All training from 0000000 to 3333333.

jack

Member
All training from 0000000 to 3333333.
All training from 0000000 to 3333333
Ex = 0000001
****** 0000002
**...
* 3333333
Delete repeated formations
* Ex = 0000001, 0001000, 0000010 0100000 = Leave only one 0000001
* And so with the others
 

time*treat

Member
Not sure if OP is asking a question, making a statement, or simply fell asleep on keyboard, but my quick and dirty guess gives a list of 34 results:

10 of 0000000 ... 0000009
10 of 1111110 ... 1111119
10 of 2222220 ... 2222229

last 4, in full: 3333330, 3333331, 3333332, & 3333333
 

jack

Member
hello TIME,The expected list is 85 to 90
It is similar to the karnaugt table
Your account is missing
* 0011122
0111223
....
3333333
 

time*treat

Member
hello TIME,The expected list is 85 to 90
It is similar to the karnaugt table
Your account is missing
* 0011122
0111223
....
3333333

This is due to the original post being only a partial explanation.
However, the expected range provided just enough of a hint to determine the intended question.

The final list has 120 items.


#1: 0 0 0 0 0 0 0 __ #41: 0 0 1 1 1 3 3 __ #81: 0 2 2 2 3 3 3 __
#2: 0 0 0 0 0 0 1 __ #42: 0 0 1 1 2 2 2 __ #82: 0 2 2 3 3 3 3 __
#3: 0 0 0 0 0 0 2 __ #43: 0 0 1 1 2 2 3 __ #83: 0 2 3 3 3 3 3 __
#4: 0 0 0 0 0 0 3 __ #44: 0 0 1 1 2 3 3 __ #84: 0 3 3 3 3 3 3 __
#5: 0 0 0 0 0 1 1 __ #45: 0 0 1 1 3 3 3 __ #85: 1 1 1 1 1 1 1 __
#6: 0 0 0 0 0 1 2 __ #46: 0 0 1 2 2 2 2 __ #86: 1 1 1 1 1 1 2 __
#7: 0 0 0 0 0 1 3 __ #47: 0 0 1 2 2 2 3 __ #87: 1 1 1 1 1 1 3 __
#8: 0 0 0 0 0 2 2 __ #48: 0 0 1 2 2 3 3 __ #88: 1 1 1 1 1 2 2 __
#9: 0 0 0 0 0 2 3 __ #49: 0 0 1 2 3 3 3 __ #89: 1 1 1 1 1 2 3 __
#10: 0 0 0 0 0 3 3 __ #50: 0 0 1 3 3 3 3 __ #90: 1 1 1 1 1 3 3 __
#11: 0 0 0 0 1 1 1 __ #51: 0 0 2 2 2 2 2 __ #91: 1 1 1 1 2 2 2 __
#12: 0 0 0 0 1 1 2 __ #52: 0 0 2 2 2 2 3 __ #92: 1 1 1 1 2 2 3 __
#13: 0 0 0 0 1 1 3 __ #53: 0 0 2 2 2 3 3 __ #93: 1 1 1 1 2 3 3 __
#14: 0 0 0 0 1 2 2 __ #54: 0 0 2 2 3 3 3 __ #94: 1 1 1 1 3 3 3 __
#15: 0 0 0 0 1 2 3 __ #55: 0 0 2 3 3 3 3 __ #95: 1 1 1 2 2 2 2 __
#16: 0 0 0 0 1 3 3 __ #56: 0 0 3 3 3 3 3 __ #96: 1 1 1 2 2 2 3 __
#17: 0 0 0 0 2 2 2 __ #57: 0 1 1 1 1 1 1 __ #97: 1 1 1 2 2 3 3 __
#18: 0 0 0 0 2 2 3 __ #58: 0 1 1 1 1 1 2 __ #98: 1 1 1 2 3 3 3 __
#19: 0 0 0 0 2 3 3 __ #59: 0 1 1 1 1 1 3 __ #99: 1 1 1 3 3 3 3 __
#20: 0 0 0 0 3 3 3 __ #60: 0 1 1 1 1 2 2 __ #100: 1 1 2 2 2 2 2 __
#21: 0 0 0 1 1 1 1 __ #61: 0 1 1 1 1 2 3 __ #101: 1 1 2 2 2 2 3 __
#22: 0 0 0 1 1 1 2 __ #62: 0 1 1 1 1 3 3 __ #102: 1 1 2 2 2 3 3 __
#23: 0 0 0 1 1 1 3 __ #63: 0 1 1 1 2 2 2 __ #103: 1 1 2 2 3 3 3 __
#24: 0 0 0 1 1 2 2 __ #64: 0 1 1 1 2 2 3 __ #104: 1 1 2 3 3 3 3 __
#25: 0 0 0 1 1 2 3 __ #65: 0 1 1 1 2 3 3 __ #105: 1 1 3 3 3 3 3 __
#26: 0 0 0 1 1 3 3 __ #66: 0 1 1 1 3 3 3 __ #106: 1 2 2 2 2 2 2 __
#27: 0 0 0 1 2 2 2 __ #67: 0 1 1 2 2 2 2 __ #107: 1 2 2 2 2 2 3 __
#28: 0 0 0 1 2 2 3 __ #68: 0 1 1 2 2 2 3 __ #108: 1 2 2 2 2 3 3 __
#29: 0 0 0 1 2 3 3 __ #69: 0 1 1 2 2 3 3 __ #109: 1 2 2 2 3 3 3 __
#30: 0 0 0 1 3 3 3 __ #70: 0 1 1 2 3 3 3 __ #110: 1 2 2 3 3 3 3 __
#31: 0 0 0 2 2 2 2 __ #71: 0 1 1 3 3 3 3 __ #111: 1 2 3 3 3 3 3 __
#32: 0 0 0 2 2 2 3 __ #72: 0 1 2 2 2 2 2 __ #112: 1 3 3 3 3 3 3 __
#33: 0 0 0 2 2 3 3 __ #73: 0 1 2 2 2 2 3 __ #113: 2 2 2 2 2 2 2 __
#34: 0 0 0 2 3 3 3 __ #74: 0 1 2 2 2 3 3 __ #114: 2 2 2 2 2 2 3 __
#35: 0 0 0 3 3 3 3 __ #75: 0 1 2 2 3 3 3 __ #115: 2 2 2 2 2 3 3 __
#36: 0 0 1 1 1 1 1 __ #76: 0 1 2 3 3 3 3 __ #116: 2 2 2 2 3 3 3 __
#37: 0 0 1 1 1 1 2 __ #77: 0 1 3 3 3 3 3 __ #117: 2 2 2 3 3 3 3 __
#38: 0 0 1 1 1 1 3 __ #78: 0 2 2 2 2 2 2 __ #118: 2 2 3 3 3 3 3 __
#39: 0 0 1 1 1 2 2 __ #79: 0 2 2 2 2 2 3 __ #119: 2 3 3 3 3 3 3 __
#40: 0 0 1 1 1 2 3 __ #80: 0 2 2 2 2 3 3 __ #120: 3 3 3 3 3 3 3 __

 

jack

Member
Hello, huu!TIME Perfect, very good job, is the perfect matrix
* For initial lottery numbers 01 to 31 at 100%
Ex = 02 05 15 16 23 24 26 = initial digits = 0011222
Good as the lottery goes until 31
We have only two initial digits that are 30 and 31
Then = 0000333 has to be filtered at most two digits 3.3 (30.31)
By ascending order this matrix was perfect, congratulations, thank you
Ok last digits is another hard part, but we can use these formations as fixed
Analyzing the ones that are most drawn
 

Sidebar

Top