Hello, Frank, okay, thank you very good job, conglatulations

You'll need third grade math to get the reference point.

Add the lowest sum ..... 21

To the highest sum ..... 345

1 + 5 = 6

2 + 4 = 6

bring the 3 down.

This equals 366

366 divided by 2 (two because you added two numbers) Which equal 183.

*

Alternative method ....

Add the sum of all sets and 50,063,860 divided by 50,063,860. If you do it this way you can chart Them While You work.

Frank you can do donate Numerous even and odd. make separate sums, like two lotteries the even and odd numbers. Then we have two sums in general

* And even and odd, and further sum positional

Eexemplo the most = 4/2 and 3/3 odd / even

In two positions, 6x2 = 15 and 6x4 = 20

* example

12,15,18 25,37 49 = odd = 15,25,37,39 numbers in positions = 2nd 4th 5th 6th pairs 1st and 3rd

6x4 posicioes are 20 = 1,2,3,4 1,2,3, 5,,,,,,,,,,, to 4,5,6,7, = 20 positions

* Of course the left is pairs. And vice versa provided 4/2