# locate the formations of 5 distinct digits (without repetition) in the 21 possible positions in 100%

#### jack

##### Member
locate the formations of 5 distinct digits (without repetition) in the 21 possible positions in 100%
frank, it's a new super seven lottery, uses 7 columns
we have few draws because it is a new lottery,
the macro has to locate the formations of 5 different digits, always the first when there are repeated pairs, please
http://www.mediafire.com/file/fskfhldo42e9s8o/5_posi%C3%A7oes_em_7.xlsx/file

#### Frank

##### Member
locate the formations of 5 distinct digits (without repetition) in the 21 possible positions in 100%
frank, it's a new super seven lottery, uses 7 columns
we have few draws because it is a new lottery,
the macro has to locate the formations of 5 different digits, always the first when there are repeated pairs, please
http://www.mediafire.com/file/fskfhldo42e9s8o/5_posi%C3%A7oes_em_7.xlsx/file
This assumes that there are only 5 distinct digits in the results. The examples you give do only have 5 distinct digits but what happens when a result is 1234567 ? which 5 digits then?

Also How can a sequence of 5 distinct results (repeats always use the first) ever begin in the second column or begin in the third?
? Thats impossible! They ALWAYS start in column 1 because its the first number!

#### jack

##### Member
ok frank, thanks for viewing the post, it's a
new lottery (super seven brazil), ok the macro
you will always see the first 5 distinct digits
the probabilities of one or two pairs of repeated digits
singles> 584 5.84%
1 pair> 4312 43.12%
2 pair> 3269 32.69%
3 pair> 541 5.41%
other> 1294 12.94%
we have then that 76% we have one to two pairs of repeated digits, the macro to identify the first 5 digits in the 7 positions
example = draw 00001 = 2,9,9,8,7,7,6
the macro ignores the twin, and identifies the position of the first 5 digits =
1st 2nd 4th 5th 7th
2 9 8 7 6 = 2,9,8,7,6
frank since in 76% we have one or two doubles, we will stay, in this probabilities of 76%

#### jack

##### Member
What to do to get the 7 digits right when you already have the exact 5 digits in hand that will come out in the next contest at SUPER SEVEN?
will be keeping the repetition of two pairs, play until
appear the pattern because it is 76%, frank we have 21 positions of 5 digits transiting in the 7 positions
below is the 21 positions of the 5 distinct digits
1ª2ª3ª4ª5ª
12346 the other is just to put (ª) to indicate positions
12347
12356
12357
12367
12456
12457
12467
12567
13456
13457
13467
13567
14567
23456
23457
23467
23567
24567
34567

#### Frank

##### Member

Also How can a sequence of 5 distinct results (repeats always use the first) ever begin in the second column or begin in the third?
? Thats impossible! They ALWAYS start in column 1 because its the first number!

you cannot program an impossibility.

#### jack

##### Member
OK, FRANK!! I agree, let's use a reference, the 2nd column,

#### jack

##### Member
frank, well we have 5 distinct digits in 7 columns in over 90%
for 5 different digits we have 10x9x8x7x6 = 30,240
and we have 21 positions in the 7 columns, as we are going to cross the 30,240 formations in 100% with the 21 positions 100%, THESE TWO FILES I CAN
post ,, we have to find a way to filter the 21 positions and filter the 30,240 and then cross

#### jack

##### Member
franco, na sua pergunta, pois temos 21 posições, 1,2,3,4,5. 1,2,3,4,6 ..... 3,4,5,6,7 = 21 posições
eles transitarão sob as 7 posições, independentemente de onde o par repetido começa
você pode testar e ver, não importa onde o par comece, nas 21 posições é 100% verificado,

#### jack

##### Member
frank, it doesn't matter the positions when two pairs of digits are drawn
ex = 7761223here we have the formation of 5 distinct digits with the reference of the 2nd position 76123 in the positions 2nd 3rd 4th 4th 6th
frank using it as the 2nd position, so we already know which doubles too, wonderful

#### jack

##### Member
hello FRANK,
if you want to locate (when you choose to play two doubles you have 21 positions in 100% positional to double digits) as there will not be played equal doubles type = 00 00, then we have 90 doubles, type 0.1 0.2 or = 9.8 are 90 pairs and 21 positions all 100% since you choose to play two pairs

1ª2ª
13
14
15
16
17
23
24
25
26
27
34
35
36
37
45
46
47
56
57
67

#### Frank

##### Member
Please STOP posting more and more information that I'm not interested in. You just muddy the waters and make it less and less probable that anybody will bother to read it. You only had to answer ONE question. Ok you’ve answered it, so STOP now.

#### jack

##### Member
ok, sorry,FRANK, but it's just a few facets of locating under the 7 columns, the 5 positions
and the two positions, frank i will always choose to play two pairs of repetition digits, i will play until these patterns come out which are 76%, do not worry about combining other shapes just this pattern of two doubles

#### Frank

##### Member
Just show me an example of a 7 digit number and which 5 digits to appear, as below
1ª2ª3ª4ª5ª6ª7ª = ===2ª3ª4ª5ª6ª
? ? ? ? ? ? ? === === ? ? ? ? ?

#### jack

##### Member
I should clarify that when I say pair, that means the same digit can repeat in any position, as in 3804321 or 0774921.

#### jack

##### Member
7749122 =2ª3ª4ª 5ª 6ª 5 digits=74912

#### jack

##### Member
my game will always be two double digits and x = 4412355. 44.55 5 digits
without repeating 4,1,2,3,5
but frank look at the 21 positions of 5 digits
1,2,3,4,5 1,2,3,4,6 ...... 3,4,5,6,7 = 21 positions,
they position, their question the formation I gave their example, 2,3,4,5,6, she is there between 21,
the other 21 two-digit positions is the mirror
or that space that is blank in the 5 positions, you have in an excel header the 21 positions there everything becomes clearer

#### Frank

##### Member
What part of NO MORE INFORMATION did you fail to understand ????

#### jack

##### Member
ok ex = 5733411 = ????? = 2ª3ª4ª5ª6ª
1ª 2ª 3ª 5ª 6ª= 57341= 5 digits no repit

#### jack

##### Member
attention, I will only choose to play this pattern of repeating two twin pairs, neighbors in the positions
so we have the formations of 5 distinct digits
ex = xx 22 x66, I will not play games outside this pattern, only with pairs of neighboring digits
ex = 3x3 x4x4 = not like that I won't play
just together = ex = 33 xxx44 ok

#### jack

##### Member
frank, I am forced to choose a standard,
I will choose to use in my bets,
two double digits repeated, ex = 2995661
99, 66, or 00 11 etc but without neighbors
ex = 7266544 66 and 44, but then we have the rest
725, it will be a crack without repeating digits since we have
66 44 in 4 positions