I'm posting the following pairs in this thread, so they can be verified after the draw.I believe with a great degree of certainty that one, possibly two pairs from the following group ,will be amongst those drawn tomorrow, and hey, if there is 3, thats even better.
draw1793, 28/29
draw1783, 18/40
draw1793, 32/35
draw1823, 1/35
draw1863, 8/42.21/45.42/45
draw1873,22/39.15/26
draw1883, 1/32.5/20.15/43.15/32.32/43
draw1893,3/14.23/43.
draw1903,11/39.35/44.35/39
draw1913, 9/34.4/9.34/43.8/9
draw1923,2/27.10/48.10/27.27/44.20/25
draw1933,9/42.9/27.9/25.25/42.27/42.33/42.
draw1943,2/39.2/10.8/39.10/39.10/30.14/31.8/14.8/10.
draw1953,3/26.3/23.12/26.12/23.26/47.12/21.21/34.23/26.21/23
draw1963,6/40.6/16.16/40.7/17.7/16.25/48.25/40.16/25.40/48.
16/17.
draw1973,10/44,10/40.11/40.11/34.10/26.11/26.5/11.26/44.
26/34.34/44.40/44.10/11.
draw1983,18/35.22/37.18/29.22/35.24/35.18/26.26/27.26/35.
22/29.29/37.29/35.22/26.26/29.24/26.35/37.
draw1993,1/30.1/28.1/24.1/19.1/18.5/28.1/5.18/28.19/28.
18/24.19/24.24/28.28/30.
Now at first it may look like a daunting task picking from 101 pairs, rather look at it as picking from 17 draws, not being a wheelmaster, if you applied some various filters of your own choosing and make the list smaller, and grouped these, ie. call them pair "A", pair "B" etc, or "GROUP" 1, "GROUP" 2 etc if the proper filter and proper wheel is applied, I think the winning pairs are amonst this group of 17. We'll see.