A few questions for the mathematically inclined re the 6/49

F

Fortune

Member
If there are 13,983,816 unique combinations of 6 numbers out of 49,

1) From inception in June 1982 (for the Canadian 6/49), approximately how many years will it take for ALL the combinations to occur?(without repetition).

2) Is this database accessible via cds, downloads, etc?

3) How many times will each of the 49 numbers appear in distinct sets of six numbers excluding bonus numbers for the universal set of 13,983,816 combinations to be complete?
Thanks
 
G

GillesD

Member
Mathematical facts on a 6/49 lottery

1) From inception in June 1982 (for the Canadian 6/49), approximately how many years will it take for ALL the combinations to occur?(without repetition).

The only thing for sure it will take a minimum of 13,983,817 draws if there are no repeat combinations. But a repeat combination could appear as soon as tonight or not for a few years. But already the same combination has come out in both Lotto 6/49 and Quebec 49).

2) Is this database accessible via cds, downloads, etc?

Yes, many sites have such a database. I would recommend the British Columbia Lottery Commission (www.bclc.com) where you can obtain the full history of Lotto 6/49 in a CSV file that can be read by Excel.

3) How many times will each of the 49 numbers appear in distinct sets of six numbers excluding bonus numbers for the universal set of 13,983,816 combinations to be complete?

I am not sure to understand the question well but in all the possible combinations, each number (1 to 49) appear 1,712,304 times.
 
Koon84

Koon84

Member
Dear GillesD,

Hello, I'm from M'sia and introduce you an new member forum.

I have ready collection several history rows in my Excel. But I have know a little in mathematic about DELTA convert to TOTO 6/49 and 6/52. Do you know about DELTA numbers? Are you skill in mathematic lotto?

Pls reply me if I want know it.


Regards, Koon.
 
johnph77

johnph77

Member
Dealing with probability, though, the chances are that, somewhere around 35% to 40% of the available draws, a duplicate set of 6 numbers will have already repeated itself or will soon be drawn.

But, in the highly unlikely probability that through 13,983,815 draws no set of six numbers has repeated itself, the odds that the last set of six numbers will be drawn will still be 1::13,983,816.
 
H

hopefull

Member
it will take all combinations 33,614.9 years before repeating if none repeated before all combinations gets drawn.
2 draws per week 8 draws per month 416 per year.
13,983,815 / 416 = 33,614.9 plus round up to 33,615.
but we have had a few 5 numbers repeat and I have not seen a 6 just yet.
 
You must log in or register to reply here.

Sidebar

Top