GameBelgium Method

Ramijami

Member
Hi people,

New poster. Tx to Admin for registering me and providing access.

I saw a method by GameBelgium with regards to selecting lines from the last 20 draws with no matches which peaked my interest. In it he was trying to select 6 lines which will have no matches in the next draw, and I thought it should be easier as a starting point to select just 3 lines thus eliminating up to 15 numbers (in our 5/45 game) and up to 18 numbers (in the 6/49 game). The number of lines out in the 5/45 game for the last 10 draws were: 13,11,8,8,10,15,6,12,13,12, so between 6 and 15 lines with no matches at an average of about 10 lines with no matches. Any ideas/suggestions on how to choose 3 lines from the approximately 10 lines that won't have any matches?

Thanks :)
 

Icewynd

Member
Hey Ramijami,

Welcome to the forum! :wavey:

I also found Game Belgium's idea interesting and started to track the number of matches in each of the previous 15 draws in my 6/49 game. What I have found is that there is about a 0.6 probability of any of the previous 15 draws matching one or more of the numbers in the most recent draw. For any draw between 2 and 10 of the previous 15 will have matches to the current draw, with an average of 6.3 draws out of the prior 15 having matches.

Therefore, your chances of getting 3 no-matches would be 0.42 (probability of a non-match) to the third power, or 0.42 x 0.42 x 0.42 = 0.074. So you would be successful about 7 times in 100 draws, or about once every 14 draws.

However, even in the worst case scenario where all three of your picks had matches with the current draw, you might still only eliminate 3 of the drawn numbers, as one match with the current draw is the most common outcome.

Why don't you do some testing on prior draws to see how it would work out?

Good luck!

:thumb:
 

Ramijami

Member
Thanks Icewynd. Exploring the concept as a 3/20 game and using high/low, odd even filters etc. to get a possible strategy. So far the best I'm doing is getting a match in 5 or more sets. Trying to get a match consistently in 1-3 sets max. The last few draws have eliminated 11-15 numbers in the 6/45, and 12-18 numbers in the 6/49.
 

Icewynd

Member
Ramijami said:
Thanks Icewynd. Exploring the concept as a 3/20 game and using high/low, odd even filters etc. to get a possible strategy. So far the best I'm doing is getting a match in 5 or more sets. Trying to get a match consistently in 1-3 sets max. The last few draws have eliminated 11-15 numbers in the 6/45, and 12-18 numbers in the 6/49.

Hi Ramijami,

Not sure what you mean by 3/20 game -- are you trying to eliminate all but 20 numbers and hoping for a 3 match?

You might try searching this forum for "filters". I know PAB had a thread a while back on this board than explored a large number of ways to filter the numbers.

Good luck!

:thumb:
 

Icewynd

Member
Thanks for the explanation.

I had a thought about which games you might pick to have no matches with the next draw. We know that games in the previous 15 draws will have no matches with the current draw about 4 times out of 10 draws. So, I would pick games that have had a higher than average percentage of matches lately. For example, if the 5th prior game had matched at least one of the current draw numbers 8 out of the last 10 draws, then it would be a good candidate for a miss, to return to its expected average in the spirit of 'regression to the mean'.

Good luck!

:thumb:
 
Hi Ramijami

Picking 3 lines from 20 will give you a reduced amount of numbers to play. It will probably give you 13 to 15 numbers which you should not play in the next draw. However, in most cases, that will be all it gives you. If you want to use the information to further eliminate numbers and provide you with a limited pool of numbers containing the winning numbers, you will need to select more lines (if you think this through, it makes perfect sense, doesn't it?). I applied the principle to Euro Millions (a 5/50 lottery) and if I remember correctly, on average, 13 (!) lines from the last 20 draws contained no matches.

Anyway, let us know how you do and if you're succesful in selecting the 3 lines correctly on a regular basis, please share how you got there, and maybe we can make it a work in progress.

Best of luck!
 

TheWasp

Member
In my 649 lotto, I've found that typically there will be 23 lines from the last 72 draws that will not have the numbers that show in the next draw. This can vary from a low of 17 to a high of 27 and not always will it just be the next 7 numbers, it could be as many as 10. Of course, generating this set will produce a lot of numbers that qualify and I've found that one needs to include some other info about the last numbers to make it work to some degree of reliability.
 

Icewynd

Member
I did some further investigation into this problem.

What I did was divide the previous games into 3 groups: last 5 games, games 6-10 prior and games 11-15 prior.

I then counted how many of the 5 draws in each group had at least one match with the current draw.

The percentages were quite consistent across all 3 groups, as one would expect from a random distribution.

The most common outcome, occurring 33% of the time was that 3 draws of each group would have a match with the current draw, with the other 2 in the group having no match.

Next most common, occurring 28% of the time, was that 2 draws in each group would have a match with the current draw, with the other 3 in the group having no match.

Another 33% had 4 or 5 games from the group of 5 having at least one match, while the remaining 6% of draws had 1 or 2 games with matches from the group of 5 with the remaining 3 or 4 games in the group having no match.

Zero matches from a group of 5 draws were very rare.

So, if you deleted the prior 5 games, there is a 62% chance that you will delete 2 or 3 sets of numbers that will have one or two matches with the upcoming draw while 12 (2X6) or 18(3X6) numbers will be successfully deleted.

Only about 6% of the time you could delete the last 5 games and have only one game with a match (most often 1 match of six).

Good luck!

:thumb:
 

Ramijami

Member
Hi GameBelgium,

I haven't yet been able to successfully select the one 3 line set correctly yet on a consistent basis. In last nights 6/49 draw I got the 3 lines correct but in five sets. I'm also looking at eliminating 1 last digit, one rootsum and 1 decade as extra reductions of the numbers. I'm having some success using the date of the draw to eliminate the FD and rootsum, but struggling with the decade.
 

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