savagegoose
Member
The Australian game super 66, picks 0-9, 6 times in order.
it actually pays
nnxxxx or xxxxnn $6.66
nnnxxx or xxxnnn $66.66
nnnnxx or xxnnnn $666.66
nnnnnx or xnnnnn $6,666.66
Where n is a hit,. all 6 in correct order pays the pot, usually, $66.666 or something lame, but then jackpots if it isnt won.
the recent prizze of $1mill for all 6 correct is a promotion, and i have no idea when it will end. but this is my plan of attack.
im thinking of playing 10 tickets as 2 x5 ticket with 0-9 as the 1st and last kind of like this
1nnnn6
2nnnn7
3nnnn8
4nnnn9
5nnnn0
and
6nnnn5
7nnnn4
8nnnn3
9nnnn2
0nnnn1
this way i am guaranteed of getting at least the 1st and last number, and having a chance at the lowest prize of $6.66.
the entry form has option to randomly pick the numbers you leave blank, so i would leave the middle 4 blank and just pick my 1st and last numbers.
i will always match a 1st and last, so there will be a %20 chance i also get the 2nd or 4th meaning a $6.66 win. and of course the 10 sets i have chose are in the pool for the top prize, of course that exact set isnt required, i could play any order of 0-9 as 1st and last. thats just a clear example. it actually cost $10.80 to buy. i bought 10 games with random picks and then thought this up when I failed to match the 1st number.
it actually pays
nnxxxx or xxxxnn $6.66
nnnxxx or xxxnnn $66.66
nnnnxx or xxnnnn $666.66
nnnnnx or xnnnnn $6,666.66
Where n is a hit,. all 6 in correct order pays the pot, usually, $66.666 or something lame, but then jackpots if it isnt won.
the recent prizze of $1mill for all 6 correct is a promotion, and i have no idea when it will end. but this is my plan of attack.
im thinking of playing 10 tickets as 2 x5 ticket with 0-9 as the 1st and last kind of like this
1nnnn6
2nnnn7
3nnnn8
4nnnn9
5nnnn0
and
6nnnn5
7nnnn4
8nnnn3
9nnnn2
0nnnn1
this way i am guaranteed of getting at least the 1st and last number, and having a chance at the lowest prize of $6.66.
the entry form has option to randomly pick the numbers you leave blank, so i would leave the middle 4 blank and just pick my 1st and last numbers.
i will always match a 1st and last, so there will be a %20 chance i also get the 2nd or 4th meaning a $6.66 win. and of course the 10 sets i have chose are in the pool for the top prize, of course that exact set isnt required, i could play any order of 0-9 as 1st and last. thats just a clear example. it actually cost $10.80 to buy. i bought 10 games with random picks and then thought this up when I failed to match the 1st number.
