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[rubronegro]

In a 49 draw try the following stategy. Assume the confident interval for the first, second, third, fourth fifth and sixth positions. Assume the confident gap bettween the first and sisth, the second and fifth and the third and fourth positions. It will give you a system of 3 equations and four unknown. Guess each of the positions inside the confident interval and check if the sum of the six numbers falls into another confident interval. That will allow you get rid at least 29 nunbers.

 

[Beaker]

much better in the 'Tips Strategy' forum.

This will get lost here

 

[thornc]

Copied to tips section!!

hehe, beat you to it sheba!

 

[LT]

Welcome to the forums rubronegro

I don't know Portuguese but I think the correct salutation is brigardo with a thumbs up? - thornc please help me out on this one if I haven't got it right.

From Brazil? ... one of my favourite places on the planet.

 

[thornc]

thornc please help me out on this one if I haven't got it right.

Almost it's "obrigado", but you got close enough!! In a conversation no one would notice the difference
!

 

[LT]

oh ... now I remember thanks a lot thornc

 

[Sheba]

Copied to tips section!!

hehe, beat you to it sheba!

You can have the job...

Sheba__ ~~~
Everybody's Got a Dream...JACKPOT!
----------------------------------------------------------------------

 

[stakar]

In a 49 draw try the following stategy. Assume the confident interval for the first, second, third, fourth fifth and sixth positions. Assume the confident gap bettween the first and sisth, the second and fifth and the third and fourth positions. It will give you a system of 3 equations and four unknown. Guess each of the positions inside the confident interval and check if the sum of the six numbers falls into another confident interval. That will allow you get rid at least 29 nunbers.

Very insteresting!!
Why dont you give us the idea using an example with a draw ?? I think it will be more specific this way.
Awaiting ....

Stathis

 

[globalgranby]

Hi

Can you explain in sample language how to discard 29 numbers? IF it's a formula, please explain.

I'm here to study your logics. So don't go to fast please.


God bless you all !

 

[Matrix]

Does anyone get them?

Does it really work?

After researching several days, I do not think they are really work.

I think they are unreasonable.

How about you?

 

[tomtom]

In a 49 draw try the following stategy. Assume the confident interval for the first, second, third, fourth fifth and sixth positions. Assume the confident gap bettween the first and sisth, the second and fifth and the third and fourth positions. It will give you a system of 3 equations and four unknown. Guess each of the positions inside the confident interval and check if the sum of the six numbers falls into another confident interval. That will allow you get rid at least 29 nunbers.

This was suposed to be a joke of the joke of the day,eh…Actually, it was a good one....