need some info 6/49 GAME playing 12 numbers

[henryc]

Good Pm I just want to know If I play System 12 Play or Wheeling System on a 6/49 lotto game without bonus number then I play for 12 numbers....
example

8, 29, 30, 39, 49, 7, 03, 21, 37, 41, 12, 19

Then for example if all six (6) of the winning numbers are drawn

How many combinations will i won

6 of 6=
5 of 6=
4 of 6=
3 of 6=

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Then if only five (5) out of 6 are drawn

How many combinations of
5 of 6=
4 of 6=
3 of 6=
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Then if only four (4) out of 6 are drawn

How many combinations of
4 out of 6=
3 out of 6=
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Hope someone could answer this question

Sorry for my bad english

 

[henryc]

I already find it

IF I PLAY SYSTEM 12 BET THE AMOUNT OF MY INVESTMENT WOULD BE 924 X P20 = P 18,480 PER DRAW

MINIMUM JACKPOT 16,000,000 AND WILL INCREASE IF NOT WON

IF 6 OF 12 NUMBERS I PICK ARE DRAWN
6 of 6 or jackpot = 1 X JACKPOT PRIZE = 140,000,000.00 (ESTIMATED JACPOT TODAY)
5 of 6 or 56,000 = 36 X P56,000 P 2,016,000
4 of 6 or P1,000 = 225 X P1,000 225,000
3 of 6 or P 100 = 400 X 100.00 40,000 2,281,000.00
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142,281,000.00

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IF 5 OF 12 NUMBERS I PICK ARE DRAWN
5 of 6 or 56,000 = 7 X P56,000 P 392,000
4 of 6 or P1,000 = 105 X P1,000 105,000
3 of 6 or P 100 = 350 X 100.00 35,000 = 532,000
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IF 4 OF 12 NUMBERS I PICK ARE DRAWN

4 of 6 or P1,000 = 28 X P1,000 28,000.00
3 of 6 or P 100 = 224 X 100.00 22,400.00 = 50,400
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IF 3 OF 12 NUMBERS I PICK ARE DRAWN

3 of 6 or P 100 = 84 X 100.00 8,400 = 8,400
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