I've been crunching same as everyone else and I'm trying to nail down a stratedgy....and thought i would run it by you guys....

and see what we come up with..

From the data I've seen for ontario pick3 there is a 50% chance that any 1 of the last 3 drawn numbers will show up in the next draw. This is true historically speaking. Also I ran a test and found that there is a 75% chance that any 1 number drawn from the last draw will show up within 2 draws.

The problem lies in that you still have a 30% chance to guess the right number out of the three drawn numbers....when i ran a test and just choose the first digit i lost more time than won.

But if you chose 2 numbers out of the 3 you would have a 66% chance you chose correctly and if you ran the combinations for it for no more than 2 draws 75% of the time on average you'll win....

That being the case and there being 1000 combinations would that mean that each number only has 100 possible combinations...I don't think so cause as i study the sequential numbers....there is 100 combos with 0 digit in number 1 spot and then even more for the second spot etc for each number 1-9 so does that mean there are 1000 combo's for each numer to fall in any slot?

I trying to work out a way to lessen the possible combos given this occurance fact and see if there is a way to bring it down to 100 combos or so...

questions...theories...flames etc to this strat..?

Troy