Bernoulli Table for Canadian649

Inspired by LottoArchitect work with Bernoulli tables

PROBABILITY OF A NUMBER TO APPEAR 01234567 TIMES IN THE LAST N DRAWS

1 85.71% 14.29% #NUM! #NUM! #NUM! #NUM! #NUM! #NUM!
2 73.47% 24.49% 2.04% #NUM! #NUM! #NUM! #NUM! #NUM!
3 62.97% 31.49% 5.25% 0.29% #NUM! #NUM! #NUM! #NUM!
4 53.98% 35.99% 9.00% 1.00% 0.04% #NUM! #NUM! #NUM!
5 46.27% 38.56% 12.85% 2.14% 0.18% 0.01% #NUM! #NUM!
6 39.66% 39.66% 16.52% 3.67% 0.46% 0.03% 0.00% #NUM!
7 33.99% 39.66% 19.83% 5.51% 0.92% 0.09% 0.01% 0.00%
8 29.14% 38.85% 22.66% 7.55% 1.57% 0.21% 0.02% 0.00%
9 24.97% 37.46% 24.97% 9.71% 2.43% 0.40% 0.04% 0.00%
10 21.41% 35.68% 26.76% 11.89% 3.47% 0.69% 0.10% 0.01%
11 18.35% 33.64% 28.03% 14.02% 4.67% 1.09% 0.18% 0.02%
12 15.73% 31.45% 28.83% 16.02% 6.01% 1.60% 0.31% 0.04%
13 13.48% 29.21% 29.21% 17.85% 7.44% 2.23% 0.50% 0.08%
14 11.55% 26.96% 29.21% 19.47% 8.92% 2.97% 0.74% 0.14%
15 9.90% 24.76% 28.89% 20.86% 10.43% 3.82% 1.06% 0.23%
16 8.49% 22.64% 28.30% 22.01% 11.92% 4.77% 1.46% 0.35%
17 7.28% 20.62% 27.49% 22.91% 13.36% 5.79% 1.93% 0.51%
18 6.24% 18.71% 26.51% 23.56% 14.73% 6.87% 2.48% 0.71%
19 5.35% 16.93% 25.39% 23.98% 15.99% 7.99% 3.11% 0.96%
20 4.58% 15.27% 24.18% 24.18% 17.13% 9.14% 3.81% 1.27%
21 3.93% 13.75% 22.91% 24.18% 18.14% 10.28% 4.57% 1.63%
22 3.37% 12.34% 21.60% 24.00% 19.00% 11.40% 5.38% 2.05%
23 2.89% 11.06% 20.28% 23.66% 19.72% 12.49% 6.24% 2.53%
24 2.47% 9.89% 18.96% 23.18% 20.28% 13.52% 7.14% 3.06%
25 2.12% 8.83% 17.67% 22.57% 20.69% 14.48% 8.05% 3.64%
26 1.82% 7.87% 16.40% 21.87% 20.96% 15.37% 8.97% 4.27%
27 1.56% 7.01% 15.19% 21.09% 21.09% 16.17% 9.88% 4.94%
28 1.34% 6.23% 14.02% 20.25% 21.09% 16.87% 10.78% 5.65%
29 1.14% 5.53% 12.91% 19.36% 20.97% 17.48% 11.65% 6.38%
30 0.98% 4.90% 11.85% 18.44% 20.74% 17.98% 12.48% 7.13%
31 0.84% 4.34% 10.86% 17.50% 20.41% 18.37% 13.27% 7.90%
32 0.72% 3.84% 9.93% 16.55% 19.99% 18.66% 14.00% 8.66%
33 0.62% 3.40% 9.06% 15.60% 19.50% 18.85% 14.66% 9.43%
34 0.53% 3.00% 8.25% 14.67% 18.95% 18.95% 15.26% 10.17%
35 0.45% 2.65% 7.50% 13.75% 18.33% 18.95% 15.79% 10.90%
36 0.39% 2.33% 6.81% 12.86% 17.68% 18.86% 16.24% 11.60%
37 0.33% 2.06% 6.17% 11.99% 16.99% 18.69% 16.61% 12.26%
38 0.29% 1.81% 5.58% 11.16% 16.28% 18.45% 16.91% 12.88%
39 0.24% 1.59% 5.04% 10.36% 15.55% 18.14% 17.13% 13.46%
40 0.21% 1.40% 4.55% 9.60% 14.81% 17.77% 17.27% 13.98%
41 0.18% 1.23% 4.10% 8.88% 14.06% 17.34% 17.34% 14.45%
42 0.15% 1.08% 3.69% 8.20% 13.32% 16.87% 17.34% 14.87%
43 0.13% 0.95% 3.32% 7.55% 12.59% 16.37% 17.28% 15.22%
44 0.11% 0.83% 2.98% 6.95% 11.87% 15.83% 17.15% 15.51%
45 0.10% 0.73% 2.67% 6.38% 11.17% 15.26% 16.96% 15.75%
46 0.08% 0.64% 2.39% 5.85% 10.48% 14.68% 16.72% 15.92%
47 0.07% 0.56% 2.14% 5.36% 9.82% 14.08% 16.42% 16.03%
48 0.06% 0.49% 1.92% 4.90% 9.18% 13.47% 16.09% 16.09%
49 0.05% 0.43% 1.71% 4.47% 8.57% 12.86% 15.72% 16.09%
50 0.04% 0.37% 1.53% 4.08% 7.99% 12.25% 15.31% 16.04%
51 0.04% 0.33% 1.36% 3.71% 7.43% 11.64% 14.87% 15.93%
52 0.03% 0.29% 1.22% 3.38% 6.90% 11.04% 14.41% 15.78%
53 0.03% 0.25% 1.08% 3.07% 6.39% 10.44% 13.93% 15.58%
54 0.02% 0.22% 0.96% 2.79% 5.92% 9.87% 13.43% 15.35%
55 0.02% 0.19% 0.86% 2.53% 5.47% 9.30% 12.92% 15.07%
56 0.02% 0.17% 0.76% 2.29% 5.05% 8.76% 12.40% 14.77%
57 0.02% 0.15% 0.68% 2.07% 4.66% 8.23% 11.88% 14.43%
58 0.01% 0.13% 0.60% 1.87% 4.29% 7.72% 11.36% 14.06%
59 0.01% 0.11% 0.53% 1.69% 3.94% 7.23% 10.84% 13.68%
60 0.01% 0.10% 0.47% 1.52% 3.62% 6.76% 10.32% 13.27%
61 0.01% 0.08% 0.42% 1.37% 3.32% 6.31% 9.81% 12.85%
62 0.01% 0.07% 0.37% 1.24% 3.04% 5.88% 9.31% 12.42%
63 0.01% 0.06% 0.33% 1.11% 2.78% 5.48% 8.82% 11.97%
64 0.01% 0.06% 0.29% 1.00% 2.55% 5.09% 8.34% 11.52%
65 0.00% 0.05% 0.26% 0.90% 2.33% 4.73% 7.88% 11.07%

