 5,6,7,8,9 6,7,8,9 in 2nd place and 3rd 0,1,2
Because it is greater than 221, greater and lesser 1

 

[TheConcept]

Thamks for the reply, much appreciated. From a quick look through the Lotto Results for Saturday Draw here in Sydney a lot of the numbers drawn fall below the Medion.

Now Balls that have a Skip greater than the Median, surely the Standard Deviation would be useful in picking numbers eg if Ball Skips isgreater than the Median + Standard Deviation the ball is overdue and could be a possible number to pick.

I'll be interested in how you get on with this too.

However, in my experience so far, I'm finding that numbers above the median are more likely to be on long streaks, e.g. all numbers that are not only overdue, but well overdue will be found there.

If one treats the median as 50%, then one could consider this pattern for a 6/49 lottery, with a median of 5 draws

- 50% of balls once drawn should reappear in the next 5 draws (skips 0-4)
- the next 25% of balls once drawn should reappear in the next 5 draws after that (skips 5-9)
- the next 12.5% of balls once drawn should reappear in the next 5 draws after that (skips 10-14)

(adding 5 draws each time and halving the percentage each time)

So looking at the numbers in groups like this may be more of an advantage?

In the past, I used to look at numbers in each skip position and if the expected number of balls was more than one less than the number of balls in that position, then I would consider them. That is when I noticed that individual numbers, or groups of two or more numbers would drift through, and for numbers above the median, you could be waiting a while for any of them to hit. Meanwhile, they bias your selection, because they keep on coming up.

 

[jack]

Hello ice, in the case one can use the median, you can use the last draw
* As a reference or base as average as the central point of a graphic
Highs and lows (elecardiagrama) to ssim not walk in circles, being the last draw, the point
* The median, the next drawing are thrown more or less at each position in the vertical
* Ice, you can create an algorithm to 60/6, where it will use the last draw
* As average factor to calculate, larger or smaller numbers in each position ?? please