Now I have the time to take care of this Quebec-49 that had been kicking me so hard lately, so I develop some strategies that will payoff handsomely, first of all I make a number selection with 22 numbers that had been draw in the last 11 draws, I eliminated the 7 numbers draw last Wednesday and add 12 and 48 because historically are the numbers that has show up the most, a total of 24 numbers. Then I create a Conditional Wheel.
1 wheel 24 numbers, 4 bankers of 3 numbers, 12 numbers to mix, 44 combinations.
1 wheel with the 4 banker numbers together, 6 combinations.
1 wheel with the 12 mix numbers, 6 combinations.
04 12 21
17 30 48
15 26 33
10 40 43
03 11 13 16 18 22 29 31 39 46 47 49
The matrix (to play the 49 numbers always fascinated me) there for I took the numbers 45 and 35 very cold at this moment and create 2 pairs together with the historical super winners 12 and 48 and play the rest of the numbers, since I have to pairs (12, 45) and (35, 48) I achieve the matrix twice; am I allow to win twice too?
The 12 and 45 matrix.
01 12 24 26 42 45
02 06 11 12 19 45
03 12 16 23 28 45
04 12 17 44 45 47
05 12 29 32 34 45
07 12 22 39 43 45
08 12 33 45 48 49
09 12 14 21 27 45
10 12 19 20 45 46
12 13 15 18 30 45
12 25 31 36 40 45
12 35 37 38 41 45
The 35 and 48 matrix.
01 08 17 35 44 48
02 19 31 35 43 48
03 35 37 38 40 48
04 10 21 33 35 48
05 24 30 35 45 48
06 12 23 35 46 48
07 15 29 34 35 48
09 16 25 35 42 48
11 13 32 35 48 49
14 35 36 41 47 48
18 22 28 35 39 48
20 22 26 27 35 48
The final total cost of all combinations is $40. I should be a winner Saturday Night. Babar
1 wheel 24 numbers, 4 bankers of 3 numbers, 12 numbers to mix, 44 combinations.
1 wheel with the 4 banker numbers together, 6 combinations.
1 wheel with the 12 mix numbers, 6 combinations.
04 12 21
17 30 48
15 26 33
10 40 43
03 11 13 16 18 22 29 31 39 46 47 49
The matrix (to play the 49 numbers always fascinated me) there for I took the numbers 45 and 35 very cold at this moment and create 2 pairs together with the historical super winners 12 and 48 and play the rest of the numbers, since I have to pairs (12, 45) and (35, 48) I achieve the matrix twice; am I allow to win twice too?
The 12 and 45 matrix.
01 12 24 26 42 45
02 06 11 12 19 45
03 12 16 23 28 45
04 12 17 44 45 47
05 12 29 32 34 45
07 12 22 39 43 45
08 12 33 45 48 49
09 12 14 21 27 45
10 12 19 20 45 46
12 13 15 18 30 45
12 25 31 36 40 45
12 35 37 38 41 45
The 35 and 48 matrix.
01 08 17 35 44 48
02 19 31 35 43 48
03 35 37 38 40 48
04 10 21 33 35 48
05 24 30 35 45 48
06 12 23 35 46 48
07 15 29 34 35 48
09 16 25 35 42 48
11 13 32 35 48 49
14 35 36 41 47 48
18 22 28 35 39 48
20 22 26 27 35 48
The final total cost of all combinations is $40. I should be a winner Saturday Night. Babar
