Hello frank here another example, now 49/6, pick trios and pairs and numbers
* Of previous draws,
* Example = if the trio is the position of 1st 4th 5th the pair has to be position
2nd and 3rd or 6th
So the choice of triplets and pairs of previous drawings may not be the same
* Positions vertically =
Numbers from the previous draw Appear frequently in the next draw. Usually one, sometimes two, and once in a few months, 3.
You need 15 tickets to make sure you cover any combination of 2 of the 6 numbers drawn illustrated previously.
Let's say the 6 numbers are 1, 2, 3, 4, 5 and 6.
So it'll be like.
1 2 A B C D
1 3 A B C D
1 4 A B C D
1 5 A B C D
1 6 A B C D
2 3 A B C D
2 4 A B C D
2 5 A B C D
2 6 A B C D
3 4 A B C D
3 5 A B C D
3 6 A B C D
4 5 A B C D
4 6 A B C D
5 6 A B C D
So, in Lotto 649, you have about 1 in 14 million chance to win. Yes?
I'll be taking the numbers from wikipedia on Lotto 649.
So referencing from there, to get 4/6 right, it's about 1 in 1000.
Let's say every week I buy the 15 tickets, hoping 2 of the previous numbers appear. On the week que 2 of Them Appear does, have my chances gone from 1 in 14 million to just 1 in 1000?