EXAMPLE:

Which is the probability of a number to appear 5 times in the last 10 draws for the Canadian649?

R=0.69%

Then as a tactic we could safely remove numbers that have appeared 5 or more times in the last 10 draws because it has a very low possibility to appear in next draw (6 in 11=0.18%).


Which is the probability of a number to appear 0 times in the last 65 draws for the Canadian649?

R=0.00%

Then as a tactic if a number has a skip of 65 or more we could choose these number, because it has a chance to appear soon.
 

PAB

Member
Hi Grandmaster,

Very Interesting Table.
Are there Excel Formulas that are Able to Calculate the Table Above Please.

All the Best.
PAB
:wavey:
 

GillesD

Member
Use of Excel for Bernouilli or Binomial distribution

PAB

You can get all the values given by Grandmaster in his table using the binomial distribution functions in Excel. Although I question the value he selected as the probability of success.

The function to use is BINOMDIST(nSucc,nTrials,pSucc,Cumul) where the various parameters required by this function are:
- nSucc is the number of successes to be obtained in the trials to be made;
- nTrials is the number of independent trials to be made;
- pSucc is the probability of success in each trial;
- Cumul is a TRUE/FALSE value depending whether you want a cumulative probability (True) or simply the probability of nSucc in nTrials (False).

Using the example given by Grandmaster, the parameters will be:
- nSucc = 5 since we are looking for 5 successes (or a number coming out in a draw);
- nTrials = 10 since we want those 5 successes to happen in the next 10 trials (or draws);
- pSucc = 14.29% (or 7/49); here I disagree with Grandmaster as I would rather use 12.24% (or 6/49). Both values can be good depending on your need; with 14,29% a success is obtained if the number comes out in the 7 numbers (including the Bonus number) but the 12.24% value applies only if the number comes out in the 6 regular numbers.
- Cumul = FALSE as we want the the probability of nSucc in nTrials

The function BINOMDIST(5,10,0,1429,FALSE) gives 0.69% while the function BINOMDIST(5,10,0,1224,FALSE) gives 0.36%.

Also the function BINOMDIST(5,10,0,1429,TRUE) gives 99.90% or the sum of 21.41, 35.68, 26.76, 11.89, 3.47 and 0.69 (the individual values for 0, 1, 2, 3, 4 and 5 successes).
 
