Different Strategy

LottoGator

Member
A)
I've noticed that sometimes I'll pick numbers to play 6/49 and they end up getting played in Ontario 49 or Lottario.
What does anyone think of playing the same set of numbers in 6/49, Ontario 49, Lottario, even Super 7 (adding another number to make 7).
With the same set of numbers - you have 4 chances.

B)
Also have noticed that even though 50% of the drawn numbers of a 6/49 game are supposed to come from the last 5 draws. I've been noticing that it's more like 4, 5, and 6. I'm thinking of wheeling the numbers that have drawn in the past 6 (for good measure) draws....that would be col#2 on my page for Ontario 49 picks... don't know why I haven't done it before. Oh, and I also take into account the bonus... because I've found that some programs will say such-and-such a number hasn't drawn in 25 draws or something and it has in fact already drawn a couple of times as the bonus.

C)
I have also been thinking about combination play with Ontario 49.
This is what I was thinking... taking my Col#2 (numbers played once in the past 6 draws)... wheeling them into groups of 8 (20 numbers into groups of 8 using La Jolla's smallest wheels would be 9 tickets of 8 combination sheet @ $14 each is too expensive. So I would take each of the 8 combination sheets and play La Jolla's 8-number 6-number tickets wheeled into 3 tickets.... so that would be 9*3=27 tickets @ 50 cents = $13.50.....

Comments?

LottoGator
 

GillesD

Member
Numbers from last 5 or 6 draws

I was somewhat curious about your statement "50% of the drawn numbers of a 6/49 game are supposed to come from the last 5 draws", so I decided to check with results from Lotto 6/49.

After 2429 draws, this is what I got:
0 : 01.4% - 00.5%
1 : 09.5% - 02.4%
2 : 26.4% - 12.3%
3 : 31.8% - 26.2%
4 : 22.4% - 29.8%
5 : 07.3% - 20.9%
6 : 01.1% - 06.9%
7 : - - - - - 01.1%

The first column (0-7) gives the number of times a winning number has appeared in the last 5 draws, then the relative percentage of times, this has happened first without considering the bonus number, then including it in the calculations.

So you are right, it is more like 62.7% of the winning numbers that have appeared in the last 5 draws but only 30.9% with 4, 5 or 6 winning numbers.

For the fun of it, I repeated the exercise, but this time using the last 6 draws. Here are the results:

0 : 00.4% - 00.1%
1 : 06.1% - 01.1%
2 : 18.5% - 05.9%
3 : 31.4% - 20.3%
4 : 27.9% - 30.1%
5 : 13.2% - 27.3%
6 : 02.4% - 12.8%
7 : - - - - - 02.5%
 

LottoGator

Member
Wow..you're good!

Hi,

Thanks! it's great to see some math behind it (not my strength...maybe that's why I haven't won the JP yet ha).

So it would seem the best way to spend lotto money is taking 4 or 5 numbers from the last 6 draws... you know I think 30% is alot.

I was wondering...to narrow down the field a bit (field being the numbers to wheel)... is it a lot more work to calculate how many of those winning numbers were not just winning numbers that played in the previous 6 draws (including the bonus) but were numbers that had played only once in those 6 draws... I mean is it possible in your program/formula to eliminate those numbers of the previous 6 draws that had already played twice and the seventh draw was the third time the number played. (or is this over-doing it).

LottoGator
 

blitzed

Member
yup, GillesD is the Lottery Spreadsheet Jedi Master :agree:

anyway, probabilities might helpya boil down your number pool. ifya can nail down probabilities to the sample of numbers you are looking at, then you can shy away from the ones which would be drawn on the fringes of probability.

later,
blitzed
 

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