magusprovernum
Member
Hello everyone,
This will be my first post on the forum. As far as I can tell from looking around on the net nobody has tried this.
What I did was split each draw up into two sets of numbers; tens and ones.
eg, 01 23 26 28 33 40 (The last 649 draw numbers)
becomes, 0 2 2 2 3 4 (tens, or "decades")
and, 1 3 6 8 3 0 (ones)
I then looked to see how often numbers repeated in each set. I found that in the decades group the pattern A A B B C D accounts for 5,400 of the total 15,625 possible combinations or 34.6% So should be drawn once in roughly three draws.
In the ones group the pattern A A B C D E accounts for 453,600 combinations of the total 1,000,000 or 45.4% and should be drawn roughly once in every two draws.
Both patterns should be drawn togeather about once in every six draws. With the total number of sets with both patterns being 2,196,634. Did I calculate this correctly? My math skills are not that great so if I made a mistake please let me know.
My theory has been plauged by human error since day 1. Because of my poor math skills and dissorganized way of keeping notes I mistakingly played the wrong pattern in the decades group last saturday on the Ontario49 (which I use to test my theories because it's cheaper to play). Instead of A A B B C D, I played A A A B B C. Luckily that pattern happened to hit along with the pattern for the ones. I played random numbers in the patterns and filtered them by sums so I ended up with 16 sets. I ended up with 29 unique numbers in all the sets I played. I scored 4/6 numbers in the draw. Unfortunately because I made an error in the program I wrote (it never picked 0,) to pick the numbers plus I chose the wrong sum, I only got a maximum of two draw numbers in any set.
I really believe I've hit on something unique and believe that with a little fine tuning my system could be the key to winning. I was going to keep this to myself.. but because I obviously need help with this I decided to post it here.
All feedback and suggestions welcome.
This will be my first post on the forum. As far as I can tell from looking around on the net nobody has tried this.
What I did was split each draw up into two sets of numbers; tens and ones.
eg, 01 23 26 28 33 40 (The last 649 draw numbers)
becomes, 0 2 2 2 3 4 (tens, or "decades")
and, 1 3 6 8 3 0 (ones)
I then looked to see how often numbers repeated in each set. I found that in the decades group the pattern A A B B C D accounts for 5,400 of the total 15,625 possible combinations or 34.6% So should be drawn once in roughly three draws.
In the ones group the pattern A A B C D E accounts for 453,600 combinations of the total 1,000,000 or 45.4% and should be drawn roughly once in every two draws.
Both patterns should be drawn togeather about once in every six draws. With the total number of sets with both patterns being 2,196,634. Did I calculate this correctly? My math skills are not that great so if I made a mistake please let me know.
My theory has been plauged by human error since day 1. Because of my poor math skills and dissorganized way of keeping notes I mistakingly played the wrong pattern in the decades group last saturday on the Ontario49 (which I use to test my theories because it's cheaper to play). Instead of A A B B C D, I played A A A B B C. Luckily that pattern happened to hit along with the pattern for the ones. I played random numbers in the patterns and filtered them by sums so I ended up with 16 sets. I ended up with 29 unique numbers in all the sets I played. I scored 4/6 numbers in the draw. Unfortunately because I made an error in the program I wrote (it never picked 0,) to pick the numbers plus I chose the wrong sum, I only got a maximum of two draw numbers in any set.
I really believe I've hit on something unique and believe that with a little fine tuning my system could be the key to winning. I was going to keep this to myself.. but because I obviously need help with this I decided to post it here.
All feedback and suggestions welcome.