I'm not sure if "permutation" is the same as "wheeling", but for this discussion I will assume it is. If I'm wrong, I'm sure someone will let me know.

Anywho, I came across a website a while ago that sells different permutation's for different lotteries. On his site, his lists his 5 number permutation for Pick 3. (pick 5 numbers from 0-9 and put them in to his formula and if 2 numbers from the 5 you picked are drawn, the formula will supply the 3rd number). I've tried it out on paper and it does what it says as long as atleast 2 numbers from the 5 you picked are drawn.

My question is, he sells permutation's for pretty much every lottery and you can purchase his 6 number pick 3 permutation for $9.99 up to 9 numbers for $30. The problem is, with the 9 number system, you have to play 84 lines which does not include doubles. Is there a better way to perm pick 3 numbers? Someone may have posted the formula on here already and I may not have realized what I was looking at. It that's the case, sorry for not noticing it.

I think I've rambled on enough, thank you everyone for your time.