Lets try this again!
I came across something rather interesting elsewhere on the web. The author was summing the last 3 results to give an indication of what might come up next. For example, consider the last 5 results for Lotto 6/49:
31-12-2016 3 5 14 18 26 28 (40)
04-01-2017 2 11 13 23 35 48 (30)
07-01-2017 1 10 18 19 23 27 (48)
11-01-2017 24 34 36 38 42 43 (30)
14-01-2017 1 6 19 30 32 44 (33)
For position 1 we have 3+2+1=6, followed by 2+1+24=27 and, most recently, 1+24+1=26. For the next result the sum will be 24+1+?=>26.
For P1 the sums have ranged between 3 (3 1's in a row) to 63 with 80% of the results falling between 10 and 35.
So what we can do is plug in various values for P1 to see what kind of sum this gives us. For example, if we guess that P1=1 then that will give us 24+1+1=26. This is the same as the previous sum, which only happens about 3% of the time, so I would eliminate 1.
Another way to look at this is to check the Delta value (change) between the current and previous sums. So, 27-6=21, 26-27=1. These deltas cluster at the low end, with 50% being between 1 and 5. The same delta value only hits 7% of the time, so less likely that we will get another sum=26 (P1=1). The deltas are calculated in absolute differences (plus or minus doesn't matter, only change). For P1, however, we can't go lower than 1, so possible values for the next draw would be sums of 27,28,29,30 or 31 or P1 values of 2,3,4,5 or 6. We have a 50% probability of hitting one of these.
A P1=6 (or sum 31) would be at the 85th percentile of the distribution, which is high (but possible) so I might go with a P1 value of 2-4.
We will see tonight!