wazzappenning
Member
ok so last nights wclc pick 3 was 230. the one before that was 396. so i take 396 and use each number(+or- 1) . so the numbers from the 3 are 234, from the 9 are 091, from the 6 are 567. ok? now the numbers from each digit can only be used in one or two of the spaces for your combo(ottherwise you end up with almost a full spread of possible combinations.)so the total amount of combinatons i get is 27x7 =? ( 27 being the combos if the numbers from each digit was used only for one digit in your final combos) or 3x3x3. AND that would only be playing box or straight/box. to play it as a straight and cover all the combos would cost way too much.so my 3 covered the 2 and the 3 and my 9 covered the 0 in last nights draw. check this on your local pick 3 and see if its any good...seems to work really well in wclc for the moment...also i dont like 6 or 9 cause ive noticed sometimes you have to flip them (9 becomes 6 and 6 becomes 9) so you end up with more numbers to play around with(bottom line more combos)and sometimes you do have to use both.