How to predict a very cold number (longhot)

[sangoma123]

Hello friends:

I am looking for a method to be able to select a "longshot", (it is to say, a number that takes more than 10 drawings without appearing), with enough safety.

They are numbers very complicated to predict, so they are a lot of time without appearing, it is not known well when they decide to do it.

In this forum I read some time ago a post it brings over of a so called method
" Side by Side ", which is good, but that gives several numbers.

I would like that with only two numbers, to guarantee that one of this two longshots would appear.(although not in all draws)

Thanks

 

[Icewynd]

I personally like the 'side x side' method, most often it gives you 3 numbers or 2 numbers, sometimes 4 numbers.

If you only want to play 2 longshots, start with a list of all 49 numbers (or however many there are in your lottery) and start marking off the numbers that have been played, starting with the most recent draw and working backwards until you are left with only 2 numbers out of 49 that have not been played recently. It takes quite a while to get all 49 numbers out -- you will have to go back an average of 32 games.

Play the two numbers -- about half the time one of them will hit within 3 games. I wouldn't chase them too long, though. Sometimes these numbers can be stubborn and refuse to come out for 15 or more games! If neither number has hit after, say, 4 or 5 games, I would start the proceedure over to find 2 new numbers.

Good luck!

 

[sangoma123]

Hello Icewynd:

The first thing, thank you very much for your interest to answer my mail.

The method that you say to me, I know it approximately two years ago.

I have used it in two variants:

1) The one that you say to your me, from the 1 to 49.

2) There is the second variant in which the numbers finished in 8,9 and 0 are not in use. I have used both methods, but they are slightly effective though if they succeed occasionally and very bored of doing manually.

It is possible that there are programs to make it automatic, but I did it to hand, and is a bit boring. Anyhow, thank you very much again for your interest.

It isn´t a bad method to considering.

Regards

 

[sangoma123]

Hello Icewynd:

Can you to explain me since do you apply your strategy side b side, in my case in a game type 6/49?

It is that to my way they go out about 4 to 6 numbers(or more), and can that this I doing something badly.

Regards and thanks

 

[jack]

Hello, sangona123, a number not? But twelve numbers!! In other words, you have divide into 4 groups, can scramble these 4 groups as you like if it is a 6/49 lottery,
A group will have 13 numbers, good sangona 123, that is how this standard is 100% a group
Always have zero or a number, and another group will have two or more numbers, this standard is 100%, then in the group that has zero or one if you play two numbers, will make mistakes and in the group that has two or more if you play a number will make mistakes too, so answering how to take
A group of 12, has to do in 4 editions, i.e. take a group, because it is not known which group will be out, you can make this simulation is 100% in any future sweepstakes, will be working with 4 rows of 36.37 numbers, one of the 4 lines will have 5 to 6 number in 100%
Any raffle, can be seen in 3 to 4 late line contests, or a drawing to another does not repeat aligns example, if in the last draw gave aligns 3 next game not to line 3,

 

[sangoma123]

Hi jack:

You and your four groups again...

Thanks for your interest

See you later

 

[Icewynd]

Hello Icewynd:

Can you to explain me since do you apply your strategy side b side, in my case in a game type 6/49?

It is that to my way they go out about 4 to 6 numbers(or more), and can that this I doing something badly.

Hmmm, my reply from yesterday seems to have disappeared...

I use the side x side strategy when two (or more) numbers have both been out for 15 games (i.e. they hit together 15 games ago and neither has hit since). I play these numbers for 4 games (16th through 19th games). About half the time one or two of the numbers will hit.

You can also search for information on the ISOLATOR (I suspect you have already read this information). Here, you take the list of 49 numbers arranged in a grid of 10 X 5 (with the top left cell empty, since there is no zero in the game), like this:
1 2 3 4 5 6 7 8 9
10 11 12 13 14 15 16 17 18 19
20 21 22 23 24 25 26 27 28 29
30 31 32 33 34 35 36 37 38 39
40 41 42 43 44 45 46 47 48 49
You can drop the 0, 8 and 9 digits from each row to make this move faster. Then you mark off the numbers as they are played until you have only two numbers remaining in any row. Play this pair for 2 games and about half will hit, about 10% of the time you will hit the pair.

Hope this helps.

 

[jack]

Hello, sangona, when you notice the pattern, the 4 groups will understand, is how that history of afric where fall more pebbles the sector that more had to Johannesburg or not
Sangona, ne not next draw of 49/6 has a group of 12 numbers which will give zero or a number, and I play two it'll lose, so why go against a mare (the tendency of accumulation of number numgrupo) for not being that can control these range from the Group
In another way, with rotating formulas, make some simulations to see this group reducer, we are looking for 80% standards 100% of the time the numbers of each draw, sangona another pattern when seen on the order of draw is so in other words, the number 49
Can be in 1st position, is in order of drawing of lots, always hpa a range of 17 to 20 number intervals without repeating a couple other draw looking vertically, sangona we need
Some 7 to 8 patterns to give confidence to bet then first 80% defaults to 100% after the filters defined patterns, then this number or not, in
About the 4 groups is the best way to give accumulation in the group, and take advantage of this standard
Then the basis is the setting of the amount of numbers drawn in each group, but we do not yet have a good formula for rotating this we must create this gearbox in our favor,
Good, sangona as it is not known which group take we must play in 4 editions, taking a group or take a group is to continue playing until the group stay out, sangona
Guess why the symbol of windosws is 4 quarters!!!! or excel 2010 symbol
Is exactly the mirror that I speak

 

[sangoma123]

Hello Icewind:

Yes, it is true, my post of yesterday also has disappeared.

Thank you very much for your response.

Yes, your method of side+side is similar to mine. The difference is that you use it with absent numbers 15 drawings, and I with absent numbers 10 drawings.

Thank you very much for your detailed response.

Regards