How many training in 14 games in 4 markers?

J

jack

Member
How many training in 14 games in 4 markers?
So we have 14 rows column 1 middle column and columns 2 (1x2)
Where only one marking is considered
We have 14 lines in 4 markings, how many are possible and what are they?
Combine the amount of column 1 and column 2 the column of the medium that is in green is the reference does not enter the combination
Objective = is to use the two end columns, the middle column is not used in the calculation
* The macro has to do automatic when you choose the marking amount of each column
* Ex = I choose 5 markings in column 1 and 4 markings in column 2
The macro has to calculate how many combinations from 1 to 14
5 in column 1 and 4 in column 2
 
Frank

Frank

Member
I know Im going to regret asking this question, but as usual it is very unclear what you are asking for.

Keeping it SIMPLE.

1. Are you asking for a macro to count how many RED cells there are in each of columns B and D ?

YES or NO ?





2. What do you mean by COMBINATIONS ? Do you mean if there are 5 reds in column B and 4 reds in column D then multiply them together to make 20 combinations of highlighted cells over 2 columns??

Or do you mean 5 from 14 =COMBIN(14,5) (in column B) AND 4 from 14 =COMBIN(14,4) (in column d)
so answer = COMBIN(14,5) x COMBIN(14,4) =2002 x 3003 = 6012006 ?

PLEASE KEEP YOUR REPLY SIMPLE !!
 
J

jack

Member
hello, ok frank, thanks, for viewing the post?
* it's for soccer lottery, I'm not going to use the middle column, this will be out of the study
* I need a field where the in macro
* example digit 3 sets in column one and 6 sets in column
* note
if the 3 sets of column one
is of the games 1,5,13, obviously in column two can not have
* maration in games 1,5,13, because it is only a mark, and you are,
another example I choose 6 games in column one and 4 in column two, the macro will make the game from 01 to 14 of each column
what is your doubt ? please
 
Frank

Frank

Member
1. Are you asking for a macro to count how many RED cells there are in each of columns B and D ?

YES or NO ?

ANSWER THIS QUESTION !!!!!
 
J

jack

Member
Hello, Frank, when you opt for 4 games in column 1 and 3 games in column 2
* Obviously in the middle column we will have 7 games these 7 games maximum
* Up to 3, followed, we can define the middle column as the base.
* Frank, or important point, is to see the markings of the last lottery test
* We can use up to 5 equal marks from the last draw, so we can play dry there
* Ex = repeated the last markings in 5 games
Game = 1,5,8,12,13 these games will be dry, (good for games in europe)
So you do not know which maraçoes will repeat, does 14 by 5 = 2002 arrays
* For the dry, one of them will hit
* Frank, I think you're going to hit the sports lottery in Spain and England, soon
* And go on an island paradise, sunbathing, you can put your considerations!
 
J

jack

Member
HELLO, YES, YES CORRECT
1. Are you asking for a macro to count how many RED cells there are in each of columns B and D ? YES, YES CORRECT
 
J

jack

Member
link link does not have this sum
* You have the sum of column 1 and column 2
* the middle column (x) would be out
* frank the link plan, was an example, you can put
* your ideas to improve, in the question repetitions of the last draw, delays, so the lottery would be treated with numbers,
* but if you play a double in a favorite game
 
J

jack

Member
Frank, you have to go to the draws tab below.
* To add column 1 and column 2,
* When placing new sweepstakes the macro will automatically make the sum
You can change the plan as you see fit.
 
Frank

Frank

Member
Sorry I havent got the slightest idea what you are doing. Hopefully some body else on the planet will understand you. I don't

I'm out.
 
J

jack

Member
let's deal with the soccer loterry also in this part in numbers as if it were 42 tens for a hit of 14
*markings that repeat from the last to the next
target = use as fixed


*the groups = pi ip iip pp, there are the pairs but so we go in 4 as if 4 quandrants
pi = 05,09,23 ...
11 = 15,19,31 ....
ip = 16.18 ..
pp = 02.08, ...

and also the left and right diagonals in a draw (objective is to filter bets at most a diagonal)

diagonal in red and diagonal and has the left also

duvidas_diag.jpg

another, divide in 4 quadrants without the middle column (the results of the middle column do not enter

*objective is to have a reference column in the case of the

then divide = into two parts = left side 7 right side 7

*and from below

*equal

The objective is to see the cards per quadrant

last draw gave

1st quadrant = zero

2nd quadrant = 5

3rd quadrant = 5

4th quadrant = 2

*suit = 0,5,5,2 in the order 1º 2º 3º 4º

the markings or the result of the column does not enter in the suits by is column reference

let's assign = 7 letters = ABCDEFG (where we have 7 games from each quadrants)

objective is to see the quantities of each letter in the 4 quadrants the 7 letters are the same in the 4 quadrntes

*objective is to see

*ex = no lottery letter A = HAD 2 MARKINGS letter b = zero (when it is zero means in the 4 quadrants where each one has the letter A NOT HAD MARCAÇAO.assim not bet by times but by numbers,
 
J

jack

Member
hello, hey! frank, in the study, I'm not taking into account the teams' names, but yes
from 01 to 42 in 14 games
 
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