18 number system

[GameBelgium]

Hello everyone. This is my first post in the lotto649 forum. I've been following your posts from the background for some time now and I would like to start of by thanking everyone for their much appreciated input. After having read several books and ideas on the www, it's time for me to join in on the fun. So, with a couple of friends, we started playing in a (very modest) lotto club.

I have a small question about the system we're gonna play. We've agreed to play with 18 numbers, in a 6/42 lottery. The 18 numbers we're playing are distributed in 6 groups of 10 numbers, each group containing 10 of the 18 numbers we're playing. In each group of 10 numbers, we're playing 10 combinations of 6 numbers (10 x 0,5 EUR = 5 EUR /group of 10). This system has a weekly cost of 6 x 5 EUR = 30 EUR.

Now here's the million dollar (I wish!) question: how can I allocate the 18 numbers we've chosen into 6 groups of 10 numbers most effectively (most combinations of 6 possible)? Is there software that can help me with this? Or can some of the smart people on this forum that can tell me how to do this?

If I notice that the system is working (regular small gains, and hoping for the big one of course), I don't mind sharing it with you guys here on the forum. Thank you very much in advance!

 

[blitzed]

Hello GameBelgium,

You can play 19 numbers in 60 combinations which offer a base guarantee of matching 3, if 3 of the 19 numbers are in the draw.

If your pool of 19 numbers has more than 3 draw numbers, then you already have those 3 match foundations for chances to build a better match upon

Perhaps this wheel template will do the trick for your lotto club:
http://www.ccrwest.org/cover/t_pages/t3/k6/C_19_6_3.html

cheers!
blitzed

 

[blitzed]

or if you feel brave, you can play three 10 number 20 combination wheels.

10 number 4if4 in 20 combinations:
http://www.ccrwest.org/cover/t_pages/t4/k6/C_10_6_4.html

cheers!
blitzed

 

[GameBelgium]

Thank you for the quick replies Blitzed!

We've already selected a wheeling system: 10 numbers, 5 if 6.

The only problem we have: how can we most effectively arrange 18 numbers into 6 groups of 10 numbers? Example (probably bad):
Group 1: 1 2 3 4 5 6 7 8 9 10
Group 2: 11 12 13 14 15 16 17 18 1 2
Group 3: 3 4 5 6 7 8 13 14 15 16 17
Group 4: 1 2 9 10 11 12 17 18 5 14
Group 5: 1 2 3 4 5 14 15 16 17 18
Group 6: 6 7 8 9 10 11 12 13 14 15

What do you guys think?

 

[blitzed]

hi GameBelgium, you are most welcome.

5if6 out of 10 is a longshot, very unlikely to have 6 numbers in 10.

4if4 out of 10 is more realistic, the 3if3 in 19 even more so.

you should run back testing to compare performance of the 3 types of wheels.

groups your sets of 10numbers by using a pick10 2if2 wheel...this is close, 19 numbers in 6 combinations of 10:
http://www.ccrwest.org/cover/t_pages/t2/k10/C_19_10_2.html

otherwise 18nums in 5 combos of 10, then arrange 6th group yourself:
http://www.ccrwest.org/cover/t_pages/t2/k10/C_18_10_2.html

cheers!
blitzed

 

[blitzed]

this wheel is another option...4if6 in 18numbers, 42 combos:
http://hem.bredband.net/b599956/Lotto-Wheels/full/wheel/pick6/0406/040618.txt

cheers!
blitzed

 

[GameBelgium]

Quote from Blitzed:
5if6 out of 10 is a longshot, very unlikely to have 6 numbers in 10.


I agree with you 100%, that's why we decided to play 18 numbers. You see where I'm going with this idea? But that brings me back to my basic question: how do I arrange the 18 numbers in the 6 groups of 10 in the most effective way. The tip about the 5 groups was close but what's the guarantee of that wheel?

Side note: We actually play 2 x 18 numbers, that's a total of 36 numbers from the 42 in the lottery. It happens a lot that we capture the 6 winning numbers in the 36 numbers. The trick is to capture them in one group of 18 numbers, which, logically, happens a lot less.