Hi,

Thank you GillesD for the explanation of the formula in excel, it is more easy than the formula I used :agree2:


PAB,

I used a variation of the same formula as GillesD, C(y,x) * p^x * (1-p)^(y-x) =


Excel type:

7/49

p=COMBIN(48,6)/COMBIN(49,7)=0.142857143

=((COMBIN(10,5)*(0.142857143^5)*(1-0.142857143)^(10-5))*(100))

=0.69%


6/49

p=COMBIN(48,5)/COMBIN(49,6)=0.122448980

=((COMBIN(10,5)*(0.12244898^5)*(1-0.12244898)^(10-5))*(100))

=0.36%


NOTE: The formula I used was obtained by an explanation of Lottoarchitect regarding Bernoulli table in LA forum.
 

PAB

Member
Hi GillesD,

I Posted the Following the Other Day, But for some Reason it did Not Appear.

Thank you for the Detailed Explanation, Excellent as Normal.
I have NOT Used the Function BINOMDIST(nSucc,nTrials,pSucc,Cumul) Before, it Seems Very Interesting. There are Probably Other Lotto Orientated Tasks that it could be Used for.
I Setup a Spreadsheet with the Total Numbers Drawn in Cell A1, the Total Numbers Drawn from in Cell A2, the "cumulative" in Cell A3, & the "probability_s" in Cell A4, it Works Great. I Changed the Total Drawn from 6 ( in Cell A1 ) to 7 and it Automatically Updated the Table.

Grandmaster,

Thanks for the Formulas and Explanation.

All the Best.
PAB
:wavey:
 

PAB

Member
Grandmaster & GillesD,

What would the Table be if we were to Set the Parameter Cumul to TRUE.
Also, what would the Formulas be Please.
Using the Example Previously ( with the Cumul Set to FALSE ) of the Probability of a Number Appearing 5 Times in the Last 10 Draws in a 649 Lotto :-

p=COMBIN(48,5)/COMBIN(49,6)=0.122448980

=((COMBIN(10,5)*(0.12244898^5)*(1-0.12244898)^(10-5))*(100))

=0.36%

Basically, what would these Formulas be if the Cumul was TRUE Please.

Thanks in Advance.
All the Best.
PAB
:wavey:
 
Hi PAB,

I will use the formulla of GillesD in excel for the Cumul set to TRUE:

=BINOMDIST(5,10,0.122448980,TRUE)
=1
=1*100=100%

(the individual values for 0, 1, 2, 3, 4 and 5 successes).

Regards
 
Last edited:
This was an edit to previous post:

Hi PAB,

I will use the formulla of GillesD in excel for the Cumul set to TRUE:

=BINOMDIST(5,10,0.1224,TRUE)
=.999545
=1*0.999545=99.95%

(the individual values for 0, 1, 2, 3, 4 and 5 successes).

5 0.003610258
4 0.021561265
3 0.088298513
2 0.237302252
1 0.377925808
0 0.270846828
TOTAL=0.999544924=99.95%


Regards
 

PAB

Member
Thanks for the Reply Grandmaster,

This is the Excel Formula that I am Using at Present for the Probability of a Number Appearing 5 Times in the Last 10 Draws in a 649 Lotto with the "cumulative" Set to "FALSE" :-

=(1-B47/B48)^(B60-H50)*(B47/B48)^H50*COMBIN(B60,H50)

This gives the Answer of 0.36%.

Cell "H50" is the Number of Times Appearing ( 5 Times ).
Cell "B60" is the Number of Draws ( 10 Draws ).
Cell "B47" is the Numbers Drawn ( 6 Numbers ).
Cell "B48" is the Numbers Drawn from ( 49 Numbers ).

What would the Above Formula look like with the Parameter Set to "TRUE".

I know it would be a LOT Easier if I was to Use the Formula …
=BINOMDIST(H50,B60,COMBIN(B48-1,B47-1)/COMBIN(B48,B47),TRUE)
… But I would Really like to know the Answer Using the NON BINOMDIST Function Way.

Thanks in Advance.
All the Best.
PAB
:wavey:
 
… But I would Really like to know the Answer Using the NON BINOMDIST Function Way.

Hi PAB,

Maybe GillesD or Lottoarchitect could answer the question..

If I found the answer I'll tell you..

Regards
 

PAB

Member
Thanks for the Reply Grandmaster,


Grandmaster said:
Maybe GillesD or Lottoarchitect could answer the question.
I will have Another look at it Tomorrow.

All the Best.
PAB
:wavey:
 

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