Hi all,
I am interested in exploiting one of the anomalies of the 6/49 game to reduce the numbers played – namely the fact that about 85% of games have one or more decades missing. If one can correctly predict these patterns one can eliminate 9 or 10 numbers from play.
One possibility that I have been looking at is the skip of the first decade (1 through 9). These numbers are missing in about 28% of draws. Further, we know that about 50% of such draws skip zero draws or one draw after the original occurrence. This would suggest a strategy of waiting for the first draw which started with the number 10 or higher (the trigger) and then to play the next two games.
A test of this method since the beginning of the Canadian 6/49 lottery identified 496 “triggers” which produced 282 occurrences of zero-decade draws in the following two games.
So far so good, but now I am faced with the problem of crafting combinations to take advantage of this. Almost 50% of the draws which were predicted successfully have only one decade (the zeros) missing, with a pattern of 11220 (34%) or 11130 (13%). What I mean by this is that one decade was missing (indicated by the “0”) and the other 4 decades had either 1 or 2 numbers in the first pattern, for example: 14-21-25-30-38-40, or 1 or 3 numbers in the second pattern, for example: 12-25-26-29-35-47.
So my problem is that I have 40 numbers which I want to use to produce combinations of the types described, that is containing one, two, or three numbers for the tens through fourties decades in two specific patterns.
Can anyone suggest how this could be done with an affordable number of combinations?
I am interested in exploiting one of the anomalies of the 6/49 game to reduce the numbers played – namely the fact that about 85% of games have one or more decades missing. If one can correctly predict these patterns one can eliminate 9 or 10 numbers from play.
One possibility that I have been looking at is the skip of the first decade (1 through 9). These numbers are missing in about 28% of draws. Further, we know that about 50% of such draws skip zero draws or one draw after the original occurrence. This would suggest a strategy of waiting for the first draw which started with the number 10 or higher (the trigger) and then to play the next two games.
A test of this method since the beginning of the Canadian 6/49 lottery identified 496 “triggers” which produced 282 occurrences of zero-decade draws in the following two games.
So far so good, but now I am faced with the problem of crafting combinations to take advantage of this. Almost 50% of the draws which were predicted successfully have only one decade (the zeros) missing, with a pattern of 11220 (34%) or 11130 (13%). What I mean by this is that one decade was missing (indicated by the “0”) and the other 4 decades had either 1 or 2 numbers in the first pattern, for example: 14-21-25-30-38-40, or 1 or 3 numbers in the second pattern, for example: 12-25-26-29-35-47.
So my problem is that I have 40 numbers which I want to use to produce combinations of the types described, that is containing one, two, or three numbers for the tens through fourties decades in two specific patterns.
Can anyone suggest how this could be done with an affordable number of combinations?
