C(42,2,2,3) Wheel can anyone help?

vibrazy

Member
:hair: Hya everybody,

I was wondering if anyone could help me with a number wheel!

I would like to play the Irish lotto online, the lottery have 42 numbers + 1(bonus).

If you match 2 numbers correct you get £30 pounds.

Can anyone suggest any number wheel that would be the most profitable?

- C(42,2,2,3)
- C(41,2,2,3)
- C(40,2,2,3)

------------------------
Another quick question

I've found this wheel in Weefs Lottosystem
http://www.weefs-lottosysteme.de/systeme,3,4203,en.htm

C(42,2,2,3)=94

1 3 7
1 4 27
1 9 24
1 10 39
1 11 14
1 16 36
1 37 42
1 38 40
2 6 34
2 6 42
2 13 37
2 15 35
2 19 25
2 21 22
2 23 32
3 4 9
3 10 27
3 11 39
3 14 36
3 16 40
3 24 38
4 7 40
4 10 38
4 11 16
4 14 39
4 24 36
5 8 30
5 12 17
5 18 29
5 20 41
5 26 28
5 31 33
6 13 23
6 15 21
6 19 35
6 22 25
6 32 37
7 9 39
7 10 16
7 11 24
7 14 38
7 27 36
8 12 29
8 17 41
8 18 33
8 20 28
8 26 31
9 10 36
9 11 27
9 14 40
9 16 38
10 11 40
10 14 24
11 36 38
12 18 30
12 20 33
12 26 41
12 28 31
13 15 32
13 15 42
13 19 34
13 21 25
13 22 35
14 16 27
15 19 23
15 22 34
15 25 37
16 24 39
17 18 26
17 20 30
17 28 33
17 29 31
18 20 31
18 28 41
19 21 37
19 21 42
19 22 32
20 26 29
21 23 34
21 32 35
22 23 37
22 23 42
23 25 35
24 27 40
25 32 34
25 32 42
26 30 33
27 38 39
28 29 30
29 33 41
30 31 41
34 35 37
34 35 42
36 39 40

Could anyone improve that wheel?

Any help would be much appreciated.



Thanks:thumb:
 
Hello Vibrazy,
the wheel C(42,2,2,3)=94 is a partial one.
the complete wheel is 420 tickets.
If you are interested for the complete one
you can create this by dividing the 42 numbers
in 2 groups of 21 nums each.
All you have to do is to make the dyads of each
group.
Having 2 groups of numbers and 3 winning nums
the possible cases are:
group a: 3 nums group b:0 nums
group a: 2 nums group b:1 num
group a: 1 num group b: 2 nums
group a: 0 nums group b:3 nums.
The dyads of 21 nums are (20*19)/(1*2)=210
and for both groups 210+210=420.
Following the same way you can create the other
systems you mentioned above.
 

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